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Two spherical objects are separated by a distance of \(1.80 \times 10^{-3} \mathrm{~m}\). The objects are initially electrically neutral and are very small compared to the distance between them. Each object acquires the same negative charge due to the addition of electrons. As a result, each object experiences an electrostatic force that has a magnitude of \(4.55 \times 10^{-21} \mathrm{~N}\). How many electrons did it take to produce the charge on one of the objects?

Short Answer

Expert verified
Approximately 11 electrons are needed.

Step by step solution

01

Identify Known Values

You've been given several key values in the problem. First, let the magnitude of the force be \( F = 4.55 \times 10^{-21} \text{ N} \). The separation between objects is \( r = 1.80 \times 10^{-3} \text{ m} \).
02

Coulomb's Law

Coulomb's Law calculates the electrostatic force between charges: \( F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \), where \( k = 8.99 \times 10^9 \text{ Nm}^2/ ext{C}^2 \) is the electrostatic constant, and \( q_1 \), \( q_2 \) are charges on the objects. Since the objects have the same charge, we can write \( q_1 = q_2 = q \). Thus, \( F = \frac{k \cdot q^2}{r^2} \).
03

Solve for Charge \( q \)

Rearrange Coulomb's Law to solve for charge \( q \):\[q = \sqrt{\frac{F \cdot r^2}{k}}\]Substitute the given values:\[q = \sqrt{\frac{(4.55 \times 10^{-21} \text{ N}) \cdot (1.80 \times 10^{-3} \text{ m})^2}{8.99 \times 10^9 \text{ Nm}^2/\text{C}^2}}.\]Calculate to find \( q \).
04

Calculate Number of Electrons

The charge of one electron is \( e = 1.60 \times 10^{-19} \text{ C} \). To find the number of electrons \( n \) that produce charge \( q \), use:\[n = \frac{q}{e}\]Divide the computed charge \( q \) from Step 3 by \( e \) to find \( n \).
05

Compute the Final Result

Complete the calculation for \( n \) using the determined value of \( q \). Round to the nearest whole number for actual electron count.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is critical to understanding electrostatics, as it describes the force between two point charges. It is mathematically represented by the formula: \( F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \). Here, \( F \) is the electrostatic force, \( k \) is Coulomb's constant (approximately \( 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \)), \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges.
This formula tells us that the force is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

Key points about Coulomb's Law include:
  • The force can be either attractive or repulsive, depending on the type of charges involved (positive or negative).
  • It acts along the line joining the charges, making it a central force.
  • The principle behind the law is applicable universally in electrostatics for point charges and charges on spherical objects.
Electrostatic Force
The electrostatic force is a fundamental aspect of the study of electronics and electrostatics. It is the result of charges interacting with each other. This force can be easily understood using Coulomb's Law, as it quantitatively defines how this force operates.
The magnitude of the electrostatic force depends on:
  • The amount of each charge involved—the larger the charge, the greater the force.
  • The distance between the two charges—shorter distances produce stronger forces, as the force magnitude reduces with the square of the distance.
This force is responsible for various phenomena in our daily lives, such as the attraction of hair to a charged comb.
In many applications, this force is harnessed to achieve technological advancements, including the design of capacitors and other electronic components.
Electric Charge
Electric charge is a basic property of matter that causes it to experience a force in an electric field. An understanding of electric charge is crucial, as it is one of the most fundamental building blocks in the study of physics and electronics.
The basic points to remember about electric charge include:
  • Charges come in two types: positive and negative.
  • Like charges repel each other, whereas opposite charges attract each other.
  • Measured in Coulombs (C), electric charge quantifies the amount of electricity carried by a particle.
Electric charges create electric fields, space around the particles where electric forces can be exerted. This concept is extremely important when analyzing circuits, conductors, and insulators in physics and engineering.
Elementary Charge
The elementary charge is defined as the smallest unit of electric charge that we know. It is the charge carried by a single proton, which is positive, or by a single electron, which is negative.
The value of the elementary charge is \( e = 1.60 \times 10^{-19} \, \text{C} \). This value is fundamental to almost all equations and calculations involving electrostatics.
Key characteristics of elementary charge include:
  • It is a fixed value, all charges are integer multiples of \( e \).
  • It helps in quantifying the charge of electrons and protons, the building particles of atoms.
When calculating the number of electrons needed to form a specific charge, use the formula: \( n = \frac{q}{e} \), where \( q \) represents the total charge. Hence, understanding the elementary charge is pivotal to solving problems related to electricity and magnetism.

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Most popular questions from this chapter

Interactive Solution \(18.37\) at provides a model for problems of this kind. A small object has a mass of \(3.0 \times 10^{-3} \mathrm{~kg}\) and a charge of \(-34 \mu \mathrm{C}\). It is placed at a certain spot where there is an electric field. When released, the object experiences an acceleration of \(2.5 \times 10^{3} \mathrm{~m} / \mathrm{s}^{2}\) in the direction of the \(+x\) axis. Determine the magnitude and direction of the electric field.

A proton is moving parallel to a uniform electric field. The electric field accelerates the proton and thereby increases its linear momentum to \(5.0 \times 10^{-23} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\) from \(1.5 \times 10^{-23} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\) in a time of \(6.3 \times 10^{-6} \mathrm{~s}\). What is the magnitude of the electric field?

Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. How would you determine the magnitude and direction of the electric field if the object were (a) positively charged and (b) negatively charged?

Multiple-Concept Example 3 illustrates several of the concepts used in this problem. A single electron orbits a lithium nucleus that contains three protons \((+3 e)\). The radius of the orbit is \(1.76 \times 10^{-11} \mathrm{~m}\). Determine the kinetic energy of the electron.

The drawing shows a positive point charge \(+q_{1}\), a second point charge \(q_{2}\) that may be positive or negative, and a spot labeled \(P\), all on the same straight line. The distance \(d\) between the two charges is the same as the distance between \(q_{1}\) and the point \(P\). With \(q_{2}\) present, the magnitude of the net electric field at \(P\) is twice what it is when \(q_{1}\) is present alone. (a) When the second charge is positive, is its magnitude smaller than, equal to, or greater than the magnitude of \(q_{1}\) ? Explain your reasoning. (b) When the second charge is negative, is its magnitude smaller than, equal to, or greater than that in question (a)? Account for your answer.

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