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On a spacecraft, two engines are turned on for \(684 \mathrm{~s}\) at a moment when the velocity of the craft has \(x\) and \(y\) components of \(v_{0 x}=4370 \mathrm{~m} / \mathrm{s}\) and \(v_{0 y}=6280 \mathrm{~m} / \mathrm{s} .\) While the engines are firing, the craft undergoes a displacement that has components of \(x=4.11 \times 10^{6} \mathrm{~m}\) and \(y=6.07 \times 10^{6} \mathrm{~m} .\) Find the \(x\) and \(y\) components of the craft's acceleration.

Short Answer

Expert verified
The acceleration components are \(a_x \approx 4.79 \text{ m/s}^2\) and \(a_y \approx 7.59 \text{ m/s}^2\).

Step by step solution

01

Define the Displacement Equation

The displacement equation for each component can be defined as:\[ x = v_{0x} t + \frac{1}{2} a_x t^2 \]\[ y = v_{0y} t + \frac{1}{2} a_y t^2 \] Given, \( x = 4.11 \times 10^6 \) m, \( y = 6.07 \times 10^6 \) m, \( v_{0x} = 4370 \) m/s, \( v_{0y} = 6280 \) m/s, and \( t = 684 \) s.
02

Solve for the Acceleration Component \( a_x \)

Substitute the given values into the x-component displacement equation:\[ 4.11 \times 10^6 = 4370 \times 684 + \frac{1}{2} a_x (684)^2 \]Calculate \( 4370 \times 684 = 2,989,080 \):\[ 4.11 \times 10^6 = 2,989,080 + \frac{1}{2} a_x \times 467,856 \]Subtract 2,989,080 from both sides:\[ 1,120,920 = \frac{1}{2} a_x \times 467,856 \]Multiply both sides by 2:\[ 2,241,840 = a_x \times 467,856 \]Finally, solve for \( a_x \):\[ a_x = \frac{2,241,840}{467,856} \approx 4.79 \text{ m/s}^2 \]
03

Solve for the Acceleration Component \( a_y \)

Substitute the given values into the y-component displacement equation:\[ 6.07 \times 10^6 = 6280 \times 684 + \frac{1}{2} a_y (684)^2 \]Calculate \( 6280 \times 684 = 4,292,520 \):\[ 6.07 \times 10^6 = 4,292,520 + \frac{1}{2} a_y \times 467,856 \]Subtract 4,292,520 from both sides:\[ 1,777,480 = \frac{1}{2} a_y \times 467,856 \]Multiply both sides by 2:\[ 3,554,960 = a_y \times 467,856 \]Finally, solve for \( a_y \):\[ a_y = \frac{3,554,960}{467,856} \approx 7.59 \text{ m/s}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement Equation
In physics, the displacement equation is essential for describing the movement of an object over time. It tells us how far an object has moved from its initial position in a given time span. For our spacecraft, let’s examine both the x and y components of displacement separately. The displacement equations for each axis are given by:
  • For the x-axis: \( x = v_{0x} t + \frac{1}{2} a_x t^2 \)
  • For the y-axis: \( y = v_{0y} t + \frac{1}{2} a_y t^2 \)

Here, \( v_{0x} \) and \( v_{0y} \) are the initial velocities along the x and y axes, respectively. \( a_x \) and \( a_y \) are the accelerations in each direction. These equations highlight that displacement depends on both the initial velocity and how much acceleration is acting over time.

With a given time \( t \), we can plug in known values to solve for the unknown accelerations \( a_x \) and \( a_y \). Understanding these equations allows us to accurately determine how the spacecraft moves through space under the influence of its engines.
Velocity Components
The velocity components of an object indicate its speed and direction in two-dimensional space. For the spacecraft, these components are important to understand how it initially moves before and after the impact of engine firings.

Initially, the spacecraft velocity is broken down into:
  • The x-component of velocity, \( v_{0x} = 4370 \) m/s, represents movement along the horizontal axis.
  • The y-component of velocity, \( v_{0y} = 6280 \) m/s, represents movement along the vertical axis.
By knowing these components, we can determine the direction and magnitude of the spacecraft's initial motion.

As the engines exert a force, the spacecraft’s velocity changes over time. This change is reflected in the acceleration components that modify the velocity components. This process translates into a new trajectory for the spacecraft, dependent on how strong and in which direction the engines push.

Ultimately, understanding velocity components helps describe the precise speed and direction of the spacecraft at any given point in its journey.
Spacecraft Dynamics
Spacecraft dynamics involve understanding how forces like thrust affect a spacecraft's motion. In our problem, the engines create forces that result in changes in the spacecraft's velocity and displacement.

When the spacecraft's engines are at work for a duration of 684 seconds, they alter the craft's trajectory. These dynamics can be broken down using equations for displacement and velocity. The forces exerted by the engines correspond to the components of acceleration \( a_x \) and \( a_y \) which we calculated earlier.
  • The understanding of spacecraft dynamics helps us predict the path and final velocities of the spacecraft after a given maneuver.
  • It's crucial in planning and executing space missions where precise control over the vehicle's position and speed is vital.
Knowing these dynamics ensures safe navigation and arrival at desired locations, such as other planets or back to Earth. Through the interplay of initial conditions, forces, and resulting accelerations, we can control and predict the spacecraft’s behavior in outer space.

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Most popular questions from this chapter

A Coast Guard ship is traveling at a constant velocity of \(4.20 \mathrm{~m} / \mathrm{s},\) due east, relative to the water. On his radar screen the navigator detects an object that is moving at a constant velocity. The object is located at a distance of \(2310 \mathrm{~m}\) with respect to the ship, in a direction \(32.0^{\circ}\) south of east. Six minutes later, he notes that the object's position relative to the ship has changed to \(1120 \mathrm{~m}, 57.0^{\circ}\) south of west. What are the magnitude and direction of the velocity of the object relative to the water? Express the direction as an angle with respect to due west.

A fire hose ejects a stream of water at an angle of \(35.0^{\circ}\) above the horizontal. The water leaves the nozzle with a speed of \(25.0 \mathrm{~m} / \mathrm{s}\). Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

The captain of a plane wishes to proceed due west. The cruising speed of the plane is \(245 \mathrm{~m} / \mathrm{s}\) relative to the air. A weather report indicates that a \(38.0-\mathrm{m} / \mathrm{s}\) wind is blowing from the south to the north. In what direction, measured with respect to due west, should the pilot head the plane relative to the air?

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A jetliner can fly 6.00 hours on a full load of fuel. Without any wind it flies at a speed of \(2.40 \times 10^{2} \mathrm{~m} / \mathrm{s} .\) The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a \(57.8-\mathrm{m} / \mathrm{s}\) wind from the jet stream, which blows from west to east. What is the maximum distance that the plane can travel due west and just be able to return home?

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