/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A duck is floating on a lake wit... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A duck is floating on a lake with \(25 \%\) of its volume beneath the water. What is the average density of the duck?

Short Answer

Expert verified
The average density of the duck is \(250 \text{ kg/m}^3\).

Step by step solution

01

Understanding the Problem

The duck is floating, which indicates it is in equilibrium. This means that the upward buoyant force equals the downward gravitational force. We need to find the average density of the duck given that 25% of its volume is submerged.
02

Applying the Principle of Flotation

According to the principle of flotation, the buoyant force equals the weight of the water displaced by the submerged volume of the duck. This is expressed as:\[ V_{sub} \cdot \rho_{water} \cdot g = V_{total} \cdot \rho_{duck} \cdot g \]Where \( V_{sub} \) is the submerged volume of the duck, \( \rho_{water} \) is the density of water, \( V_{total} \) is the total volume of the duck, and \( \rho_{duck} \) is the duck's density.
03

Relating Submerged Volume to Total Volume

Given that 25% of the duck's volume is submerged, we have:\[ V_{sub} = 0.25 \times V_{total} \]
04

Solving for the Duck's Density

Substituting \( V_{sub} = 0.25 \times V_{total} \) into the flotation equation gives:\[ 0.25 \cdot V_{total} \cdot \rho_{water} \cdot g = V_{total} \cdot \rho_{duck} \cdot g \]Canceling \( V_{total} \) and \( g \) from both sides, we get:\[ 0.25 \cdot \rho_{water} = \rho_{duck} \]
05

Calculating the Average Density of the Duck

The density of water is approximately \( 1000 \text{ kg/m}^3 \). Using this:\[ \rho_{duck} = 0.25 \times 1000 \]\[ \rho_{duck} = 250 \text{ kg/m}^3 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a measure of how much mass is contained in a given volume. It is crucial for understanding why objects float or sink. The formula for density is given by \[\rho = \frac{m}{V}\]where \(\rho\) is the density, \(m\) is the mass, and \(V\) is the volume. An object's density determines whether it will float or sink in a fluid.
If the density of the object is less than the fluid's density, it will float; otherwise, it will sink.
For our duck, the average density was calculated as \( 250 \text{ kg/m}^3 \), which is less than that of water, allowing it to float.
Flotation Principle
The flotation principle is fundamental in understanding buoyancy, the upward force that allows objects to float. According to this principle: - The buoyant force acting on a submerged object is equal to the weight of the fluid displaced by the object.
- For an object floating on a fluid, this buoyant force equals the gravitational force pulling the object downward.
The duck floats because the buoyant force from the water balances the gravitational force. This principle is expressed mathematically to find the density of the duck by calculating the weight of the displaced water, providing a key clue in understanding flotation dynamics.
Submerged Volume
In buoyancy problems, the submerged volume of an object is the volume below the surface of the fluid. For our floating duck, 25% of its total volume is submerged.
This part of the volume is crucial as it determines how much fluid the object displaces, which, in turn, affects the buoyant force. The submerged volume is connected to density through the equation:\[V_{sub} = 0.25 \times V_{total}\]This tells us that only a fraction of the duck's body displaces water, directly linking to its ability to float. The more an object is submerged, the higher its density relative to the fluid.
Equilibrium in Fluids
Equilibrium in fluids refers to a state where forces acting on an object are balanced. Two primary forces generally act on floating bodies: - Gravitational force pulling downward - Buoyant force pushing upward When these two forces are equal, the object is in equilibrium, neither sinking nor rising in the fluid.
For the floating duck, equilibrium is reached when the downward gravitational force matches the upward buoyant force. This balance is what keeps the duck afloat, and it's tied directly to the density and submerged volume.
Understanding equilibrium helps clarify why some objects, despite varying sizes and shapes, can float on water.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Interactive LearningWare 11.2 at reviews the approach taken in problems such as this one. A small crack occurs at the base of a 15.0 -m-high dam. The effective crack area through which water leaves is \(1.30 \times 10^{-3} \mathrm{~m}^{2}\). (a) Ignoring viscous losses, what is the speed of water flowing through the crack? (b) How many cubic meters of water per second leave the dam?

The ice on a lake is \(0.010 \mathrm{~m}\) thick. The lake is circular, with a radius of \(480 \mathrm{~m}\). Find the mass of the ice.

Interactive Solution \(11.73\) at illustrates a model for solving this problem. A pressure difference of \(1.8 \times 10^{3} \mathrm{~Pa}\) is needed to drive water \(\left(\eta=1.0 \times 10^{-3} \mathrm{~Pa} \cdot \mathrm{s}\right)\) through a pipe whose radius is \(5.1 \times 10^{-3} \mathrm{~m}\). The volume flow rate of the water is \(2.8 \times 10^{-4} \mathrm{~m}^{3} / \mathrm{s}\). What is the length of the pipe?

A room has a volume of \(120 \mathrm{~m}^{3}\). An air-conditioning system is to replace the air in this room every twenty minutes, using ducts that have a square cross section. Assuming that air can be treated as an incompressible fluid, find the length of a side of the square if the air speed within the ducts is (a) \(3.0 \mathrm{~m} / \mathrm{s}\) and \((\mathrm{b}) 5.0 \mathrm{~m} / \mathrm{s}\).

Interactive LearningWare 11.1 at provides a review of the concepts that are important in this problem. A spring is attached to the bottom of an empty swimming pool, with the axis of the spring oriented vertically. An \(8.00-\mathrm{kg}\) block of wood \(\left(\rho=840 \mathrm{~kg} / \mathrm{m}^{3}\right)\) is fixed to the top of the spring and compresses it. Then the pool is filled with water, completely covering the block. The spring is now observed to be stretched twice as much as it had been compressed. Determine the percentage of the block's total volume that is hollow. Ignore any air in the hollow space.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.