/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 A 67.0 -kg person jumps from res... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 67.0 -kg person jumps from rest off a 3.00 -m-high tower straight down into the water. Neglect air resistance during the descent. She comes to rest \(1.10 \mathrm{~m}\) under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Short Answer

Expert verified
The average force exerted by the water is 1792.17 N.

Step by step solution

01

Calculate Initial Potential Energy

The initial potential energy of the diver is determined by the formula \( PE = mgh \), where \( m \) is the mass (67.0 kg), \( g \) is the acceleration due to gravity (9.81 m/s²), and \( h \) is the height of the tower (3.00 m). Thus, \( PE = 67.0 \times 9.81 \times 3.00 = 1971.39 \text{ J} \).
02

Convert Potential Energy to Kinetic Energy

As the diver jumps off the tower, all of her potential energy is converted to kinetic energy just before she hits the water because air resistance is neglected. This means that the kinetic energy just before hitting the water is also 1971.39 J.
03

Calculate the Work Done by the Water

Once the diver enters the water, she comes to a stop 1.10 m under the surface. The work done by the water to stop her is equal to the change in kinetic energy, which is equal to the kinetic energy just before entering the water because she comes to rest. So, the work done by the water is \( -1971.39 \text{ J} \). The negative sign indicates that the water exerts a force in the opposite direction to the motion of the diver.
04

Relate Work Done to Force

The work done by the water is also given by the equation \( W = F \times d \), where \( W \) is the work done (-1971.39 J), \( F \) is the average force, and \( d \) is the distance (1.10 m). Rearranging for \( F \), we get \( F = \frac{-1971.39}{1.10} \approx -1792.17 \text{ N} \).
05

Determine the Magnitude of the Average Force

The magnitude of the average force is the absolute value of the calculated force, so the magnitude is \( 1792.17 \text{ N} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy of motion. It describes how much work an object can do based on its speed and mass. When the diver is about to hit the water, all of her initial potential energy, obtained from the height of the tower, is transformed into kinetic energy. The mathematical expression for kinetic energy is:\[ KE = \frac{1}{2}mv^2 \]where \( m \) represents mass and \( v \) is the velocity. In this exercise, it's essential to understand that just before the diver enters the water, her kinetic energy equals her initial potential energy—1971.39 J. Hence, no energy loss occurs, as air resistance is ignored. This energy conversion is critical for determining the work done by the water later on.
Potential Energy
Potential energy is the stored energy of position possessed by an object. The diver's potential energy is based on her height above the water. We calculate it using:\[ PE = mgh \]where:
  • \( m \) is the mass of the diver, 67.0 kg,
  • \( g \) is the acceleration due to gravity, approximately \( 9.81 \text{ m/s}^2 \),
  • \( h \) is the height of the jump, 3.00 m.
Given these values, the initial potential energy is 1971.39 J. As the diver falls, this energy is transformed seamlessly into kinetic energy. This exchange is what allows the diver to gain speed as she descends.
Work Done by Force
The work done by a force describes how much energy is transferred by the force acting over a distance. Here, when the diver hits the water surface, she begins to decelerate due to the force exerted by the water. The work done by the water, which brings her to a complete stop 1.10 m underwater, can be calculated as:\[ W = F \cdot d \]where:
  • \( W \) is the work done by the water (-1971.39 J),
  • \( F \) is the average force exerted by the water,
  • \( d \) is the distance over which this force acts, 1.10 m.
The negative sign for work implies that the force exerted by the water opposes the motion, reducing the diver's kinetic energy.
Conservation of Energy
The principle of conservation of energy states that energy in a closed system cannot be created or destroyed, only transformed from one form to another. In this scenario, the diver transitions from potential energy to kinetic energy smoothly without any energy loss to air resistance. When she enters the water, her kinetic energy is then spent entirely in doing work against the resisting force of the water. This transformation and balance of energy exemplify the conservation principle, as the total energy remains constant throughout her fall and submersion.
Force Calculation
Calculating the force required to stop the diver involves understanding the relationship between work and force. From the work-energy principle, the force exerted by the water can be calculated by rearranging the work formula:\[ F = \frac{W}{d} \]Inserting the known values:
  • Work \( W = -1971.39 \text{ J} \) (negative because the force direction is opposite),
  • Distance \( d = 1.10 \text{ m} \),
we find the average force \( F \approx -1792.17 \text{ N} \). The magnitude of this force is 1792.17 N, which tells us how strongly the water acts to bring the diver to rest. This nonconservative force dissipates the diver's kinetic energy, that was otherwise conserved from the jump.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A bicyclist rides \(5.0 \mathrm{~km}\) due east, while the resistive force from the air has a magnitude of \(3.0 \mathrm{~N}\) and points due west. The rider then turns around and rides \(5.0 \mathrm{~km}\) due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of \(3.0 \mathrm{~N}\) and points due east. (a) Find the work done by the resistive force during the round trip. (b) Based on your answer to part (a), is the resistive force a conservative force? Explain.

A swing is made from a rope that will tolerate a maximum tension of \(8.00 \times 10^{2} \mathrm{~N}\) without breaking. Initially, the swing hangs vertically. The swing is then pulled back at an angle of \(60.0^{\circ}\) with respect to the vertical and released from rest. What is the mass of the heaviest person who can ride the swing?

When a \(0.045-\mathrm{kg}\) golf ball takes off after being hit, its speed is \(41 \mathrm{~m} / \mathrm{s}\). (a) How much work is done on the ball by the club? (b) Assume that the force of the golf club acts parallel to the motion of the ball and that the club is in contact with the ball for a distance of \(0.010 \mathrm{~m}\). Ignore the weight of the ball and determine the average force applied to the ball by the club.

A \(5.00 \times 10^{2}-\mathrm{kg}\) hot-air balloon takes off from rest at the surface of the earth. The nonconservative wind and lift forces take the balloon up, doing \(+9.70 \times 10^{4} \mathrm{~J}\) of work on the balloon in the process. At what height above the surface of the earth does the balloon have a speed of \(8.00 \mathrm{~m} / \mathrm{s}\) ?

Two cars, \(A\) and \(B\), are traveling with the same speed of \(40.0 \mathrm{~m} / \mathrm{s}\), each having started from rest. Car A has a mass of \(1.20 \times 10^{3} \mathrm{~kg}\), and car \(\mathrm{B}\) has a mass of \(2.00 \times 10^{3} \mathrm{~kg} .\) Compared to the work required to bring car A up to speed, how much additional work is required to bring car B up to speed?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.