/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 The drawing shows two boxes rest... [FREE SOLUTION] | 91Ó°ÊÓ

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The drawing shows two boxes resting on frictionless ramps. One box is relatively light and sits on a steep ramp. The other box is heavier and rests on a ramp that is less steep. The boxes are released from rest at \(\mathrm{A}\) and allowed to slide down the ramps. Which box, if either, has (a) the greater speed and (b) the greater kinetic energy at B? Provide a reason for each answer. The two boxes have masses of 11 and \(44 \mathrm{~kg}\). If \(\mathrm{A}\) and \(\mathrm{B}\) are 4.5 and \(1.5 \mathrm{~m},\) respectively, above the ground, determine the speed of (a) the lighter box and (b) the heavier box when each reaches \(\mathrm{B}\). (c) What is the ratio of the kinetic energy of the heavier box to that of the lighter box at B? Be sure that your answers are consistent with your answers to the Concept Questions.

Short Answer

Expert verified
Both boxes have the same speed of 7.67 m/s at B; the heavier box has greater KE with a ratio of 4:1.

Step by step solution

01

Determine Initial and Final Height

The initial height of both boxes is given as 4.5 m. The final height for both boxes when they reach point B is 1.5 m. Because both fall the same height difference (4.5 m - 1.5 m = 3.0 m), the potential energy change will be driven by this height difference.
02

Calculate Speed Using Energy Conservation

We will use conservation of energy to find the speed at point B. The formula for gravitational potential energy (PE) is: \[ PE = mgh \]and the kinetic energy (KE) at B is given by:\[ KE = \frac{1}{2} mv^2 \].Using conservation of energy, potential energy decrease equals kinetic energy gained:\[ mgh_i = \frac{1}{2} mv^2 + mgh_f \]Simplifying gives:\[ mg(h_i - h_f) = \frac{1}{2} mv^2 \]\[ v = \sqrt{2g(h_i - h_f)} \]This shows that the speed is independent of mass.
03

Calculate Speed for Each Box

Since both boxes drop by the same height (3.0 m), their speeds will be the same. Using the freefall speed formula:\[ v = \sqrt{2 \times 9.8 \times 3.0} \approx \sqrt{58.8} \approx 7.67 \ \text{m/s} \]Thus, both boxes will have a speed of 7.67 m/s when they reach point B.
04

Calculate Kinetic Energy for Each Box

The kinetic energy of each box at B is calculated using:\[ KE = \frac{1}{2} mv^2 \].For the lighter box (11 kg):\[ KE_{light} = \frac{1}{2} \times 11 \times (7.67)^2 \approx 322.93 \ \text{J} \].For the heavier box (44 kg):\[ KE_{heavy} = \frac{1}{2} \times 44 \times (7.67)^2 \approx 1291.72 \ \text{J} \].
05

Calculate Ratio of Kinetic Energies

The ratio of the kinetic energy of the heavier box to that of the lighter box is:\[ \text{Ratio} = \frac{KE_{heavy}}{KE_{light}} = \frac{1291.72}{322.93} \approx 4 \].This shows that the heavier box has four times the kinetic energy of the lighter box.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

kinetic energy
Kinetic energy is the energy an object possesses due to its motion. Whether it is a box sliding down a ramp or a car speeding down the highway, any object in motion has kinetic energy. This energy can be calculated with the formula
  • \( KE = \frac{1}{2} mv^2 \)
where \( m \) is mass and \( v \) is velocity.

It's important to understand that kinetic energy is directly related to both mass and speed. If either the mass or the velocity of an object is doubled, the kinetic energy will increase significantly. In our exercise with two boxes, even though both reach the same velocity going down the ramp, the heavier box ends up with more kinetic energy simply because it has more mass. This is a common occurrence in physics: more massive objects will have more kinetic energy if they have the same speed as lighter ones.

