/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Tsunamis are fast-moving waves o... [FREE SOLUTION] | 91Ó°ÊÓ

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Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticeable, but upon reaching shore, they can rise up to the astonishing height of a six-story building. One tsunami, generated off the Aleutian islands in Alaska, had a wavelength of \(750 \mathrm{~km}\) and traveled a distance of \(3700 \mathrm{~km}\) in \(5.3 \mathrm{~h}\). (a) What was the speed (in \(\mathrm{m} / \mathrm{s}\) ) of the wave? For reference, the speed of a 747 jetliner is about \(250 \mathrm{~m} / \mathrm{s}\). Find the wave's (b) frequency and (c) period.

Short Answer

Expert verified
The speed of the wave is 193.91 m/s, its frequency is 2.59 x 10^-4 Hz, and its period is approximately 3860 seconds.

Step by step solution

01

Convert Given Units

The distance traveled by the wave is given as \(3700 \mathrm{~km}\) and the time taken is \(5.3 \mathrm{~h}\). First, convert these units to meters and seconds respectively. \(3700 \mathrm{~km} = 3700 \times 1000 = 3,700,000\) meters and \(5.3 \mathrm{~h} = 5.3 \times 3600 = 19080\) seconds.
02

Calculate Speed of the Wave

The speed \(v\) of the wave can be calculated using the formula \(v = \frac{\text{distance}}{\text{time}}\). Substitute the converted values: \(v = \frac{3,700,000\, \mathrm{m}}{19080\, \mathrm{s}} = 193.91\, \mathrm{m/s}\).
03

Calculate Frequency of the Wave

The frequency \( f \) can be found by using the formula \( f = \frac{v}{\lambda} \), where \( \lambda \) is the wavelength in meters. We convert the given wavelength \(750 \mathrm{~km}\) to meters: \(750 \times 1000 = 750,000\) meters. Then, \( f = \frac{193.91\, \mathrm{m/s}}{750,000\, \mathrm{m}} = 2.59 \times 10^{-4}\, \mathrm{Hz}.\)
04

Calculate Period of the Wave

The period \( T \) of the wave is the inverse of frequency: \( T = \frac{1}{f} \). Using the frequency calculated in Step 3, \( T = \frac{1}{2.59 \times 10^{-4}} \approx 3860\, \mathrm{s}.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Speed
Wave speed is a key concept when analyzing the motion of waves, such as those of a tsunami. This is the rate at which the wave travels through the water. Mathematically, wave speed \( v \) can be computed using the formula \( v = \frac{\text{distance}}{\text{time}} \). In the example of a tsunami traveling 3700 kilometers in 5.3 hours, we first need to convert these measurements into compatible units for speed calculation - meters and seconds. This conversion is crucial since our final result needs to be in meters per second \( \text{m/s} \).
By converting, we find 3700 km equals 3,700,000 meters, and 5.3 hours translates to 19080 seconds. Plugging these into the wave speed formula gives us \( v = \frac{3,700,000\,\text{m}}{19080\,\text{s}} \), resulting in a wave speed of approximately 193.91 \( \text{m/s} \).
This speed is comparable to some of the fastest modes of transport and is particularly significant given the destructive power of tsunamis when they reach shore.
Wave Frequency
The frequency of a wave is another important concept. It defines how many wave cycles pass a point in a given time period, typically one second. Let's delve deeper into understanding wave frequency. It is inversely related to the wave period and is measured in Hertz (Hz), where 1 Hz equals one cycle per second. In our context, it is calculated using \( f = \frac{v}{\lambda} \), where \( v \) is the wave speed and \( \lambda \) the wavelength.
First, we ensure the wavelength is in the correct unit. Given as 750 km, it converts to 750,000 meters. Substituting into the frequency formula: \( f = \frac{193.91\,\text{m/s}}{750,000\,\text{m}} \), we get a frequency of approximately \( 2.59 \times 10^{-4}\,\text{Hz} \).
This low frequency reflects the long distance between successive wave peaks in a tsunami, contrasting with other common wave types, such as sound or light waves, which have a much higher frequency.
Wave Period
The wave period is a key measure of wave behavior, especially in phenomena like tsunamis. It represents the time it takes for one complete wave cycle to pass a point, and is the mathematical inverse of frequency. The relationship is expressed by \( T = \frac{1}{f} \), where \( T \) is the period and \( f \) is frequency.
Using the calculated frequency of \( 2.59 \times 10^{-4} \) from the prior section, we find \( T = \frac{1}{2.59 \times 10^{-4}} \approx 3860 \) seconds. This implies that about every 3860 seconds, or slightly over an hour, a full wave cycle occurs at a stationary point.
Understanding the wave period helps in disaster readiness planning, as it indicates how often waves strike, which is crucial for predicting impact sequences during tsunamis.
Unit Conversion in Physics
Unit conversion is a foundational step in solving physics problems, allowing us to work within a consistent measurement system. By converting units, we ensure calculations are accurate and comparable, especially when the problem's data is given in diverse units as seen in our tsunami example.
For any physics-related computation, it's crucial to convert all quantities into a coherent set of units, typically meters, kilograms, and seconds (MKS system).
  • Kilometers are converted to meters by multiplying by 1000.
  • Hours are converted to seconds by multiplying by 3600.
In the tsunami exercise, converting 3700 km to 3,700,000 meters and 5.3 hours to 19080 seconds were essential steps.
These unit conversions are not only about ensuring consistency; they also serve to prevent misinterpretation of scales and improve the precision of our problem-solving.

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Most popular questions from this chapter

The mass of a string is \(5.0 \times 10^{-3} \mathrm{~kg}\), and it is stretched so that the tension in it is \(180 \mathrm{~N}\). A transverse wave traveling on this string has a frequency of \(260 \mathrm{~Hz}\) and a wavelength of \(0.60 \mathrm{~m}\). What is the length of the string?

Argon (molecular mass \(=39.9 \mathrm{u}\) ) is a monatomic gas. As suming that it behaves like an ideal gas at \(298 \mathrm{~K}(\gamma=1.67),\) find (a) the rms speed of argon atoms and (b) the speed of sound in argon.

Two wires are parallel, and one is directly above the other. Each has a length of \(50.0 \mathrm{~m}\) and a mass per unit length of \(0.020 \mathrm{~kg} / \mathrm{m}\). However, the tension in wire \(\mathrm{A}\) is \(6.00 \times 10^{2} \mathrm{~N}\), and the tension in wire \(\mathrm{B}\) is \(3.00 \times 10^{2} \mathrm{~N}\). Transverse wave pulses are generated simultaneously, one at the left end of wire \(A\) and one at the right end of wire B. The pulses travel toward each other. How much time does it take until the pulses pass each other?

Review Interactive Solution \(\underline{16.55}\) at for one approach to this problem. A dish of lasagna is being heated in a microwave oven. The effective area of the lasagna that is exposed to the microwaves is \(2.2 \times 10^{-2} \mathrm{~m}^{2}\). The mass of the lasagna is \(0.35 \mathrm{~kg},\) and its specific heat capacity is \(3200 \mathrm{~J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right)\). The temperature rises by \(72 \mathrm{C}^{\circ}\) in 8.0 minutes. What is the intensity of the microwaves in the oven?

A wave has the following properties: amplitude \(=0.37 \mathrm{~m}\), period \(=0.77 \mathrm{~s}\), wave speed \(=12 \mathrm{~m} / \mathrm{s} .\) The wave is traveling in the \(-x\) direction. What is the mathematical expression (similar to Equation 16.3 or 16.4 ) for the wave?

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