/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 Interactive Solution \(11.73\) a... [FREE SOLUTION] | 91Ó°ÊÓ

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Interactive Solution \(11.73\) at illustrates a model for solving this problem. A pressure difference of \(1.8 \times 10^{3} \mathrm{~Pa}\) is needed to drive water \(\left(\eta=1.0 \times 10^{-3} \mathrm{~Pa} \cdot \mathrm{s}\right)\) through a pipe whose radius is \(5.1 \times 10^{-3} \mathrm{~m}\). The volume flow rate of the water is \(2.8 \times 10^{-4} \mathrm{~m}^{3} / \mathrm{s}\). What is the length of the pipe?

Short Answer

Expert verified
The length of the pipe is approximately 0.107 m.

Step by step solution

01

Understand the Problem

We need to find the length of the pipe given the pressure difference, the viscosity of the fluid, the radius of the pipe, and the volume flow rate of the water.
02

Use Poiseuille's Law

Poiseuille's Law relates the flow rate (Q), the pressure difference (abla P), the radius (r), the viscosity (eta), and the length (L) of the pipe:\[ Q = \frac{{\pi r^4 abla P}}{{8 \eta L}} \]
03

Rearrange the Formula to Solve for Length

To find the length (L), rearrange the formula:\[ L = \frac{{\pi r^4 abla P}}{{8 \eta Q}} \]
04

Plug in the Given Values

Substitute the given values into the equation:- Pressure difference \( abla P = 1.8 \times 10^{3} \ \mathrm{Pa} \)- Radius \( r = 5.1 \times 10^{-3} \ \mathrm{m} \)- Viscosity \( \eta = 1.0 \times 10^{-3} \ \mathrm{Pa \cdot s} \)- Flow rate \( Q = 2.8 \times 10^{-4} \ \mathrm{m}^{3}/s \)\[ L = \frac{{\pi \cdot (5.1 \times 10^{-3})^4 \cdot 1.8 \times 10^{3}}}{{8 \cdot 1.0 \times 10^{-3} \cdot 2.8 \times 10^{-4}}} \]
05

Calculate the Length

Calculate the value:\[ L = \frac{{\pi \cdot 6.7321 \times 10^{-14} \cdot 1.8 \times 10^{3}}}{{2.24 \times 10^{-6}}} \]\[ L \approx 0.107 \ \mathrm{m} \]
06

Conclusion

The length of the pipe is approximately \(0.107 \ \mathrm{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Poiseuille's Law
In fluid dynamics, Poiseuille's Law is a key principle that describes how viscous fluid flows through a cylindrical pipe. The law provides a relationship between various parameters that affect the flow rate of the fluid. It is expressed mathematically by the equation:
  • \[ Q = \frac{{\pi r^4 \Delta P}}{{8 \eta L}} \]
Where:
  • \( Q \) is the volumetric flow rate, or how much fluid passes through the pipe per unit of time.
  • \( \Delta P \) represents the pressure difference between the ends of the pipe.
  • \( r \) is the radius of the pipe.
  • \( \eta \) stands for the fluid's viscosity.
  • \( L \) indicates the length of the pipe.
Poiseuille's Law is particularly relevant in circumstances where the fluid flow is laminar, meaning it flows in parallel layers without any disruption between them. Understanding this law provides insight into the control and efficiency of fluid delivery in systems such as pipelines, vascular networks in biological organisms, or even simple household plumbing.
Viscosity
Viscosity is a measure of a fluid's resistance to deformation or flow. In simpler terms, it describes how "thick" or "sticky" a fluid is. For example, honey has a higher viscosity compared to water. In the context of Poiseuille's Law, viscosity is a crucial factor because it influences how easily a fluid can move through a pipe.
  • Higher viscosity means more resistance, which slows down the flow rate.
  • Conversely, lower viscosity fluids flow more freely.
When we look at the formula from Poiseuille's Law, the viscosity \((\eta)\) is in the denominator, showing that as viscosity increases, the flow rate \((Q)\) decreases, assuming all other factors are constant. This relationship helps in designing systems where fluid flow needs to be controlled or predicted, such as medical devices or industrial applications where fluid consistency cannot vary significantly.
Pressure Difference
Pressure difference, denoted as \( \Delta P \), is a fundamental concept in fluid dynamics, influencing the movement of fluids through Pipelines. It refers to the difference in pressure between two points in a pipe.
  • A greater pressure difference typically accelerates fluid flow, propelling it from the high-pressure region to the low-pressure region.
  • On the contrary, a smaller pressure difference results in slower flow rates.
In Poiseuille's Law, pressure difference is directly proportional to the flow rate \((Q)\), assuming other variables such as viscosity \((\eta)\), pipe length \((L)\), and pipe radius \((r)\) remain constant. This means that when the pressure difference increases, the flow rate tends to increase as well. Engineers and scientists use this principle to manipulate and predict fluid movement in a range of applications, from natural systems to complex industrial processes.
Flow Rate
Flow rate in fluid dynamics is the volume of fluid that moves through a specified area in a given time frame. It is often expressed in cubic meters per second \((\mathrm{m}^3/\mathrm{s})\).
  • Flow rate provides valuable information about the efficiency and effectiveness of fluid systems, such as water supply networks or fuel pipelines.
  • It helps in determining the optimal design and operation conditions for systems requiring precise fluid management.
Poiseuille's Law illustrates how the flow rate \((Q)\) is a function of several factors: pipe radius, fluid viscosity, pressure difference across the pipe's length, and the pipe's length itself. By understanding how these variables influence the flow rate, engineers can adjust these parameters to meet specific requirements, whether to increase transportation efficiency or develop consistent delivery mechanisms for sensitive fluids.