Knowing this, when you're considering the kinetic energy of objects, always think about both their speed and their mass.
potential energy
Potential energy is the energy stored in an object due to its position relative to other objects. In our scenario, the potential energy comes from an object's height above the ground, given by the formula:
  • \( PE = mgh \)
where \( m \) is mass, \( g \) is gravitational acceleration (\( 9.8 \, \text{m/s}^2 \) on Earth), and \( h \) is height.

The key point here is that potential energy is all about position. When the two boxes are at the top of their ramps, they start with maximum potential energy. As they slide down the ramps, this stored energy is converted to kinetic energy, driving the increase in speed.

It is essential to understand that the initial potential energy depends on how high the objects are above some reference point. In this case, both boxes drop the same vertical distance (3 meters). Therefore, they lose the same amount of potential energy, which is entirely transformed into kinetic energy because there is no friction on the ramps. So, although the ramps and boxes are different, the change in vertical height is the common factor that determines the change in potential energy.
gravitational force
Gravitational force is the attractive force that the Earth exerts on objects. It's what gives objects weight and causes them to fall when dropped. This force is key to understanding how potential energy is converted to kinetic energy as an object moves under the influence of gravity.

The gravitational force acting on an object is calculated by the product
  • \( F = mg \)
where \( F \) is the gravitational force, \( m \) is the object's mass, and \( g \) is the acceleration due to gravity.

It's straightforward but critically important in physics problems involving motion. The gravitational force causes objects to accelerate downward at \( 9.8 \, \text{m/s}^2 \). In our exercise, as the boxes slide down the ramps, this force is what pulls them, converting potential energy (due to their elevated positions) into kinetic energy (due to their motion).

Understanding gravitational force helps you predict how objects will move when released from rest, and explains why objects accelerate the way they do in free fall or slide scenarios. It's a fundamental concept that not only applies to school exercises but also to real-world situations.

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Most popular questions from this chapter

A \(2.00\) -kg rock is released from rest at a height of \(20.0 \mathrm{~m}\). Ignore air resistance and determine the kinetic energy, gravitational potential energy, and total mechanical energy at each of the following heights: \(20.0,10.0\), and \(0 \mathrm{~m}\).

A 1900 -kg car experiences a combined force of air resistance and friction that has the same magnitude whether the car goes up or down a hill at \(27 \mathrm{~m} / \mathrm{s}\). Going up a hill, the car's engine needs to produce 47 hp more power to sustain the constant velocity than it does going down the same hill. At what angle is the hill inclined above the horizontal?

When a \(0.045-\mathrm{kg}\) golf ball takes off after being hit, its speed is \(41 \mathrm{~m} / \mathrm{s}\). (a) How much work is done on the ball by the club? (b) Assume that the force of the golf club acts parallel to the motion of the ball and that the club is in contact with the ball for a distance of \(0.010 \mathrm{~m}\). Ignore the weight of the ball and determine the average force applied to the ball by the club.

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. (a) Is the direction of the force the same as or opposite to the direction of the displacement of the asteroid? Why? (b) Does the force do positive, negative, or zero work? Justify your answer. (c) What type of energy is changing as the object slows down? (d) What is the relationship between the work done by this force and the change in the object's energy? The asteroid has a mass of \(4.5 \times 10^{4} \mathrm{~kg}\), and the force causes its speed to change from 7100 to \(5500 \mathrm{~m} / \mathrm{s}\). (a) What is the work done by the force? (b) If the asteroid slows down over a distance of \(1.8 \times 10^{6} \mathrm{~m}\), determine the magnitude of the force. Verify that your answers are consistent with the answers to the Concept Questions.

A sled is being pulled across a horizontal patch of snow. Friction is negligible. The pulling force points in the same direction as the sled's displacement, which is along the \(+x\) axis. As a result, the kinetic energy of the sled increases by \(38 \% .\) By what percentage would the sled's kinetic energy have increased if this force had pointed \(62^{\circ}\) above the \(+x\) axis?

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