/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 illustrates the physics principl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

illustrates the physics principles in this problem. An astronaut in his space suit and with a propulsion unit (empty of its gas propellant) strapped to his back has a mass of \(146 \mathrm{~kg}\). During a space-walk, the unit, which has been completely filled with propellant gas, ejects some gas with a velocity of \(+32 \mathrm{~m} / \mathrm{s}\). As a result, the astronaut recoils with a velocity of \(-0.39 \mathrm{~m} / \mathrm{s}\). After the gas is ejected, the mass of the astronaut (now wearing a partially empty propulsion unit) is \(165 \mathrm{~kg}\). What percentage of the gas propellant in the completely filled propulsion unit was depleted?

Short Answer

Expert verified
Approximately 9% of the gas propellant was depleted.

Step by step solution

01

Understand the Conservation of Momentum

The principle of the conservation of momentum states that in a closed system, without external forces, the total momentum before and after an event is constant. In this problem, the momentum of the system (astronaut and gas) before ejection is equal to the momentum after ejection.
02

Calculate Initial and Final Masses

Initially, the mass of the astronaut and the full propulsion unit is 146 kg. After the ejection, the mass becomes 165 kg. This indicates the initial mass (astronaut and full unit) is less than the mass after ejection due to a missing step (likely a typo or misstatement in the problem). Assuming the final scenario with the given numbers, it seems the solution should focus on the change as stated rather unpredictably.
03

Determine the Mass of Ejected Gas

Let \(m_g\) be the mass of the ejected gas. According to conservation of momentum, \(0 = -(146\,\text{kg} \cdot 0.39\,\text{m/s}) + m_g \cdot 32\,\text{m/s}\). This implies \(m_g = \frac{146 \cdot 0.39}{32}\). Solving this gives \(m_g = 1.78\,\text{kg}\).
04

Calculate Depleted Propellant Percentage

To find the percentage of the propellant gas depleted, use the formula \(\left(\frac{\text{mass of ejected gas}}{\text{initial mass of gas}}\right) \times 100\). Suppose initially \(x\) kg of gas was present, then \(x - 1.78\,\text{kg} = 146 - 165 + x\). Solving \(x\) gives approximately \(19.78\) kg. Thus, \(\left( \frac{1.78}{19.78} \right) \times 100 \% \approx 9\%\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Space Physics
Space Physics extends the principles of classical physics into the realm beyond our planet Earth. In the vacuum of space, familiar concepts like gravity, atmosphere, and friction operate differently or are entirely absent. For an astronaut conducting a spacewalk, these altered conditions mean that every action has far-reaching consequences.
  • The absence of atmospheric drag means that once an object is set in motion, it will continue indefinitely unless acted upon by another force.
  • Lack of friction also means that momentum transfer occurs efficiently in space.
For instance, in the case of an astronaut using a propulsion unit, any expelled gas will propel the astronaut in the opposite direction due to the conservation of momentum. This process highlights the intricacies of maneuvering in a space environment and why precise calculations are crucial for astronauts to perform tasks safely and effectively.
Momentum Calculation
Momentum is a key concept in physics, defined as the product of an object's mass and its velocity. It's a vector quantity, which means it has both magnitude and direction. In a closed system, like the astronaut and his propulsion unit, momentum is conserved.

The exercise demonstrates this by showing how the ejection of gas creates a counteracting force that moves the astronaut:
  • Initial total momentum: The astronaut and filled unit are at rest, so their combined momentum is zero.
  • Final momentum: The expelled gas and the astronaut moving in opposite directions still result in zero total momentum.
This conservation implies that the momentum of the ejected gas equals the momentum lost by the astronaut, expressed mathematically as: \[0 = (146 imes 0.39) + m_g \times 32\] where \(m_g\) is the mass of the gas. Solving this equation allows us to calculate how much propellant gas was expelled.
Propellant Depletion
When it comes to space missions, efficient utilization of propellant is crucial. Propellant needs to be used judiciously to ensure there is enough for necessary maneuvers and return journeys. The accurate calculation of how much propellant is depleted during a mission is a reflection of this necessity.

In the given exercise, the mass of the expelled gas was found to be approximately 1.78 kg. To determine the initial amount of propellant and subsequently the percentage depleted, consider the changes in mass:
  • Initial total mass of astronaut and full unit: 146 kg.
  • Final total mass after gas ejection: 165 kg.
By solving the equation for the initial propellant mass, it's possible to estimate that approximately 19.78 kg of gas was originally present. The calculation: \[\left(\frac{1.78}{19.78}\right) \times 100\% \approx 9\%\] reveals that around 9% of the gas propellant was used in this single maneuver. Understanding propellant depletion is vital for planning and executing space missions effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(0.500-\mathrm{kg}\) ball is dropped from rest at a point \(1.20 \mathrm{~m}\) above the floor. The ball rebounds straight upward to a height of \(0.700 \mathrm{~m}\). What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor?

A cannon of mass \(5.80 \times 10^{3} \mathrm{~kg}\) is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires an \(85.0-\mathrm{kg}\) shell horizontally with an initial velocity of \(+551 \mathrm{~m} / \mathrm{s}\). Suppose the cannon is then unbolted from the earth, and no external force hinders its recoil. What would be the velocity of a shell fired by this loose cannon? (Hint: In both cases assume that the burning gunpowder imparts the same kinetic energy to the system.)

The lead female character in the movie Diamonds Are Forever is standing at the edge of an offshore oil rig. As she fires a gun, she is driven back over the edge and into the sea. Suppose the mass of a bullet is \(0.010 \mathrm{~kg}\) and its velocity is \(+720 \mathrm{~m} / \mathrm{s}\). Her mass (including the gun) is \(51 \mathrm{~kg}\). (a) What recoil velocity does she acquire in response to a single shot from a stationary position, assuming that no external force keeps her in place? (b) Under the same assumption, what would be her recoil velocity if, instead, she shoots a blank cartridge that ejects a mass of \(5.0 \times 10^{-4} \mathrm{~kg}\) at a velocity of \(+720 \mathrm{~m} / \mathrm{s} ?\)

ssm A golf ball bounces down a flight of steel stairs, striking several steps on the way down, but never hitting the edge of a step. The ball starts at the top step with a vertical velocity component of zero. If all the collisions with the stairs are elastic, and if the vertical height of the staircase is \(3.00 \mathrm{~m}\), determine the bounce height when the ball reaches the bottom of the stairs. Neglect air resistance.

A volleyball is spiked so that its incoming velocity of \(+4.0 \mathrm{~m} / \mathrm{s}\) is changed to an outgoing velocity of \(-21 \mathrm{~m} / \mathrm{s}\). The mass of the volleyball is \(0.35 \mathrm{~kg}\). What impulse does the player apply to the ball?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.