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Concept Questions A flat coil of wire has an area \(A\), \(N\) turns, and a resistance \(R\). It is situated in a magnetic field such that the normal to the coil is parallel to the magnetic field. The coil is then rotated through an angle of \(90^{\circ}\), so that the normal becomes perpendicular to the magnetic field. (a) Why is an emf induced in the coil? (b) What determines the amount of induced current in the coil? (c) How is the amount of charge \(\Delta q\) that flows related to the induced current \(I\) and the time interval \(t-t_{0}\) during which the coil rotates? Problem The coil has an area of \(1.5 \times 10^{-3} \mathrm{~m}^{2}, 50\) turns, and a resistance of \(140 \Omega\). During the time when it is rotating, a charge of \(8.5 \times 10^{-5} \mathrm{C}\) flows in the coil. What is the magnitude of the magnetic field?

Short Answer

Expert verified
Magnetic field magnitude is 0.016 T.

Step by step solution

01

Understanding why emf is induced

The principle of electromagnetic induction states that an emf (electromotive force) is induced in a coil when there is a change in magnetic flux through the coil. When the coil rotates from a position where its normal is parallel to the magnetic field to perpendicular (90° rotation), the magnetic flux through the coil changes, inducing an emf.
02

Factors determining induced current

The amount of induced current in the coil is determined by Ohm's Law, which is given by \( I = \frac{\text{emf}}{R} \), where \( I \) is the current, \( \text{emf} \) is the induced electromotive force, and \( R \) is the resistance of the coil. The emf itself is influenced by the rate of change of magnetic flux, which depends on factors such as the coil's area, the number of turns, the strength of the magnetic field, and the speed of rotation.
03

Relating charge, current, and time interval

The total charge \( \Delta q \) that flows through the coil is related to the induced current \( I \) and the time interval \( \Delta t = t - t_0 \) by the equation \( \Delta q = I \cdot \Delta t \). This relationship shows that the charge is the product of current and the time during which the current flows.
04

Calculate the total induced emf during rotation

Since \( \Delta q = 8.5 \times 10^{-5} \) C flowed in the coil, and using the relationship \( \Delta q = I \cdot \Delta t \) and \( I = \frac{\text{emf}}{R} \), we can express the total induced emf as \( \text{emf} \cdot \Delta t = R \cdot \Delta q \). Substituting the given resistance, \( R = 140 \Omega \), we find: \[ \text{emf} \cdot \Delta t = 140 \Omega \cdot 8.5 \times 10^{-5} \text{ C} \].
05

Calculate change in magnetic flux

The induced emf is also given by Faraday's Law: \( \text{emf} = -N \frac{\Delta \Phi}{\Delta t} \), where \( N \) is the number of turns, and \( \Delta \Phi \) is the change in magnetic flux. Since \( \Delta \Phi = B(A_f - A_i) = BA \) where \( A_f \) is the final area (0 when perpendicular) and \( A = 1.5 \times 10^{-3} \text{ m}^2 \), we find \( \Delta \Phi = -BA \) when the coil goes from parallel to perpendicular.
06

Solve for the magnetic field magnitude

By equating the expressions for \( \text{emf} \): \( \text{emf} \cdot \Delta t = 140 \times 8.5 \times 10^{-5} = N \cdot BA \), solving for \( B \), we get: \[ B = \frac{140 \cdot 8.5 \times 10^{-5}}{N \cdot A} \]. Substituting \( N = 50 \) and \( A = 1.5 \times 10^{-3} \): \[ B = \frac{140 \cdot 8.5 \times 10^{-5}}{50 \cdot 1.5 \times 10^{-3}} = 0.016 \text{ T} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a central concept in understanding electromagnetic induction. It measures the amount of magnetic field passing through a given area. Imagine a magnetic field as a collection of invisible lines flowing through space. These lines penetrating through a surface define the magnetic flux.

The formula for calculating magnetic flux is given by:
  • \( \Phi = B \cdot A \cdot \cos(\theta) \)
Here, \( \Phi \) represents the magnetic flux, \( B \) is the magnetic field strength, \( A \) is the area through which the lines pass, and \( \theta \) is the angle between the magnetic field lines and the perpendicular (normal) to the surface.

When a coil rotates in a magnetic field, the angle \( \theta \) changes, altering the magnetic flux passing through the coil. This change is what sets the stage for electromagnetic induction.
Induced EMF
The concept of induced electromotive force (emf) arises from changes in magnetic flux. As the name suggests, it is a force that "motors" the electrons to move, creating an electric current. Induced emf can be visualized as a driver of current, resulting from alterations in the magnetic environment.
  • The induced emf (\(\text{emf}\)) is quantitatively described by Faraday's Law, as shown in the formula: \(\text{emf} = -N \frac{\Delta \Phi}{\Delta t}\), where \( N \) is the number of turns in the coil and \( \Delta \Phi \) is the change in magnetic flux over time \(\Delta t\).
The sign is negative due to Lenz's Law, emphasizing that the induced emf will always oppose the change causing it. This is akin to physical principles such as inertia or friction which resist changes in motion.

