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Two cars, \(A\) and \(B\), are traveling with the same speed of \(40.0 \mathrm{~m} / \mathrm{s}\), each having started from rest. Car A has a mass of \(1.20 \times 10^{3} \mathrm{~kg}\), and car \(\mathrm{B}\) has a mass of \(2.00 \times 10^{3} \mathrm{~kg} .\) Compared to the work required to bring car A up to speed, how much additional work is required to bring car B up to speed?

Short Answer

Expert verified
Car B requires an additional 640,000 joules of work compared to Car A.

Step by step solution

01

Understand the Work-Energy Principle

The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. Here, each car starts from rest, so all the work done on a car goes into its kinetic energy.
02

Calculate Kinetic Energy for Car A

The kinetic energy of a car can be calculated using the formula \[KE = \frac{1}{2}mv^2\]For Car A, with mass \(m_A = 1.20 \times 10^3 \text{ kg}\) and velocity \(v = 40.0 \text{ m/s}\), the kinetic energy is:\[KE_A = \frac{1}{2} (1.20 \times 10^3) (40.0)^2\]
03

Evaluate Expression for Car A

Substitute the values into the expression:\[KE_A = \frac{1}{2} (1.20 \times 10^3) (40.0)^2 = 0.5 \times 1200 \times 1600\]\[KE_A = 960,000 \text{ joules}\]
04

Calculate Kinetic Energy for Car B

For Car B, with mass \(m_B = 2.00 \times 10^3 \text{ kg}\) and velocity \(v = 40.0 \text{ m/s}\), the kinetic energy is:\[KE_B = \frac{1}{2} (2.00 \times 10^3) (40.0)^2\]
05

Evaluate Expression for Car B

Substitute the values to find:\[KE_B = \frac{1}{2} (2.00 \times 10^3) (40.0)^2 = 0.5 \times 2000 \times 1600\]\[KE_B = 1,600,000 \text{ joules}\]
06

Compare the Works Done

The additional work needed for Car B, compared to Car A, is found by subtracting the kinetic energy of Car A from Car B:\[W_{additional} = KE_B - KE_A = 1,600,000 - 960,000\]
07

Final Calculation

Perform the subtraction to find the additional work:\[W_{additional} = 640,000 \text{ joules}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. It's an important concept in physics because it helps us understand how energy is transferred when an object is set in motion or comes to a stop.

The formula for kinetic energy, denoted as \[KE = \frac{1}{2} m v^2\]where:
  • KE is the kinetic energy
  • m is the mass of the object
  • v is the velocity of the object
This formula shows that kinetic energy is directly related to both the mass and the square of the velocity of the object. This means that even small increases in velocity can lead to significant increases in kinetic energy.

In the example of the two cars, although Car A and Car B reached the same speed, their different masses resulted in different amounts of kinetic energy.
Work Done
Work done refers to the process of energy transfer that occurs when a force acts upon an object resulting in the displacement of that object.

It's a core concept in understanding how energy forms change and how systems conserve energy. The work-energy principle tells us that the work done on an object results in a change in kinetic energy. This principle can be represented as:\[W = \Delta KE\]which means the work done equals the change in kinetic energy.

In the case of the two cars, bringing each car from a stop to a speed of 40 m/s involved performing work, with all of that work going into increasing the cars' kinetic energy. The calculation of work done for each car was directly related to their kinetic energies, helping us quantify how much effort it took to move these cars to the specified speed.
Mass and Velocity Relationship
The relationship between mass, velocity, and kinetic energy is crucial in understanding how objects move and how much energy they require.

In the kinetic energy formula, \[KE = \frac{1}{2} mv^2\], the mass (m) and velocity (v) are key contributors to the object’s kinetic energy.
Let’s break it down:
  • **Mass (m)**: Heavier objects (with more mass) tend to have more kinetic energy if they are moving at the same speed as a lighter object. This is why Car B, being heavier, had more kinetic energy as compared to Car A.
  • **Velocity (v)**: Since kinetic energy increases with the square of the velocity, any change in velocity leads to much larger changes in kinetic energy. Hence, even small differences in speed can drastically change the energy.
In summary, even when two objects move at the same speed, like our two cars, their kinetic energy can differ broadly due to differences in mass, requiring different quantities of work to achieve that speed. This highlights how both mass and velocity are fundamental in understanding energy dynamics in moving systems.

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Most popular questions from this chapter

The brakes of a truck cause it to slow down by applying a retarding force of \(3.0 \times 10^{3} \mathrm{~N}\) to the truck over a distance of \(850 \mathrm{~m}\). What is the work done by this force on the truck? Is the work positive or negative? Why?

A 63 -kg skier coasts up a snow-covered hill that makes an angle of \(25^{\circ}\) with the horizontal. The initial speed of the skier is \(6.6 \mathrm{~m} / \mathrm{s}\). After coasting a distance of \(1.9 \mathrm{~m}\) up the slope, the speed of the skier is \(4.4 \mathrm{~m} / \mathrm{s}\). (a) Find the work done by the kinetic frictional force that acts on the skis. (b) What is the magnitude of the kinetic frictional force?

A sled is being pulled across a horizontal patch of snow. Friction is negligible. The pulling force points in the same direction as the sled's displacement, which is along the \(+x\) axis. As a result, the kinetic energy of the sled increases by \(38 \% .\) By what percentage would the sled's kinetic energy have increased if this force had pointed \(62^{\circ}\) above the \(+x\) axis?

The drawing shows a version of the loop-the-loop trick for a small car. If the car is given an initial speed of \(4.0 \mathrm{~m} / \mathrm{s}\), what is the largest value that the radius \(r\) can have if the car is to remain in contact with the circular track at all times?

A swing is made from a rope that will tolerate a maximum tension of \(8.00 \times 10^{2} \mathrm{~N}\) without breaking. Initially, the swing hangs vertically. The swing is then pulled back at an angle of \(60.0^{\circ}\) with respect to the vertical and released from rest. What is the mass of the heaviest person who can ride the swing?

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