/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 The secondary coil of a step-up ... [FREE SOLUTION] | 91Ó°ÊÓ

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The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is \(50: 1\). The primary coil is plugged into a standard \(120-V\) outlet. The current in the secondary coil is \(1.7 \times 10^{-3} \mathrm{~A}\). Find the power consumed by the air filter.

Short Answer

Expert verified
The power consumed by the air filter is 10.2 watts.

Step by step solution

01

Understand the Transformer Turns Ratio

A step-up transformer increases voltage from the primary to the secondary coil according to the turns ratio. Here, the turns ratio is 50:1, which means the secondary voltage is 50 times the primary voltage.
02

Calculate the Secondary Voltage

The primary voltage is 120 V. Using the turns ratio 50:1, the secondary voltage \( V_s \) is calculated as \( V_s = 50 \times 120 = 6000 \) volts.
03

Understand Power Calculation in the Secondary Coil

The power consumed by an electric circuit is given by the formula \( P = V imes I \), where \( P \) is power, \( V \) is voltage, and \( I \) is current. We can use this formula to find the power consumed by the air filter.
04

Calculate Power in the Secondary Coil

Using the calculated secondary voltage \( V_s = 6000 \) volts and the given secondary current \( I_s = 1.7 \times 10^{-3} \) A, the power \( P \) consumed is \( P = 6000 \times 1.7 \times 10^{-3} = 10.2 \) watts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Induction
Electromagnetic induction is a fundamental concept in physics where a voltage is generated in a conductor by a changing magnetic field. This principle was first discovered by Michael Faraday and is the principle behind transformers. In a transformer, when alternating current flows through the primary coil, it creates a changing magnetic field that induces a voltage in the secondary coil. This process is essential for the functioning of transformers, which are used to either increase (step-up) or decrease (step-down) voltage levels depending on the application. The efficiency of electromagnetic induction is key to ensuring that energy is not lost during the transformation process, allowing for effective transfer of electrical energy from one coil to another.

Understanding electromagnetic induction helps in grasping how transformers work and the way they convert electrical energy at different voltage levels. This is particularly important in electricity transmission systems where voltage levels need adjustment for safe and efficient transportation of electricity over long distances.
Power Consumption
Power consumption refers to the amount of electrical energy used by an electrical device or circuit over time. It's measured in watts (W), indicating how much energy is consumed per unit time. In the context of transformers, power consumption is an important aspect to consider, especially in the secondary coil, which delivers the final output voltage and current to the device.

Calculating power consumption involves using the formula \( P = V \times I \), where \( P \) is power, \( V \) is voltage, and \( I \) is the current. In our exercise, we determine the power consumed by the air filter connected to the secondary coil by applying this formula.
  • Understand that higher power consumption means more energy usage, and in electric circuits, this could translate to efficiency losses if not properly managed.
  • Power consumption calculation helps in determining the actual energy requirement of an electrical appliance at any given moment, which is crucial for designing energy-efficient systems.
  • By analyzing power consumption, consumers can better evaluate their energy usage and optimize it, reducing costs and enhancing sustainability.

Understanding power consumption is vital in many applications, particularly in designing electrical circuits and managing energy resources effectively.
Step-Up Transformer
A step-up transformer is a device that increases the voltage from the primary side to the secondary side of the transformer. This is achieved by having more turns of wire on the secondary coil than the primary coil, as seen with the given turns ratio of 50:1. This means that the voltage output on the secondary side is 50 times greater than the primary voltage.

Step-up transformers are crucial in electrical systems where higher voltage levels are needed, such as in power transmission over long distances. By stepping up the voltage, the transformer helps in reducing energy losses since a higher voltage allows for efficient transmission.

  • Main characteristic: More turns on the secondary coil than the primary coil.
  • Purpose: Boost voltage for efficient energy transfer.
  • Applications: Used in electronic devices and power grids where high voltage is necessary for performance or transmission.

With a step-up transformer, it's essential to understand the relationship between voltage and current, as increasing the voltage decreases the current, maintaining the power level consistent.
Voltage and Current Relationship
The relationship between voltage and current in a transformer is governed by the principle of conservation of energy and can be defined using the equation: \( V_p \times I_p = V_s \times I_s \), where \( V_p \) and \( I_p \) are the primary voltage and current respectively, and \( V_s \) and \( I_s \) are the secondary voltage and current respectively.

