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A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1250 Hz. The bird-watcher, however, hears a frequency of \(1290 \mathrm{~Hz}\). What is the speed of the bird, expressed as a percentage of the speed of sound?

Short Answer

Expert verified
The speed of the bird is 3.2% of the speed of sound.

Step by step solution

01

Understand the Doppler Effect Formula

The Doppler Effect formula for sound frequency is given by \( f' = \frac{f}{1 - \frac{v}{v_s}} \), where \( f' \) is the observed frequency (1290 Hz), \( f \) is the source frequency (1250 Hz), \( v \) is the speed of the source (the bird), and \( v_s \) is the speed of sound in air.
02

Substitute Given Values into the Formula

Insert the given frequencies into the formula: \( 1290 = \frac{1250}{1 - \frac{v}{v_s}} \). We need to solve for \( \frac{v}{v_s} \), which represents the speed of the bird as a percentage of the speed of sound.
03

Solve the Equation for \( \frac{v}{v_s} \)

First, rearrange the equation: \( 1 - \frac{v}{v_s} = \frac{1250}{1290} \). Then solve for \( \frac{v}{v_s} \): \( \frac{v}{v_s} = 1 - \frac{1250}{1290} \).
04

Calculate the Numerical Value

Calculate \( \frac{1250}{1290} \) to get approximately \( 0.968 \). Then, \( \frac{v}{v_s} = 1 - 0.968 = 0.032 \). Thus, the speed of the bird is 3.2% of the speed of sound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency
Frequency is a fundamental concept when discussing sound waves and the Doppler Effect. It represents the number of sound wave cycles that pass a particular point each second. The unit of frequency is Hertz (Hz). In the context of our bird-watcher problem, frequency is crucial because the changing frequency of sound helps us understand how objects are moving relative to each other.
When a source of sound, like our flying bird, moves toward a stationary observer, the sound waves get compressed. This
  • Increases the number of waves reaching the observer.
  • Results in a higher observed frequency.
  • Explains why the bird-watcher hears a frequency of 1290 Hz instead of the emitted 1250 Hz by the bird.
The Doppler Effect formula helps us calculate the change in frequency when the source or observer is moving. Understanding frequency's role allows us to predict and analyze such changes accurately.
Sound Waves
Sound waves are mechanical waves that travel through a medium such as air, water, or solids. They are created by vibrating objects and are characterized by compressions and rarefactions in the medium they travel through. In our scenario, the bird emits sound waves as it flies, which are detected by the bird-watcher on the ground.
Sound waves carry energy and information. Here's how they work in the context of the Doppler Effect:
  • Sound is perceived due to vibrating molecules set in motion by the emitter, in this situation, the bird.
  • The frequency of these waves is altered when the source or observer is moving, leading to changes in the pitch.
  • The bird moving toward the observer causes the sound waves to reach him more frequently, explaining why he perceives a higher frequency than emitted.
Understanding sound waves' properties helps deepen our comprehension of phenomena such as the Doppler Effect and its impact on perceived frequencies.
Speed of Sound
The speed of sound is the rate at which sound waves travel through a medium. It varies based on factors such as temperature, medium, and atmospheric pressure. In air at sea level and typical room temperature, sound travels at approximately 343 meters per second.
The Doppler Effect equation uses the speed of sound to calculate how the frequency of waves changes when the source is in motion.
  • In our exercis, the bird's speed is compared to the speed of sound.
  • The calculated value tells us how fast the bird is flying relative to this constant speed.
  • Knowing the speed of sound helps us determine how factors such as temperature or medium can affect sound waves.
By understanding the speed of sound, we can calculate how fast an object must move to cause significant frequency changes, which is key to solving Doppler Effect problems.
Motion
Motion is all about the change in position of an object over time. In the context of the Doppler Effect, the movement of the sound source or the observer introduces apparent changes in the frequency of the sound.
  • The bird is moving towards the stationary observer, causing a shift in the observed frequency.
  • This motion is directly linked to the change from the emitted frequency to the one the observer perceives.
  • Understanding motion allows us to use the Doppler Effect equations effectively and determine the relative speed.
The Doppler Effect demonstrates how motion can alter perception, turning motion-based changes into quantifiable data, like determining the bird's speed relative to the speed of sound.

