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Review Conceptual Example 7 as background for this problem. A car is traveling to the left, which is the negative direction. The direction of travel remains the same throughout this problem. The car's initial speed is \(27.0 \mathrm{~m} / \mathrm{s},\) and during a 5.0 -s interval, it changes to a final speed of (a) \(29.0 \mathrm{~m} / \mathrm{s}\) and ( b) \(23.0 \mathrm{~m} / \mathrm{s}\). In each case, find the acceleration (magnitude and algebraic sign) and state whether or not the car is decelerating.

Short Answer

Expert verified
In case (a), acceleration is -0.4 m/s², not decelerating. In case (b), acceleration is 0.8 m/s², decelerating.

Step by step solution

01

Understanding the Problem

We need to determine the acceleration of a car moving in the negative direction with initial speed. We will calculate it in two scenarios, where the final speed changes, and identify if the car is decelerating.
02

Identify the Formula

The formula to calculate acceleration is \(a = \frac{{v_f - v_i}}{{t}}\), where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and \(t\) is the time interval.
03

Substitute Values for Case (a)

In this scenario, the initial speed \(v_i = -27.0\) m/s, and the final speed \(v_f = -29.0\) m/s over a time \(t = 5.0\) s. Substitute these values into the formula: \(a = \frac{{-29.0 - (-27.0)}}{{5.0}} = \frac{{-2.0}}{{5.0}} = -0.4\) m/s².
04

Determine Deceleration for Case (a)

Since acceleration is negative and the car is moving in the negative direction, acceleration is increasing the car's speed in that direction (not deceleration).
05

Substitute Values for Case (b)

Here, the initial speed \(v_i = -27.0\) m/s, and the final speed \(v_f = -23.0\) m/s over a time \(t = 5.0\) s. Substitute these values into the formula: \(a = \frac{{-23.0 - (-27.0)}}{{5.0}} = \frac{{4.0}}{{5.0}} = 0.8\) m/s².
06

Determine Deceleration for Case (b)

The positive acceleration indicates the car's speed is decreasing in the negative direction, meaning the car is decelerating.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration
Acceleration refers to how much an object's velocity changes with time. It tells us how quickly something speeds up or slows down. In mathematical terms, acceleration (\(a\)) is described using the formula:
  • \(a = \frac{{v_f - v_i}}{{t}}\)
where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and \(t\) is the time interval over which the change happens. For example, if a car's speed changes from \(-27 \text{ m/s}\) to \(-29 \text{ m/s}\) in \(5\) seconds, the acceleration would be the rate of change in velocity during that time span.

This concept is fundamental in kinematics, a branch of mechanics that describes the motion of objects. Understanding acceleration is critical because it helps us predict how objects will move in the presence of various forces.
Deceleration
Deceleration is just a special case of acceleration. It occurs when an object slows down. In other words, the velocity of the object decreases over time. Despite sounding different, deceleration can still be expressed using the same acceleration formula:
  • \(a = \frac{{v_f - v_i}}{{t}}\)
The only difference is that in deceleration, the value of \(a\) is typically positive when the object is moving in the negative direction, as was the case for our car example when it slowed from \(-27 \text{ m/s}\) to \(-23 \text{ m/s}\).

In this scenario, while the direction of travel (negative direction) remains unchanged, the car is losing speed, hence decelerating. Deceleration occurs whenever the acceleration vector opposes the velocity vector, which reduces the speed.
Velocity
Velocity is a vector quantity that signifies the speed and direction of an object's motion. It is different from speed, which is just a scalar indicating how fast something moves. In kinematics, understanding velocity is crucial because it helps define other concepts like acceleration.

Velocity is represented by \(v\), and when we discuss changes in velocity over time, we are either dealing with acceleration or deceleration. For instance, if a car speeds up from \(-27 \text{ m/s}\) to \(-29 \text{ m/s}\), the negative sign indicates its direction. Velocity, therefore, is not only about the magnitude of speed but also includes the directional component, making it a more complex measure.
  • Positive velocity indicates movement in the positive direction.
  • Negative velocity implies movement in the opposite (usually leftward) direction.
Negative Direction
The negative direction in physics often refers to movement opposite to an established positive direction. In our problem, when the car travels leftward, it is moving in the negative direction. This concept is significant because it affects how we interpret changes in velocity and acceleration.

With movement in the negative direction, any velocity value with a "-" sign indicates movement leftwards. It’s crucial to remember that a negative acceleration (when the object is already moving left) signifies speeding up, whereas positive acceleration in that direction denotes slowing down.
  • A negative velocity means the object is traveling in the negative direction.
  • Negative acceleration implies a decrease in velocity if the object moves in a positive direction or an increase if moving in a negative one.
Understanding the negative direction is key to analyzing motion accurately, especially in exercises involving vectors and opposing forces.

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Most popular questions from this chapter

Before starting this problem, review Multiple-Concept Example \(6 .\) The left ventricle of the heart accelerates blood from rest to a velocity of \(+26 \mathrm{~cm} / \mathrm{s}\). (a) If the displacement of the blood during the acceleration is \(+2.0 \mathrm{~cm}\), determine its acceleration (in \(\mathrm{cm} / \mathrm{s}^{2}\) ). (b) How much time does blood take to reach its final velocity?

Review Interactive Solution 2.49 at before beginning this problem. A woman on a bridge \(75.0 \mathrm{~m}\) high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 7.00 \(\mathrm{m}\) more to travel before passing under the bridge. The stone hits the water \(4.00 \mathrm{~m}\) in front of the raft. Find the speed of the raft.

A wrecking ball is hanging at rest from a crane when suddenly the cable breaks. The time it takes for the ball to fall halfway to the ground is \(1.2 \mathrm{~s}\). Find the time it takes for the ball to fall from rest all the way to the ground.

A ball is dropped from rest from the top of a cliff that is \(24 \mathrm{~m}\) high. From ground level, a second ball is thrown straight upward at the same instant that the first ball is dropped. The initial speed of the second ball is exactly the same as that with which the first ball eventually hits the ground. In the absence of air resistance, the motions of the balls are just the reverse of each other. Determine how far below the top of the cliff the balls cross paths.

In a historical movie, two knights on horseback start from rest \(88.0 \mathrm{~m}\) apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of \(0.300 \mathrm{~m} / \mathrm{s}^{2},\) while Sir Alfred's has a magnitude of \(0.200 \mathrm{~m} / \mathrm{s}^{2}\). Relative to Sir George's starting point, where do the knights collide?

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