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Two air-track carts move toward one another on an air track. Cart 1 has a mass of \(0.35 \mathrm{kg}\) and a speed of \(1.2 \mathrm{m} / \mathrm{s}\). Cart 2 has a mass of \(0.61 \mathrm{kg}\). (a) What speed must cart 2 have if the total momentum of the system is to be zero? (b) Since the momentum of the system is zero, does it follow that the kinetic energy of the system is also zero? (c) Verify your answer to part (b) by calculating the system's kinetic energy.

Short Answer

Expert verified
(a) Cart 2 speed = -0.69 m/s. (b) No, kinetic energy is not zero. (c) Total kinetic energy = 0.397 J.

Step by step solution

01

Understand Momentum Conservation

Total momentum of the system is zero, hence the momentum of cart 1 must be equal in magnitude and opposite in direction to the momentum of cart 2.
02

Write the Momentum Equation

The momentum of an object is given by the product of its mass and velocity. Thus, for cart 1, we have \( p_1 = m_1 \cdot v_1 = 0.35 \, \text{kg} \times 1.2 \, \text{m/s} = 0.42 \, \text{kg} \cdot \text{m/s} \). For cart 2, \( p_2 = -p_1 \) to make the total momentum zero.
03

Solve for Cart 2's Velocity

The equation for cart 2 becomes \( 0.61 \, \text{kg} \cdot v_2 = -0.42 \, \text{kg} \cdot \text{m/s} \). Solving for \( v_2 \), we have \( v_2 = \frac{-0.42 \, \text{kg} \cdot \text{m/s}}{0.61 \, \text{kg}} \approx -0.69 \, \text{m/s} \).
04

Analyze Kinetic Energy

Kinetic energy is given by \( KE = \frac{1}{2}mv^2 \). Since both masses have non-zero velocities, the system will have some non-zero kinetic energy. Therefore, even if momentum is zero, kinetic energy is not necessarily zero.
05

Calculate System's Kinetic Energy

Calculate the kinetic energy for both carts. For cart 1: \( KE_1 = \frac{1}{2} \times 0.35 \, \text{kg} \times (1.2 \, \text{m/s})^2 = 0.252 \, \text{J} \). For cart 2: \( KE_2 = \frac{1}{2} \times 0.61 \, \text{kg} \times (0.69 \, \text{m/s})^2 = 0.145 \, \text{J} \). Thus, the total kinetic energy is \( KE_{total} = KE_1 + KE_2 = 0.252 \, \text{J} + 0.145 \, \text{J} = 0.397 \, \text{J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a fundamental concept in physics that describes the energy of an object due to its motion. To calculate kinetic energy, use the formula:\[KE = \frac{1}{2}mv^2\]where \(m\) is mass and \(v\) is velocity. This formula highlights that kinetic energy depends not only on the speed of an object but also on its mass.
While momentum can be zero in certain scenarios—like when two objects have equal and opposite momentum—kinetic energy can't be zero unless the objects are at rest. In our exercise, even though the total momentum is zero because the carts move toward each other with precision, both carts are still in motion. Hence, each has a non-zero kinetic energy.
For practical understanding:
  • A cart with a higher mass or speed will have greater kinetic energy.
  • Even if two carts cancel each other's momentum, they can each still have kinetic energy because it's based on \(v^2\).
Air-Track Carts
Air-track carts are a popular tool in physics experiments to explore motion concepts such as momentum and energy. They move on a cushion of air, minimizing friction, which allows for nearly ideal collision conditions. This setup makes it easier to study theoretical physics concepts in a practical scenario.
During experiments, air is pumped underneath the track, creating a consistent thin layer that lifts the carts slightly, allowing them to glide smoothly. This allows observers to focus on the motion-related forces rather than getting distracted by friction. Air-track carts are exceptionally helpful in illustrating key principles like:
  • Conservation of momentum: This occurs when two carts collide and the total momentum remains unchanged.
  • Effects of varying masses and velocities on collision outcomes.
These experiments help students visualize theoretical physics principles in action, aiding deeper understanding.
Collision Physics
In the realm of collision physics, it’s crucial to understand how forces and energies interact during an impact. Collisions can be either elastic or inelastic, differing in how kinetic energy is conserved. Here’s a simplified breakdown:
- **Elastic Collisions**: Both momentum and kinetic energy are conserved. Such collisions generally occur between hard objects where no energy is lost to sound, heat, or deformation. - **Inelastic Collisions**: These collisions conserve momentum, but not kinetic energy. Energy is lost in other forms, like sound or heat, and objects might stick together afterward.
In the exercise at hand, we explore momentum conservation—a scenario in which the total momentum before and after the collision remains constant. This doesn’t necessarily mean kinetic energy is conserved, especially in inelastic collisions.
For aspiring physicists:
  • Comprehending these collision types can greatly aid in predicting real-world outcomes of object interactions.
  • It's pivotal to calculate both momentum and kinetic energy to grasp different aspects of a collision thoroughly.
By understanding these principles, students can extend learning beyond the classroom and think critically about physical phenomena around them.

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Most popular questions from this chapter

Object A has a mass \(m\), object B has a mass \(2 m,\) and object C has a mass \(m / 2\). Rank these objects in order of increasing kinetic energy, given that they all have the same momentum. Indicate ties where appropriate.

A hoop of mass \(M\) and radius \(R\) rests on a smooth, level surface. The inside of the hoop has ridges on either side, so that it forms a track on which a ball can roll, as indicated in Figure \(9-25\). If a ball of mass \(2 M\) and radius \(r=R / 4\) is released as shown, the system rocks back and forth until it comes to rest with the ball at the bottom of the hoop. When the ball comes to rest, what is the \(x\) coordinate of its center?

Predict/Explain A net force of \(200 \mathrm{N}\) acts on a \(100-\mathrm{kg}\) boulder, and a force of the same magnitude acts on a \(100-\mathrm{g}\) pebble. (a) Is the change of the boulder "s momentum in one second greater than, less than, or equal to the change of the pebble's momentum in the same time period? (b) Choose the best explanation from among the following: I. The large mass of the boulder gives it the greater momentum. II. The force causes a much greater speed in the 100 -g pebble, resulting in more momentum. III. Equal force means equal change in momentum for a given time.

On a cold winter morning, a child sits on a sled resting on smooth ice. When the 9.75 -kg sled is pulled with a horizontal force of \(40.0 \mathrm{N},\) it begins to move with an acceleration of \(2.32 \mathrm{m} / \mathrm{s}^{2} .\) The \(21.0-\mathrm{kg}\) child accelerates too, but with a smaller acceleration than that of the sled. Thus, the child moves forward relative to the ice, but slides backward relative to the sled. Find the acceleration of the child relative to the ice.

A 26.2-kg dog is running northward at 2.70 m/s, while a \(5.30-\mathrm{kg}\) cat is running eastward at \(3.04 \mathrm{m} / \mathrm{s} .\) Their \(74.0-\mathrm{kg}\) owner has the same momentum as the two pets taken together. Find the direction and magnitude of the owner's velocity.

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