/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 A planar coil of wire has a sing... [FREE SOLUTION] | 91Ó°ÊÓ

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A planar coil of wire has a single turn. The normal to this coil is parallel to a uniform and constant (in time) magnetic field of \(1.7 \mathrm{~T}\). An emf that has a magnitude of \(2.6 \mathrm{~V}\) is induced in this coil because the coil's area \(A\) is shrinking. What is the magnitude of \(\Delta A / \Delta t,\) which is the rate \(\left(\right.\) in \(\left.m^{2} / s\right)\) at which the area changes?

Short Answer

Expert verified
The rate at which the area changes is approximately \(-1.53\, \mathrm{m^2/s}\), indicating a decrease in area.

Step by step solution

01

Understanding the Concept

We need to find the rate at which the area of the coil changes, which is represented by \(\Delta A / \Delta t\). According to Faraday's law of electromagnetic induction, the induced electromotive force (emf) \(\epsilon\) is related to the change in magnetic flux. The equation is \(\epsilon = -\frac{d\Phi}{dt}\).
02

Relating Magnetic Flux to Area

Magnetic flux \(\Phi\) through the coil can be expressed as \(\Phi = B \cdot A \cdot \cos\theta\), where \(B\) is the magnetic field strength and \(\theta\) is the angle between the magnetic field and the normal to the coil. Here, \(\theta = 0\) since the normal to the coil is parallel to the magnetic field, so \(\cos\theta = 1\). Therefore, \(\Phi = B \cdot A\).
03

Expressing Change in Flux

Since the magnetic field \(B=1.7\, \mathrm{T}\) is constant, the change in magnetic flux \(\frac{d\Phi}{dt}\) is \(B \cdot \frac{dA}{dt}\). Then the emf can be written as \(\epsilon = -B \cdot \frac{dA}{dt}\).
04

Solving for the Rate of Area Change

Rearrange the equation \(\epsilon = -B \cdot \frac{dA}{dt}\) to solve for \(\frac{dA}{dt}\): \(\frac{dA}{dt} = -\frac{\epsilon}{B}\). Substitute \(\epsilon = 2.6\, \mathrm{V}\) and \(B = 1.7\, \mathrm{T}\) into the formula: \(\frac{dA}{dt} = -\frac{2.6}{1.7}\).
05

Calculating the Rate

Perform the calculation: \(\frac{dA}{dt} = -1.529\, \mathrm{m^2/s}\). The negative sign indicates the area is decreasing, which is consistent with the problem statement about the coil's area shrinking.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a fundamental concept in electromagnetism that links the magnetic field to the physical object it penetrates. Imagine magnetic flux as the number of magnetic field lines passing through a given area. It captures the essence of how a magnetic field influences the space it occupies.
In mathematical terms, magnetic flux \( \Phi \) is expressed as: \[ \Phi = B \cdot A \cdot \cos\theta \]
- \( B \) is the magnetic field strength (in Tesla, T).- \( A \) is the area through which the field lines pass (in square meters, m²).- \( \theta \) is the angle between the magnetic field direction and the perpendicular (normal) to the area.
In many exercises, like the one discussed, the magnetic field is perpendicular to the coil (\( \theta = 0 \)). Therefore, the formula simplifies to:\[ \Phi = B \cdot A \]
This direct relationship makes it clear how a change in area \( A \) affects the magnetic flux, particularly important in Faraday's Law.
EMF (Electromotive Force)
Electromotive force (emf) is the voltage generated by changing magnetic fields. According to Faraday's Law of Electromagnetic Induction, an emf is induced when there is a change in magnetic flux through a circuit.
Faraday's Law is expressed as: \[ \epsilon = -\frac{d\Phi}{dt} \]
- \( \epsilon \) is the electromotive force (in volts, V).- \( \frac{d\Phi}{dt} \) is the rate of change of magnetic flux (in webers per second, Wb/s).
The negative sign in the equation represents Lenz's Law, indicating that the induced emf generates a current that opposes the change in flux. This is a crucial aspect of electromagnetic principles, ensuring the conservation of energy.
In the context of our exercise, a shrinking coil area results in a varying magnetic flux, thus inducing an emf.
Coil Area Change
The change in a coil's area is often the core cause for a change in magnetic flux, which in turn induces an emf. In situations where the coil's shape or size is modified, the area \( A \) is either increasing or reducing. Here, as the coil area shrinks over time, we focus on the rate of change.
In mathematical terms, this rate is denoted as \( \frac{\Delta A}{\Delta t} \) for average rates or \( \frac{dA}{dt} \) for instantaneous situations.
When inserted into the equation \( \epsilon = -B \cdot \frac{dA}{dt} \), this term shows how quickly the area is changing. By rearranging terms and solving for \( \frac{dA}{dt} \), we isolate the rate at which the area changes: \[ \frac{dA}{dt} = -\frac{\epsilon}{B} \]
Using the given values from the exercise, \( \epsilon = 2.6 \, \text{V} \) and \( B = 1.7 \, \text{T} \), the calculation gives:\[ \frac{dA}{dt} = -1.529 \, \text{m}^2/\text{s} \]
The negative outcome shows the reduction in area, consistent with the description of the coil shrinking. Understanding area change is key to applying Faraday's Law effectively in real-world scenarios.

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Most popular questions from this chapter

A magnetic field is passing through a loop of wire whose area is \(0.018 \mathrm{~m}^{2}\). The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of \(0.20 \mathrm{~T} / \mathrm{s}\). (a) Determine the magnitude of the emf induced in the loop. (b) Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in \(\mathrm{m}^{2} / \mathrm{s}\) ) should the area be changed at the instant when \(B=1.8 \mathrm{~T}\) if the induced emf is to be zero? Explain whether the area is to be enlarged or shrunk.

Multiple-Concept Example 13 reviews some of the principles used in this problem. Suppose you wish to make a solenoid whose self-inductance is \(1.4 \mathrm{mH}\). The inductor is to have a cross-sectional area of \(1.2 \times 10^{-3} \mathrm{~m}^{2}\) and a length of \(0.052 \mathrm{~m}\). How many turns of wire are needed?

A rectangular loop of wire with sides 0.20 and \(0.35 \mathrm{~m}\) lies in a plane perpendicular to a constant magnetic field (see part \(a\) of the drawing). The magnetic field has a magnitude of \(0.65 \mathrm{~T}\) and is directed parallel to the normal of the loop's surface. In a time of \(0.18 \mathrm{~s}\), one-half of the loop is then folded back onto the other half, as indicated in part \(b\) of the drawing. Determine the magnitude of the average emf induced in the loop.

Electric doorbells found in many homes require \(10.0 \mathrm{~V}\) to operate. To obtain this voltage from the standard 120-V supply, a transformer is used. Is a step-up or a stepdown transformer needed, and what is its turns ratio \(N_{\mathrm{s}} / N_{\mathrm{p}}\) ?

A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius \(r=0.20 \mathrm{~m} .\) The normal to the plane of the loop is parallel to a constant magnetic field \(\left(\phi=0^{\circ}\right)\) of magnitude \(0.75 \mathrm{~T}\). What is the change \(\Delta \Phi\) in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?

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