/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Multiple-Concept Example 13 revi... [FREE SOLUTION] | 91Ó°ÊÓ

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Multiple-Concept Example 13 reviews some of the principles used in this problem. Suppose you wish to make a solenoid whose self-inductance is \(1.4 \mathrm{mH}\). The inductor is to have a cross-sectional area of \(1.2 \times 10^{-3} \mathrm{~m}^{2}\) and a length of \(0.052 \mathrm{~m}\). How many turns of wire are needed?

Short Answer

Expert verified
220 turns are needed.

Step by step solution

01

Identify Known Values

We are given the self-inductance \( L = 1.4\, \text{mH} = 1.4 \times 10^{-3} \text{ H}\), the cross-sectional area \( A = 1.2 \times 10^{-3} \text{ m}^2\), and the length of the solenoid \( l = 0.052 \text{ m}\). We need to find the number of turns of wire \( N \).
02

Recall the Formula for Solenoid Inductance

The formula for the self-inductance \( L \) of a solenoid is:\[L = \frac{\mu_0 N^2 A}{l}\]where \( \mu_0 = 4\pi \times 10^{-7} \text{ Tm/A} \) is the permeability of free space.
03

Solve for the Number of Turns

Rearrange the solenoid inductance formula to solve for \( N \):\[N = \sqrt{\frac{L l}{\mu_0 A}}\]
04

Substitute the Given Values

Now, substitute the known values into the formula:\[N = \sqrt{\frac{(1.4 \times 10^{-3}) \times 0.052}{4\pi \times 10^{-7} \times 1.2 \times 10^{-3}}}\]
05

Calculate the Number of Turns

Calculate the expression inside the square root:\[N = \sqrt{\frac{7.28 \times 10^{-5}}{1.50796 \times 10^{-9}}}\]and then complete the calculation:\[N = \sqrt{48285.5} \approx 220\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solenoid
A solenoid is a coil of wire that is typically wound in a tightly packed helix. It is a fundamental component in various electronic devices and circuit designs, utilized for its ability to create a magnetic field when an electric current passes through it. The magnetic field inside a long, tightly wound solenoid is uniform and parallel to the axis of the solenoid, which makes it an excellent tool for converting electrical energy into mechanical work or for generating magnetic fields in laboratory settings.

When designing a solenoid, key parameters include its dimensions—specifically, the cross-sectional area, the length, and the number of turns of the coil. These aspects dictate the solenoid’s inductive properties. Understanding the principles of solenoids is crucial for tasks such as building inductors with specific characteristics, such as self-inductance, which is the ability of the solenoid to induce electromotive force (EMF) in itself when the current through it changes.
Permeability of Free Space
The permeability of free space, often denoted as \( \mu_0 \), is a physical constant that measures the ability of a vacuum to sustain a magnetic field. Its value is approximately \( 4\pi \times 10^{-7} \, \text{Tm/A} \). This constant is critical in calculating the magnetic field generated by electric currents and is an integral part of equations that describe electromagnetic phenomena.

In the context of a solenoid, the permeability of free space appears in the formula for self-inductance \( L \). This ensures that the calculations take into account the effectiveness of the medium (in this case, a vacuum) in allowing magnetic field lines to pass through it. The value of \( \mu_0 \) is crucial for obtaining accurate results in theoretical and practical applications involving electromagnetic fields.
Cross-Sectional Area
The cross-sectional area of a solenoid is a measure of the size of the space through which the solenoid's magnetic field passes. It is typically given in square meters (m²). The cross-sectional area is a critical factor in determining the solenoid's self-inductance. A larger area allows for more magnetic field lines, which increases the inductance, assuming other factors remain constant.

In practical terms, when constructing a solenoid for a specific inductance, the cross-sectional area can be adjusted to meet design requirements. Understanding how cross-sectional area impacts inductance helps in making informed decisions about the dimensions and materials used in constructing electromagnetic devices.
Number of Turns
The number of turns in a solenoid refers to how many times the wire coils around the solenoid's core. It is a crucial parameter because it directly influences the solenoid's inductance. According to the formula \( L = \frac{\mu_0 N^2 A}{l} \), the inductance is proportional to the square of the number of turns. This means even a modest increase in the number of turns can significantly enhance the inductance.

In our calculation, the number of turns requires precise determination to achieve the desired inductance. By rearranging the inductance formula to solve for the number of turns \( N \), one can identify the proper amount of coil needed to match the calculated inductance requirements. Properly calculating the number of turns ensures the solenoid functions efficiently within its intended application.

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Most popular questions from this chapter

In 1996 , NASA performed an experiment called the Tethered Satellite experiment. In this experiment a \(2.0 \times 10^{4}-\mathrm{m}\) length of wire was let out by the space shuttle Atlantis to generate a motional emf. The shuttle had an orbital speed of \(7.6 \times 10^{3} \mathrm{~m} / \mathrm{s},\) and the magnitude of the earth's magnetic field at the location of the wire was \(5.1 \times 10^{-5} \mathrm{~T}\). If the wire had moved perpendicular to the earth's magnetic field, what would have been the motional emf generated between the ends of the wire?

A \(3.0-\mu\) F capacitor has a voltage of 35 V between its plates. What must be the current in a 5.0 -mH inductor, such that the energy stored in the inductor equals the energy stored in the capacitor?

A \(3.0-\mu F\) capacitor has a voltage of \(35 \mathrm{~V}\) between its plates. What must be the current in a 5.0-mH inductor, such that the energy stored in the inductor equals the energy stored in the capacitor?

A circular loop of wire rests on a table. A long, straight wire lies on this loop, directly over its center, as the drawing illustrates. The current \(I\) in the straight wire is decreasing. In what direction is the induced current, if any, in the loop? Give your reasoning.

ssm www The drawing shows a plot of the output emf of a generator as a function of time \(t\). The coil of this device has a cross-sectional area per turn of \(0.020 \mathrm{~m}^{2}\) and contains 150 turns. Find (a) the frequency \(f\) of the generator in hertz, (b) the angular speed \(\omega\) in \(\mathrm{rad} / \mathrm{s}\), and \((\mathrm{c})\) the magnitude of the magnetic field

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