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Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticeable, but upon reaching shore, they can rise up to the astonishing height of a six-story building. One tsunami, generated off the Aleutian islands in Alaska, had a wavelength of \(750 \mathrm{~km}\) and traveled a distance of \(3700 \mathrm{~km}\) in \(5.3 \mathrm{~h}\). (a) What was the speed (in \(\mathrm{m} / \mathrm{s}\) ) of the wave? For reference, the speed of a 747 jetliner is about \(250 \mathrm{~m} / \mathrm{s}\). Find the wave's (b) frequency and (c) period.

Concept Questions Multiple-Concept 11 provides a model for solving this type of problem. A wireless transmitting microphone is mounted on a small platform, which can roll down an incline, away from a speaker that is mounted at the top of the incline. The speaker broadcasts a fixed-frequency tone. (a) The platform is positioned in front of the speaker and released from rest. Describe how the velocity of the platform changes and why. (b) How is the changing velocity related to the acceleration of the platform? (c) Describe how the frequency detected by the microphone changes. Explain why the frequency changes as you have described. (d) Which equation given in the chapter applies to this situation? Justify your answer. Problem The speaker broadcasts a tone that has a frequency of \(1.000 \times 10^{4} \mathrm{~Hz}\), and the speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). At a time of \(1.5 \mathrm{~s}\) following the release of the platform, the microphone detects a frequency of \(9939 \mathrm{~Hz}\). At a time of \(3.5 \mathrm{~s}\) following the release of the platform, the microphone detects a frequency of \(9857 \mathrm{~Hz}\). What is the acceleration (assumed constant) of the platform?

Concept Questions The table shows three situations in which the Doppler effect may arise. The first two columns indicate the velocities of the sound source and the observer, where the length of each arrow is proportional to the speed. For each situation, fill in the empty columns by deciding whether the wavelength of the sound and the frequency heard by the observer increase, decrease, or remain the same compared to the case when there is no Doppler effect. Provide a reason for each answer. $$ \begin{array}{|l|c|c|c|c|} \hline & \begin{array}{c} \text { Velocity of Sound } \\ \text { Source (Toward the } \\ \text { Observer) } \end{array} & \begin{array}{c} \text { Velocity of } \\ \text { Observer (Toward } \\ \text { the Source) } \end{array} & \text { Wavelength } & \begin{array}{c} \text { Frequency Heard by } \\ \text { Observer } \end{array} \\ \hline \text { (a) } & 0 \mathrm{~m} / \mathrm{s} & 0 \mathrm{~m} / \mathrm{s} & & \\ \hline \text { (b) } & \rightarrow & 0 \mathrm{~m} / \mathrm{s} & & \\ \hline \text { (c) } & \rightarrow & \leftarrow & & \\ \hline \end{array} $$ Problem The siren on an ambulance is emitting a sound whose frequency is \(2450 \mathrm{~Hz}\). The speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). (a) If the ambulance is stationary and you (the "observer") are sitting in a parked car, what is the wavelength of the sound and the frequency heard by you? (b) Suppose the ambulance is moving toward you at a speed of \(26.8 \mathrm{~m} / \mathrm{s}\). Determine the wavelength of the sound and the frequency heard by you. (c) If the ambulance is moving toward you at a speed of \(26.8 \mathrm{~m} / \mathrm{s}\) and you are moving toward it at a speed of \(14.0 \mathrm{~m} / \mathrm{s}\), find the wavelength of the sound and the frequency that you hear. Be sure that your answers are consistent with your answers to the Concept Questions.

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