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An \(85-\mathrm{kg}\) jogger is heading due east at a speed of \(2.0 \mathrm{~m} / \mathrm{s}\). A \(55-\mathrm{kg}\) jogger is heading \(32^{\circ}\) north of east at a speed of \(3.0 \mathrm{~m} / \mathrm{s}\). Find the magnitude and direction of the sum of the momenta of the two joggers.

Short Answer

Expert verified
The total momentum is approximately 321.8 kg·m/s at 15.75° north of east.

Step by step solution

01

- Define Momentum

The momentum of an object is defined as the product of its mass and velocity. Therefore, the momentum of a jogger can be calculated by multiplying their mass by their velocity.
02

- Calculate Momentum of Jogger 1

Jogger 1 has a mass of 85 kg and is moving east at 2.0 m/s. Thus, his momentum is calculated as: \[ \mathbf{p_1} = 85 \, \text{kg} \times 2.0 \, \text{m/s} = 170 \, \text{kg} \cdot \text{m/s} \] In vector form, this is: \[ \mathbf{p_1} = (170 \, \text{kg} \cdot \text{m/s}, 0) \]
03

- Calculate Momentum of Jogger 2: Components

Jogger 2 has a mass of 55 kg and is moving at an angle of \(32^\circ\) north of east at 3.0 m/s. We need to calculate the components of the velocity first. Eastward component: \[ v_{2x} = 3.0 \, \text{m/s} \times \cos(32^\circ) \approx 2.54 \, \text{m/s} \] Northward component: \[ v_{2y} = 3.0 \, \text{m/s} \times \sin(32^\circ) \approx 1.59 \, \text{m/s} \] Then we find the components of momentum: Eastward momentum: \[ p_{2x} = 55 \, \text{kg} \times 2.54 \, \text{m/s} \approx 139.7 \, \text{kg} \cdot \text{m/s} \] Northward momentum: \[ p_{2y} = 55 \, \text{kg} \times 1.59 \, \text{m/s} \approx 87.45 \, \text{kg} \cdot \text{m/s} \] In vector form, this is: \[ \mathbf{p_2} = (139.7 \, \text{kg} \cdot \text{m/s}, 87.45 \, \text{kg} \cdot \text{m/s}) \]
04

- Sum of Momentums

Now add the momentum vectors of both joggers to find the total momentum: \[ \mathbf{p}_{\text{total}} = \mathbf{p_1} + \mathbf{p_2} = (170 \, \text{kg} \cdot \text{m/s} + 139.7 \, \text{kg} \cdot \text{m/s}, 0 + 87.45 \, \text{kg} \cdot \text{m/s}) \] Thus, \[ \mathbf{p}_{\text{total}} = (309.7 \, \text{kg} \cdot \text{m/s}, 87.45 \, \text{kg} \cdot \text{m/s}) \]
05

- Calculate Magnitude of Total Momentum

Calculate the magnitude of the total momentum vector using the Pythagorean theorem: \[ |\mathbf{p}_{\text{total}}| = \sqrt{(309.7)^2 + (87.45)^2} \approx \sqrt{95917.49 + 7645.60} \approx \sqrt{103563.09} \approx 321.8 \, \text{kg} \cdot \text{m/s} \]
06

- Determine Direction of Total Momentum

Use the inverse tangent function to determine the direction of the total momentum vector: \[ \theta = \tan^{-1}\left(\frac{87.45}{309.7}\right) \approx \tan^{-1}(0.2823) \approx 15.75^\circ \] Therefore, the direction is \(15.75^\circ\) north of east.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
In physics, particularly when dealing with forces or momentum, vector addition is a crucial concept. Vectors are quantities that have both magnitude and direction, and they can be added together to find a resultant vector. This process involves aligning all vectors such that they form a continuous path that leads to the resultant vector.
For our exercise, we're dealing with two vectors representing the momenta of two joggers. The momentum vectors of these joggers are added together to find the total momentum. The resultant vector provides us with both the magnitude and direction of the combined effect of these momenta.
Vector addition is generally carried out by breaking each vector into its components along the coordinate axes, and then summing those components. It's comparable to putting one arrow (vector) tip to another's tail and drawing the resultant arrow from the start of the first to the tip of the second.
Velocity Components
When dealing with vectors inclined to standard axes, it's often useful to break them into components. Velocity components represent this method well.
For instance, Jogger 2's velocity is not aligned with the standard east-west North-South axis, moving at an angle. To handle this, we decompose Jogger 2's velocity into horizontal (eastward) and vertical (northward) components using trigonometric functions: cosine for the horizontal and sine for the vertical.
  • The eastward component, using cosine, finds how much of the total velocity pushes east.
  • The northward component, using sine, finds how much of the total velocity goes north.
The same principles apply to any vector, making this a versatile tool in physics, allowing us to handle complex vector problems by working on simpler linear components.
Pythagorean Theorem
The Pythagorean theorem is a cornerstone of mathematics, particularly useful in physics for calculating the magnitude of a resultant vector when its components are known. This theorem states that the square of the hypotenuse (the longest side of a right triangle) is equal to the sum of the squares of the other two sides.
In the context of our exercise, once we have the total momentum components (east and north), we use the Pythagorean theorem to compute the magnitude of the total momentum vector. This involves creating a right triangle, where the length of each side is the magnitude of each component, and using the formula:
\[ |\mathbf{p}_{\text{ total}}| = \sqrt{(p_{ \text{ east}})^2 + (p_{ \text{ north}})^2} \]
This gives us the overall momentum magnitude, encompassing the effects of both joggers. It's a straightforward but powerful technique to move from visualizing separate impacts to identifying combined momentum.
Inverse Tangent Function
The inverse tangent function, commonly written as \( \tan^{-1} \) or \( \text{atan} \), is an essential mathematical tool used to determine the angle of a resultant vector when horizontal and vertical components are known. This function essentially reverses the tangent in trigonometry, which relates to the ratios of opposite and adjacent sides of a right triangle.
In our problem, after calculating total momentum components east and north, we use the inverse tangent function to find the angle of the resulting momentum vector. The formula is:\[\theta = \tan^{-1}\left(\frac{\text{North component}}{\text{East component}}\right)\]This tells us the direction the combined momentum takes relative to the horizontal axis (eastward direction).
Understanding this function is crucial for translating numerical data into insightful directional information, practically allowing vector directions to be meaningful beyond mere numbers.

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Most popular questions from this chapter

A wagon is coasting at a speed \(v_{\mathrm{A}}\) along a straight and level road. When ten percent of the wagon's mass is thrown off the wagon, parallel to the ground and in the forward direction, the wagon is brought to a halt. If the direction in which this mass is thrown is exactly reversed, but the speed of this mass relative to the wagon remains the same, the wagon accelerates to a new speed \(v_{\mathrm{B}}\). Calculate the ratio \(v_{\mathrm{B}} / v_{\mathrm{A}}\).

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