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Most popular questions from this chapter

A blood transfusion is being set up in an emergency room for an accident victim. Blood has a density of \(1060 \mathrm{~kg} / \mathrm{m}^{3}\) and a viscosity of \(4.0 \times 10^{-3} \mathrm{~Pa} \cdot \mathrm{s}\). The needle being used has a length of \(3.0 \mathrm{~cm}\) and an inner radius of \(0.25 \mathrm{~mm} .\) The doctor wishes to use a volume flow rate through the needle of \(4.5 \times 10^{-8} \mathrm{~m}^{3} / \mathrm{s}\). What is the distance \(h\) above the victim's arm where the level of the blood in the transfusion bottle should be located? As an approximation, assume that the level of the blood in the transfusion bottle and the point where the needle enters the vein in the arm have the same pressure of one atmosphere. (In reality, the pressure in the vein is slightly above atmospheric pressure.)

The vertical surface of a reservoir dam that is in contact with the water is \(120 \mathrm{~m}\) wide and \(12 \mathrm{~m}\) high. The air pressure is one atmosphere. Find the magnitude of the total force acting on this surface in a completely filled reservoir. (Hint: The pressure varies linearly with depth, so you must use an average pressure.)

A meat baster consists of a squeeze bulb attached to a plastic tube. When the bulb is squeezed and released, with the open end of the tube under the surface of the basting sauce, the sauce rises in the tube to a distance \(h\), as the drawing shows. It can then be squirted over the meat. (a) Is the absolute pressure in the bulb in the drawing greater than or less than atmospheric pressure? (b) In a second trial, the distance \(h\) is somewhat less than it is in the drawing. Is the absolute pressure in the bulb in the second trial greater or smaller than in the case shown in the drawing? Explain your answers. Using \(1.013 \times 10^{5} \mathrm{~Pa}\) for the atmospheric pressure and \(1200 \mathrm{~kg} / \mathrm{m}^{3}\) for the density of the sauce, find the absolute pressure in the bulb when the distance \(h\) is (a) \(0.15\) \(\mathrm{m}\) and (b) \(0.10 \mathrm{~m}\). Verify that your answers are consistent with your answers to the Concept Questions.

In the human body, blood vessels can dilate, or increase their radii, in response to various stimuli, so that the volume flow rate of the blood increases. Assume that the pressure at either end of a blood vessel, the length of the vessel, and the viscosity of the blood remain the same, and determine the factor \(R_{\text {dilated }} / R_{\text {normal }}\) by which the radius of a vessel must change in order to double the volume flow rate of the blood through the vessel.

One of the concrete pillars that support a house is \(2.2 \mathrm{~m}\) tall and has a radius of \(0.50 \mathrm{~m}\). The density of concrete is about \(2.2 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\). Find the weight of this pillar in pounds \((1 \mathrm{~N}=0.2248 \mathrm{lb})\).

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