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In a mall, a shopper rides up an escalator between floors. At the top of the escalator, the shopper turns right and walks \(9.00 \mathrm{~m}\) to a store. The magnitude of the shopper's displacement from the bottom of the escalator is \(16.0 \mathrm{~m}\). The vertical distance between the floors is \(6.00 \mathrm{~m}\). At what angle is the escalator inclined above the horizontal?

Short Answer

Expert verified
The escalator is inclined at approximately \(22.02^\circ\) above the horizontal.

Step by step solution

01

Visualize the Problem

Imagine the scenario: the escalator forms a right triangle with the vertical distance between floors as one leg and a horizontal component (the distance at which they are connected) of the triangle as another leg. The hypotenuse is the escalator itself.
02

Apply the Pythagorean Theorem

We know the hypotenuse (escalator) is \(16.0\, \text{m}\) and one leg (vertical distance) is \(6.00\, \text{m}\). Using the Pythagorean theorem: \[ c^2 = a^2 + b^2 \]Where \(c = 16.0\, \text{m}\), \(a = 6.00\, \text{m}\), and \(b\) is the horizontal component. So, \[ 16.0^2 = 6.00^2 + b^2 \]\[ 256 = 36 + b^2 \]\[ b^2 = 220 \]\[ b = \sqrt{220} \approx 14.83 \, \text{m} \].
03

Find the Angle of Inclination

Use trigonometry to find the angle \(\theta\) above horizontal. Use the sine function, where \[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \]\[ \sin(\theta) = \frac{6.00}{16.0} \]\[ \theta = \sin^{-1}\left(\frac{6.00}{16.0}\right) \]\[ \theta \approx \sin^{-1}(0.375) \approx 22.02^\circ \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry
Trigonometry is a branch of mathematics that deals with the relationship between the angles and sides of triangles, particularly right-angled triangles. In physics, trigonometry is essential for solving problems involving angles and distances, such as calculating the incline angle of a plane or displacement.
Many trigonometric functions, like sine, cosine, and tangent, are used to relate different sides of a triangle. For example, the sine function relates the angle of a triangle to the ratio of the opposite side over the hypotenuse:
  • \( \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \)
This is useful when one knows the lengths of the sides of a triangle and needs to find the angle, or vice versa. For the escalator problem, the relationship between the vertical distance and the hypotenuse helped find the angle of inclination using sine.
Understanding trigonometry provides a fundamental tool for visualizing and solving complex physical problems.
Pythagorean Theorem
The Pythagorean Theorem is one of the most commonly used theorems in mathematics and physics, especially when dealing with right triangles. It states:
  • \( c^2 = a^2 + b^2 \)
Here, \( c \) represents the length of the hypotenuse, the side opposite the right angle, while \( a \) and \( b \) are the lengths of the other two sides—often called the legs of the triangle.
In the context of the escalator problem, the hypotenuse is the escalator itself, with known length \(16.0 \mathrm{~m}\). The vertical leg \(a\) is \(6.00 \mathrm{~m}\), representing the height difference between floors. Using the Pythagorean Theorem:
  • Calculate the horizontal component, \( b \).
  • Use \( b = \sqrt{c^2 - a^2} = \sqrt{256 - 36} = \sqrt{220}\approx 14.83\, \text{m}\)
Thus, this theorem efficiently solves for the unknown side of a triangle, important in many real-life and theoretical situations.
Inclined Plane
An inclined plane is a flat surface tilted at an angle, used to ease the effort of lifting or moving objects upward. In physics, it helps us understand how forces and motions work on a slope.
To analyze forces on an inclined plane, it is crucial to separate the components of a force:
  • The component parallel to the plane, influenced by gravity, is what typically moves an object up or down.
  • The perpendicular component presses objects against the surface of the plane.
In the context of the problem, the escalator serves as the inclined plane. The angle of elevation calculated by the trigonometric function outlines the relationship between vertical and horizontal forces. This understanding helps predict how different angles alter motion and effort required on slopes.
Displacement Calculation
Displacement is a vector quantity describing the change in position of an object from one point to another. Unlike distance, displacement considers direction and not just how far an object has moved.
In physics exercises like the escalator problem, displacement is often visually represented as the hypotenuse of a right triangle when considering motion in three dimensions or along an incline.
  • In this problem, the exact displacement from the starting point (bottom of the escalator) to the endpoint (store location) is given as \(16.0 \mathrm{~m}\).
  • Despite the horizontal movement of \(9.00 \mathrm{~m}\) after reaching the top, initial displacement solely considers the change in position up the escalator.
Understanding displacement is key to solving many real-world physics problems, as it provides both magnitude and direction of an object's movement, critical for accurate calculations and analyses.

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Most popular questions from this chapter

In the javelin throw at a track-and-field event, the javelin is launched at a speed of \(29 \mathrm{~m} /\) s at an angle of \(36^{\circ}\) above the horizontal. As the javelin travels upward, its velocity points above the horizontal at an angle that decreases as time passes. How much time is required for the angle to be reduced from \(36^{\circ}\) at launch to \(18^{\circ}\) ?

A swimmer, capable of swimming at a speed of \(1.4 \mathrm{~m} / \mathrm{s}\) in still water (i.e., the swimmer can swim with a speed of \(1.4 \mathrm{~m} / \mathrm{s}\) relative to the water), starts to swim directly across a 2.8-km- wide river. However, the current is \(0.91 \mathrm{~m} / \mathrm{s}\), and it carries the swimmer downstream, (a) How long does it take the swimmer to cross the river? (b) How far downstream will the swimmer be upon reaching the other side of the river?

On a spacecraft, two engines are turned on for \(684 \mathrm{~s}\) at a moment when the velocity of the craft has \(x\) and \(y\) components of \(v_{0 x}=4370 \mathrm{~m} / \mathrm{s}\) and \(v_{0 y}=6280 \mathrm{~m} / \mathrm{s} .\) While the engines are firing, the craft undergoes a displacement that has components of \(x=4.11 \times 10^{6} \mathrm{~m}\) and \(y=6.07 \times 10^{6} \mathrm{~m} .\) Find the \(x\) and \(y\) components of the craft's acceleration.

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Two cars, \(A\) and \(B,\) are traveling in the same direction, although car \(A\) is \(186 \mathrm{~m}\) behind car \(\mathrm{B}\). The speed of \(\mathrm{A}\) is \(24.4 \mathrm{~m} / \mathrm{s},\) and the speed of \(\mathrm{B}\) is \(18.6 \mathrm{~m} / \mathrm{s}\). How much time does it take for A to catch B?

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