/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Review Interactive Solution 2.49... [FREE SOLUTION] | 91Ó°ÊÓ

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Review Interactive Solution 2.49 at before beginning this problem. A woman on a bridge \(75.0 \mathrm{~m}\) high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 7.00 \(\mathrm{m}\) more to travel before passing under the bridge. The stone hits the water \(4.00 \mathrm{~m}\) in front of the raft. Find the speed of the raft.

Short Answer

Expert verified
The speed of the raft is approximately 2.81 m/s.

Step by step solution

01

Analyze the problem situation

We have a stone being dropped from a bridge 75.0 m high just before a raft passes under the bridge. The stone falls vertically, while the raft moves horizontally at a constant speed. The stone hits the water 4.00 m in front of the raft's position when it would have been directly under the point of release.
02

Calculate the fall time for the stone

Let's calculate the time it takes for the stone to hit the water. Using the equation of motion for free fall: \[ s = ut + \frac{1}{2}gt^2 \] where \( s = 75.0 \) m, \( u = 0 \) (initial speed), \( g = 9.8 \) m/s². Solving for \( t \):\[ 75.0 = 0 \cdot t + \frac{1}{2} \cdot 9.8 \cdot t^2 \]\[ 75.0 = 4.9 t^2 \]\[ t^2 = \frac{75.0}{4.9} \approx 15.31 \]\[ t = \sqrt{15.31} \approx 3.91 \, \text{seconds} \]
03

Determine distance covered by the raft during fall

The raft travels 7.00 m to reach directly under the stone's initial position, plus another distance because the stone hits 4.00 m in front of it, totaling 11.00 m. As determined in the previous step, the stone takes about 3.91 seconds to hit the water.
04

Calculate the speed of the raft

Since the raft travels 11.00 meters in the time it takes the stone to fall (3.91 seconds), we can find the speed \( v \) of the raft using:\[ v = \frac{\text{distance}}{\text{time}} = \frac{11.00}{3.91} \approx 2.81 \, \text{m/s} \]
05

Final Result

The speed of the raft is approximately 2.81 meters per second.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that describes the motion of objects without considering the forces that cause this motion. It involves the study of the positions, velocities, and accelerations of objects. In the context of projectile motion, kinematics helps us understand how objects move when they are thrown or fall freely under the influence of gravity.

Kinematics uses mathematical equations to predict future positions and velocities. When an object is moving, we often break down its motion into components – typically vertical and horizontal. This separation allows for simpler calculations, assuming that the only force acting is gravity, which affects the vertical component of motion. By calculating each component separately, it is possible to analyze complex motions, such as that of the stone dropped from a bridge in our example, and evaluate how it and the raft move in relation to everything else around them.
Free Fall
Free fall refers to the motion of an object under the influence of gravitational force alone. When an object is in free fall, it accelerates downwards at a constant rate due to gravity, typically about 9.8 m/s² on Earth. In our problem, the stone dropped from the bridge is a classic example of free fall.

In free fall, the only force acting on the object is gravity. Thus, the object does not encounter air resistance, and the acceleration remains uniform. This simplifies the physics calculations significantly. The stone's initial velocity was zero, as it was simply released and not given any additional force. This allows the use of specific equations of motion to calculate the time it takes for the stone to hit the water from a certain height.
Equations of Motion
Equations of motion are key in analyzing the kinematics of a moving object. These equations are crucial for predicting how an object will move, based on its initial velocity, acceleration, and time of travel. In the case of the stone and the raft, we utilize these equations to determine the duration of the free fall and the resultant speed of the raft.

One commonly used equation is: \[ s = ut + \frac{1}{2}gt^2 \]This formula allows us to find the distance an object will fall over time with an initial velocity \( u \), acceleration \( g \), and time \( t \). In our exercise, the stone's fall time was calculated using this equation, knowing the distance it had to fall and its initial velocity of zero. Understanding and manipulating these equations is essential in solving many types of physics problems.
Displacement
Displacement refers to the change in position of an object and is a vector quantity, meaning it has both magnitude and direction. In simpler terms, it is the straight-line distance between an object’s initial and final positions. Displacement plays an important role in physics problems involving motion, as it helps determine how far an object travels during an event.

In the context of this exercise, the displacement of the stone was the vertical distance from the bridge to the water, which was 75.0 meters. For the raft, however, displacement was calculated as the total horizontal distance, which included both the distance needed for it to reach directly beneath the bridge and the additional distance it moved before the stone hit the water. By accurately calculating displacement, we can better understand an object's path and its interaction with other moving objects, such as the raft moving toward the stone-dropped location.

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Most popular questions from this chapter

Listed below are three pairs of initial and final positions that lie along the \(x\) axis. Using the concept of displacement discussed in Section \(2.1,\) decide which pairs give a positive displacement and which a negative displacement. Explain. $$ \begin{array}{|c|c|c|} \hline & \text { Initial position } x_{0} & \text { Final position } x \\ \hline(\mathrm{a}) & +2.0 \mathrm{~m} & +6.0 \mathrm{~m} \\ \hline(\mathrm{b}) & +6.0 \mathrm{~m} & +2.0 \mathrm{~m} \\ \hline(\mathrm{c}) & -3.0 \mathrm{~m} & +7.0 \mathrm{~m} \\ \hline \end{array} $$ Problem For each of the three pairs of positions listed above, determine the magnitude and direction (positive or negative) of the displacement. Verify that your answers are consistent with those determined in the Concept Question.

Interactive Solution \(\underline{2.31}\) at offers help in modeling this problem. A car is traveling at a constant speed of \(33 \mathrm{~m} / \mathrm{s}\) on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is \(2.5 \mathrm{~km}\) away?

An 18 -year-old runner can complete a \(10.0-\mathrm{km}\) course with an average speed of \(4.39 \mathrm{~m} / \mathrm{s}\). A 50-year-old runner can cover the same distance with an average speed of \(4.27 \mathrm{~m} / \mathrm{s}\). How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?

A whale swims due east for a distance of \(6.9 \mathrm{~km},\) turns around and goes due west for \(1.8 \mathrm{~km},\) and finally turns around again and heads \(3.7 \mathrm{~km}\) due east. (a) What is the total distance traveled by the whale? (b) What are the magnitude and direction of the displacement of the whale?

In 1954 the English runner Roger Bannister broke the four-minute barrier for the mile with a time of 3: 59.4 s \((3\) min and \(59.4 \mathrm{~s}\) ). In 1999 the Moroccan runner Hicham elGuerrouj set a record of 3: 43.13 s for the mile. If these two runners had run in the same race, each running the entire race at the average speed that earned him a place in the record books, el-Guerrouj would have won. By how many meters?

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