The magnitude of induced emf is affected by factors including:
  • The rate of change of the magnetic field.
  • The area of the coil.
  • The number of turns in the coil.
Faraday's Law
Faraday's Law is a fundamental pillar of electromagnetism and describes how electric currents can be produced by changing magnetic fields. This principle is foundational in technologies like electric generators and transformers.

According to this law, an emf is induced in a circuit if the magnetic flux through the circuit changes with time. The induced emf is directly proportional to the rate of change of the magnetic flux. Mathematically, it is expressed as:
  • \(\text{emf} = -N \frac{\Delta \Phi}{\Delta t}\)
Where:
  • \(\Delta \Phi\) is the change in magnetic flux.
  • \(\Delta t\) is the change in time.
  • \(N\) is the number of loops in the wire.
This equation illustrates why rotating a coil in a magnetic field, thus altering its angle relative to the field, induces an emf.

We see Faraday's Law in everyday electric devices. It's what allows power plants to convert mechanical energy into electrical energy.
Ohm's Law
Ohm's Law is a foundational principle that describes how voltage, current, and resistance interrelate in electric circuits. It's a simple formula but potent in application, especially in understanding how currents flow in response to voltages.

The relationship is expressed in the equation:
  • \( V = I \cdot R \)
Here, \( V \) represents the voltage (or induced emf in the context of electromagnetic induction), \( I \) is the current, and \( R \) is the resistance in the circuit.

In electromagnetic induction, knowing the induced emf and the resistance of a coil allows us to calculate the induced current using Ohm's Law:
  • \( I = \frac{\text{emf}}{R} \)
This relationship helps determine how strong a current is produced by an induced emf which is crucial in assessing the functionality and efficiency of devices like transformers and motors. Understanding Ohm's Law is fundamental to designing circuits that effectively channel the induced currents.

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Most popular questions from this chapter

The rechargeable batteries for a laptop computer need a much smaller voltage than what a wall socket provides. Therefore, a transformer is plugged into the wall socket and produces the necessary voltage for charging the batteries. (a) Is the transformer a step-up or a step-down transformer? (b) Is the current that goes through the batteries greater than, equal to, or smaller than the current coming from the wall socket? (c) If the transformer has a negligible resistance, is the electric power delivered to the batteries greater than, equal to, or less than the power coming from the wall socket? In all cases, provide a reason for your answer. the batteries of a laptop computer are rated at \(9.0 \mathrm{~V}\), and a current of \(225 \mathrm{~mA}\) is used to charge them. The wall socket provides a voltage of \(120 \mathrm{~V}\). (a) Determine the turns ratio of the transformer, (b) What is the current coming from the wall socket? (c) Find the power delivered by the wall socket and the power sent to the batteries. Be sure your answers are consistent with your answers to the Concept Questions.

Mutual induction can be used as the basis for a metal detector. A typical setup uses two large coils that are parallel to each other and have a common axis. Because of mutual induction, the ac generator connected to the primary coil causes an emf of \(0.46 \mathrm{~V}\) to be induced in the secondary coil. When someone without metal objects walks through the coils, the mutual inductance and, thus, the induced emf do not change much. But when a person carrying a hand gun walks through, the mutual inductance increases. The change in emf can be used to trigger an alarm. If the mutual inductance increases by a factor of three, find the new value of the induced emf.

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is \(50: 1\). The primary coil is plugged into a standard \(120-V\) outlet. The current in the secondary coil is \(1.7 \times 10^{-3} \mathrm{~A}\). Find the power consumed by the air filter.

A house has a floor area of \(112 \mathrm{~m}^{2}\) and an outside wall that has an area of \(28 \mathrm{~m}^{2}\). The earth's magnetic field here has a horizontal component of \(2.6 \times 10^{-5} \mathrm{~T}\) that points due north and a vertical component of \(4.2 \times 10^{-5} \mathrm{~T}\) that points straight down, toward the earth. Determine the magnetic flux through the wall if the wall faces (a) north and (b) east. (c) Calculate the magnetic flux that passes through the floor.

The drawing shows a type of flow meter that can be used to measure the speed of blood in situations when a blood vessel is sufficiently exposed (e.g., during surgery). Blood is conductive enough that it can be treated as a moving conductor. When it flows perpendicularly with respect to a magnetic field, as in the drawing, electrodes can be used to measure the small voltage that develops across the vessel. Suppose the speed of the blood is \(0.30 \mathrm{~m} / \mathrm{s}\) and the diameter of the vessel is \(5.6 \mathrm{~mm} .\) In a 0.60 -T magnetic field what is the magnitude of the voltage that is measured with the electrodes in the drawing?

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