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Two very small spheres are initially neutral and separated by a distance of \(0.50 \mathrm{~m}\). Suppose that \(3.0 \times 10^{13}\) electrons are removed from one sphere and placed on the other. (a) What is the magnitude of the electrostatic force that acts on each sphere? (b) Is the force attractive or repulsive? Why?

Short Answer

Expert verified
The force is 0.276 N and is attractive.

Step by step solution

01

Understanding the Problem

We have two small spheres initially neutral, separated by a distance of 0.50 m. We remove electrons from one sphere and transfer them to the other, thereby creating a charge difference between the spheres. We need to find the electrostatic force between them.
02

Calculate Charge on Spheres

When electrons are removed from one sphere, it becomes positively charged, and the other becomes negatively charged. The charge transferred (Q) can be calculated using the charge of one electron (e = -1.6 x 10^{-19} C). Thus, the total charge transferred is \[ Q = n imes e = 3.0 imes 10^{13} imes -1.6 imes 10^{-19} \]. Calculate Q to find the charge on each sphere.
03

Applying Coulomb's Law

Coulomb's Law quantifies the electrostatic force between two charges: \[ F = \frac{k imes |q_1 imes q_2|}{r^2} \]. Here, \( k = 8.99 imes 10^{9} \) N m²/C², \( q_1 \) and \( q_2 \) are the charges found in Step 2, and \( r \) is the distance between the charges (0.50 m). Substitute these values to calculate F.
04

Evaluating the Force Type

After calculating the magnitude using Coulomb's Law, we determine if the force is attractive or repulsive. Since one sphere is positive and the other is negative due to electron transfer, the force will be attractive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is the principle that describes how charged objects interact. Imagine two small spheres that suddenly gain opposite charges; the force between them can be explained using this fundamental law. It states that the electrostatic force (F) between two charged objects is proportional to the product of their charges and inversely proportional to the square of the distance between them.
Coulomb's Law is expressed mathematically as: \[ F = \frac{k \times |q_1 \times q_2|}{r^2} \]where \( k = 8.99 \times 10^9 \) N m²/C² is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges. This relationship highlights how increasing the distance decreases force and vice versa.
In our scenario, using Coulomb's Law allows us to calculate the force acting between two spheres with opposite charges after a transfer of electrons has occurred.
Charge Transfer
Charge transfer is a process that changes the electric charge of an object by moving electrons from one place to another. In our problem, electrons are transferred from one sphere to another. This transaction affects both objects: one becomes positively charged because it loses electrons, and the other becomes negatively charged as it gains electrons.
Consider this process as a sort of balance: removing negatively charged electrons from a neutral object results in a net positive charge, while adding electrons gives a negative charge. This is crucial for understanding how the resulting charges interact with each other according to electrostatic principles.
Calculating the charge involves knowing the number of electrons transferred and the charge of a single electron, \( e = -1.6 \times 10^{-19} \) C, to determine the total charge involved in the process. This helps set the stage for calculating the forces involved.
Electric Charge
Electric charge is a fundamental property of certain particles, such as electrons and protons. It comes in two types: positive and negative. In our example, the two spheres initially have no net charge. Once we transfer electrons, the balance is disturbed.
The concept of electric charge is essential because it is the source of the electrostatic force described by Coulomb's Law. Electrons, carrying a negative charge, can be moved from one object to another, causing a positive charge to remain on the former and a negative charge to accumulate on the latter.
This shift in charge leads to an electrostatic force, either attracting or repelling objects depending on the charges involved. Understanding how charges work is key to analyzing the forces that act between charged objects.
Attractive and Repulsive Forces
An important aspect of electrostatics is the nature of the forces between charges. These forces can either be attractive or repulsive, depending on the types of charges interacting.
When two objects have opposite charges, as in our problem with one sphere becoming positive and the other negative, the force between them is attractive. Oppositely charged objects pull towards one another.
On the other hand, if both spheres had the same charge, either both positive or both negative, the force would be repulsive, pushing the spheres apart.
This distinction between attractive and repulsive forces helps explain behaviors of charged objects in various scenarios, from fundamental atomic interactions to practical applications in electronics.

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Most popular questions from this chapter

Concept Questions Two identical metal spheres have charges of \(q_{1}\) and \(q_{2}\). They are brought together so they touch, and then they are separated. (a) How is the net charge on the two spheres before they touch related to the net charge after they touch? (b) After they touch and are separated, is the charge on each sphere the same? Why? Problem Four identical metal spheres have charges of \(q_{\mathrm{A}}=-8.0 \mu \mathrm{C}, q_{\mathrm{B}}=-2.0 \mu \mathrm{C}\) \(q_{\mathrm{C}}=+5.0 \mu \mathrm{C}\), and \(q_{D}=+12.0 \mu \mathrm{C}\). (a) Two of the spheres are brought together so they touch and then they are separated. Which spheres are they, if the final charge on each of the two is \(+5.0 \mu \mathrm{C} ?(\mathrm{~b})\) In a similar manner, which three spheres are brought together and then separated, if the final charge on each of the three is \(+3.0 \mu \mathrm{C}\) (c) How many electrons would have to be added to one of the spheres in part (b) to make it electrically neutral?

Two charges are located along the \(x\) axis: \(q_{1}=+6.0 \mu \mathrm{C}\) at \(x_{1}=+4.0 \mathrm{~cm}\), and \(q_{2}=+6.0 \mu \mathrm{C}\) at \(x_{2}=-4.0 \mathrm{~cm}\). Two other charges are located on the \(y\) axis: \(q_{3}=+3.0 \mu \mathrm{C}\) at \(y_{3}=+5.0 \mathrm{~cm}\), and \(q_{4}=-8.0 \mu \mathrm{C}\) at \(y_{4}=+7.0 \mathrm{~cm} .\) Find the net electric field (magnitude and direction) at the origin.

A vertical wall \((5.9 \mathrm{~m} \times 2.5 \mathrm{~m})\) in a house faces due east. A uniform electric field has a magnitude of \(150 \mathrm{~N} / \mathrm{C}\). This field is parallel to the ground and points \(35^{\circ}\) north of east. What is the electric flux through the wall?

Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equilateral triangle, as the drawing shows. (a) The charge at any one corner experiences forces from the charges at the other corners. Do the individual forces exerted by the charges have the same or different magnitudes? (b) At which one or more corners does (do) the charge(s) experience a net force that has the greatest magnitude? (c) At which one or more corners does (do) the charge(s) experience a net force that has the smallest magnitude?

A proton and an electron are moving due east in a constant electric field that also points due east. (a) Does each experience an electric force of the same magnitude and direction? (b) What is the direction of the proton's acceleration, and what is the direction of the electron's acceleration? (c) Is the magnitude of the proton's acceleration greater than, less than, or the same as that of the electron's acceleration? Explain your answers.

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