From this equation, it's clear that if the voltage is increased (as it is in a step-up transformer), the current must decrease to maintain the energy balance—assuming an ideal transformer with 100% efficiency. This inverse relationship between voltage and current is fundamental in transformer operations.

  • Increase in voltage results in a proportional decrease in current, helping in maintaining power continuity.
  • This relationship ensures that transformers efficiently transfer electrical energy without unnecessary losses.
  • Engineers use this relationship to design circuit systems that require specific voltage and current levels for optimal operation.

Understanding the voltage and current relationship allows for better design and optimization of electrical systems, ensuring effective power distribution and device performance.

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Most popular questions from this chapter

One generator uses a magnetic field of \(0.10 \mathrm{~T}\) and has a coil area per turn of \(0.045 \mathrm{~m}^{2} . \mathrm{A}\) second generator has a coil area per turn of \(0.015 \mathrm{~m}^{2}\). The generator coils have the same number of turns and rotate at the same angular speed. What magnetic field should be used in the second generator so that its peak emf is the same as that of the first generator?

Concept Questions A constant current \(I\) exists in a solenoid whose inductance is \(L .\) The current is then reduced to zero in a certain amount of time. (a) If the wire from which the solenoid is made has no resistance, is there a voltage across the solenoid during the time when the current is constant? (b) If the wire from which the solenoid is made has no resistance, is there an emf across the solenoid during the time that the current is being reduced to zero? (c) Does the solenoid store electrical energy when the current is constant? If so, express this energy in terms of the current and the inductance. (d) When the current is reduced from its constant value to zero, what is the rate at which energy is removed from the solenoid? Express your answer in terms of the initial current, the inductance, and the time during which the current goes to zero. Problem A solenoid has an inductance of \(L=3.1 \mathrm{H}\) and carries a current of \(I=15 \mathrm{~A}\). (a) If the current goes from 15 to \(0 \mathrm{~A}\) in a time of \(75 \mathrm{~ms}\), what is the emf induced in the solenoid? (b) How much electrical energy is stored in the solenoid? (c) At what rate must the electrical energy be removed from the solenoid when the current is reduced to zero in \(75 \mathrm{~ms} ?\)

Interactive Solution \(\underline{22.39}\) at provides one model for solving this problem. The maximum strength of the earth's magnetic field is about \(6.9 \times 10^{-5} \mathrm{~T}\) near the south magnetic pole. In principle, this field could be used with a rotating coil to generate 60.0 Hz ac electricity. What is the minimum number of turns (area per turn \(=0.022 \mathrm{~m}^{2}\) ) that the coil must have to produce an rms voltage of \(120 \mathrm{~V} ?\)

The rechargeable batteries for a laptop computer need a much smaller voltage than what a wall socket provides. Therefore, a transformer is plugged into the wall socket and produces the necessary voltage for charging the batteries. (a) Is the transformer a step-up or a step-down transformer? (b) Is the current that goes through the batteries greater than, equal to, or smaller than the current coming from the wall socket? (c) If the transformer has a negligible resistance, is the electric power delivered to the batteries greater than, equal to, or less than the power coming from the wall socket? In all cases, provide a reason for your answer. the batteries of a laptop computer are rated at \(9.0 \mathrm{~V}\), and a current of \(225 \mathrm{~mA}\) is used to charge them. The wall socket provides a voltage of \(120 \mathrm{~V}\). (a) Determine the turns ratio of the transformer, (b) What is the current coming from the wall socket? (c) Find the power delivered by the wall socket and the power sent to the batteries. Be sure your answers are consistent with your answers to the Concept Questions.

A rectangular loop of wire with sides 0.20 and \(0.35 \mathrm{~m}\) lies in a plane perpendicular to a constant magnetic field (see part \(a\) of the drawing). The magnetic field has a magnitude of \(0.65 \mathrm{~T}\) and is directed parallel to the normal of the loop's surface. In a time of \(0.18 \mathrm{~s}\), one-half of the loop is then folded back onto the other half, as indicated in part \(b\) of the drawing. Determine the magnitude of the average emf induced in the loop.

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