/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A vacuum cleaner is plugged into... [FREE SOLUTION] | 91Ó°ÊÓ

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A vacuum cleaner is plugged into a \(120.0\) -V socket and uses \(3.0\) A of current in normal operation when the back emf generated by the electric motor is \(72.0 \mathrm{~V}\). Find the coil resistance of the motor.

Short Answer

Expert verified
The coil resistance is 16.0 Ω.

Step by step solution

01

Understand the Problem

We are given that the vacuum cleaner operates at a voltage of \(120.0\) V with a current of \(3.0\) A. The back electromotive force (emf) generated is \(72.0\) V. We need to find the coil resistance of the motor.
02

Apply Ohm's Law Concept

Ohm's Law states that \(V = IR\), where \(V\) is the voltage across the resistor, \(I\) is the current, and \(R\) is the resistance. We can use this relationship to find the resistance of the motor coil.
03

Calculate Effective Voltage

The effective voltage across the motor coil is the difference between the supplied voltage and the back emf. Calculate it using: \[ V_{\text{effective}} = V_{\text{total}} - \text{Back Emf}\]\[ V_{\text{effective}} = 120.0 \, \text{V} - 72.0 \, \text{V} = 48.0 \, \text{V} \]
04

Calculate Coil Resistance

Use Ohm's Law to find the coil resistance: \[ R = \frac{V_{\text{effective}}}{I} \]Substitute the values: \[ R = \frac{48.0 \, \text{V}}{3.0 \, \text{A}} = 16.0 \, \Omega \] Thus, the coil resistance is \(16.0 \, \Omega\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Coil Resistance
In an electric motor, like the one in a vacuum cleaner, coil resistance is a key factor. It describes how much the motor coil resists the electrical current flow through it. The "coil" is just a long wire wound into a coil shape to make better use of the electromagnetic effects. More resistance means the coil will heat up more easily, as some electrical energy gets converted to heat instead of doing useful work.
To find the coil resistance in a motor, we use Ohm's Law. This is expressed as \(R = \frac{V_{ ext{effective}}}{I}\), where \(V_{\text{effective}}\) is the voltage across the coil and \(I\) is the current through it. Coil resistance is crucial for understanding how efficiently the motor operates and how much power is lost as heat.
Explaining Back Electromotive Force
Back electromotive force (emf) is another important concept when dealing with electric motors. It is the voltage that is generated by the motor itself as it spins. When the motor's coil spins within a magnetic field, it induces a voltage opposite to the supplied voltage. This is what's called back emf.
  • Back emf works against the applied potential difference.
  • It affects how fast the motor can spin.
  • It increases with the speed at which the motor operates, providing a natural form of speed regulation.
This opposing force must be considered to determine the effective voltage, and thus affects calculations regarding power and resistance.
How an Electric Motor Functions
An electric motor is a device that transforms electrical energy into mechanical energy. It does this by using electromagnetism. Inside the motor, electric current passing through coils creates a magnetic field. This magnetic field interacts with permanent magnets or other coils, causing rotation. This rotation is then used to perform work, such as turning the fan in a vacuum cleaner.
Electric motors are efficient and have been around for over a century, being crucial in countless everyday appliances. Understanding the above concepts, like coil resistance and back emf, helps optimize their performance and reliability.
Determining Effective Voltage
Effective voltage is the actual voltage that does useful work in the motor. It's the difference between the supply voltage and the back emf. You can think of it as the "push" available to make the motor turn, after accounting for the opposition from back emf.
With the help of the equation \(V_{\text{effective}} = V_{\text{total}} - \text{Back Emf}\), we calculate how much voltage is effectively driving the motor. This is crucial for applying Ohm's Law to find coil resistance, and it determines how much power the motor can deliver. Knowing this helps in designing motors for efficiency and effectiveness.

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Most popular questions from this chapter

The earth's magnetic field, like any magnetic field, stores energy. The maximum strength of the earth's field is about \(7.0 \times 10^{-5} \mathrm{~T}\). Find the maximum magnetic energy stored in the space above a city if the space occupies an area of \(5.0 \times 10^{8} \mathrm{~m}^{2}\) and has a height of \(1500 \mathrm{~m}\).

A step-down transformer (turns ratio \(=1: 8\) ) is used with an electric train to reduce the voltage from the wall receptacle to a value needed to operate the train. When the train is running, the current in the secondary coil is \(1.6 \mathrm{~A}\). What is the current in the primary coil?

Interactive Solution \(\underline{22.39}\) at provides one model for solving this problem. The maximum strength of the earth's magnetic field is about \(6.9 \times 10^{-5} \mathrm{~T}\) near the south magnetic pole. In principle, this field could be used with a rotating coil to generate 60.0 Hz ac electricity. What is the minimum number of turns (area per turn \(=0.022 \mathrm{~m}^{2}\) ) that the coil must have to produce an rms voltage of \(120 \mathrm{~V} ?\)

A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius \(r=0.20 \mathrm{~m} .\) The normal to the plane of the loop is parallel to a constant magnetic field \(\left(\phi=0^{\circ}\right)\) of magnitude \(0.75 \mathrm{~T}\). What is the change \(\Delta \Phi\) in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?

A planar coil of wire has a single turn. The normal to this coil is parallel to a uniform and constant (in time) magnetic field of \(1.7 \mathrm{~T}\). An emf that has a magnitude of \(2.6 \mathrm{~V}\) is induced in this coil because the coil's area \(A\) is shrinking. What is the magnitude of \(\Delta A / \Delta t,\) which is the rate \(\left(\right.\) in \(\left.m^{2} / s\right)\) at which the area changes?

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