/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 An \(85-k g\) lumberjack stands ... [FREE SOLUTION] | 91Ó°ÊÓ

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An \(85-k g\) lumberjack stands at one end of a \(380-\mathrm{kg}\) floating log, as shown in Figure \(9-15\). Both the log and the lumberjack are at rest initially. (a) If the lumberjack now trots toward the other end of the log with a speed of \(2.7 \mathrm{m} / \mathrm{s}\) relative to the log, what is the lumberjack's speed relative to the shore? Ignore friction between the log and the water. (b) If the mass of the log had been greater, would the lumberjack's speed relative to the shore be greater than, less than, or the same as in part (a)? Explain. (c) Check your answer to part (b) by calculating the lumberjack's speed relative to the shore for the case of a \(450-\mathrm{kg}\) log.

Short Answer

Expert verified
(a) 2.177 m/s, (b) Greater, (c) 2.282 m/s.

Step by step solution

01

Identify Given Values

Let's note down the given information from the problem: The mass of the lumberjack is \( m_l = 85 \text{ kg} \), and the mass of the log is initially \( m_{log1} = 380 \text{ kg} \). The speed of the lumberjack relative to the log is \( v_{l/log} = 2.7 \text{ m/s} \). We are to find the speed of the lumberjack relative to the shore.
02

Apply Conservation of Momentum for Part (a)

Since there is no external horizontal force working in the system (lumberjack + log), momentum is conserved. Initially, both the log and the lumberjack are at rest, so the total initial momentum is zero. In the final state, we use the equation: \[ m_l \cdot v_{l/shore} + m_{log} \cdot v_{log/shore} = 0 \] where \( v_{log/shore} \) is the speed of the log relative to the shore.
03

Relate Relative Speeds for Part (a)

The speed of the lumberjack relative to the log, \( v_{l/log} = v_{l/shore} - v_{log/shore} \). Substitute this into the conservation of momentum equation: \( m_l \cdot (v_{log/shore} + v_{l/log}) + m_{log} \cdot v_{log/shore} = 0 \). Simplify to find \( v_{l/shore} \).
04

Calculate Lumberjack's Speed Relative to the Shore for Part (a)

Substitute the known values in the simplified equation: \( 85(v_{log/shore} + 2.7) + 380v_{log/shore} = 0 \). Solve this to get \( v_{log/shore} = -0.523 \text{ m/s} \). Substitute back to find \( v_{l/shore} = v_{log/shore} + v_{l/log} = 2.177 \text{ m/s} \).
05

Discuss the Effect of Increasing Log Mass for Part (b)

If the log's mass increases, then according to the conservation of momentum equation: closely examining the equation \( m_{log} \cdot v_{log/shore} \) must become larger negatively to offset, meaning \( v_{log/shore} \) must become smaller since the mass has increased. As \( v_{l/shore} - v_{log/shore} = 2.7 \), with a smaller negative \( v_{log/shore} \), \( v_{l/shore} \) will increase.
06

Apply Conservation of Momentum for Part (c)

For a \(450\text{ kg}\) log, use the same momentum equation \( 85 \cdot (v_{l/shore} + v_{log/shore}) + 450 \cdot v_{log/shore} = 0 \).
07

Calculate Lumberjack's Speed Relative to the Shore for Part (c)

Substitute the values for a \(450\text{ kg}\) log: \( 85(v_{log/shore} + 2.7) + 450v_{log/shore} = 0 \). Solving gives \( v_{log/shore} = -0.418 \text{ m/s} \). Therefore, \( v_{l/shore} = v_{log/shore} + v_{l/log} = 2.282 \text{ m/s} \), confirming the speed increase.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Speed
Understanding relative speed can be crucial in solving physics problems like the one involving the lumberjack and the floating log. Relative speed refers to the speed of one object as observed from another object or reference point.
The concept becomes particularly relevant when different frames of reference are in motion relative to one another.In the given exercise, the lumberjack's speed is stated in relation to the log, which is itself capable of movement. The lumberjack moves with a speed of \(2.7 \text{ m/s} \) relative to the log. This is not the same as his speed relative to the shore, because both he and the log can move along the surface of the water.- To solve such problems, it's important to remember that relative speed accounts for the motion seen from a different frame of reference.- Always define all movements with respect to a chosen reference point — in this case, the shore is the static point of reference.
This necessitates translating the relative speed into real-world or absolute terms by using the relative speed formula:\[ v_{l/shore} = v_{log/shore} + v_{l/log} \]By incorporating both the speeds of the log and the lumberjack relative to each other and to the shore, we solve for the lumberjack's absolute speed relative to the shore.
Inertia
Inertia is an important element at play in this problem, influencing how both the lumberjack and the log move. According to Newton's First Law of Motion, inertia is the property of an object to resist changes to its state of motion. - Objects with more mass have greater inertia and therefore resist changes in motion more strongly.
Larger mass, like the log compared to the lumberjack, means it requires more force to achieve the same acceleration. In the context of the problem, when the lumberjack moves, the log resists this change due to its inertia, impacting how it contributes to the overall system's momentum. • When the lumberjack starts running, due to conservation of momentum, the log begins to move in the opposite direction to balance the system because there are no external forces acting on the system.
The interplay of inertia in the system dictates the outcomes of their velocities concerning the shore, and understanding inertia helps in reasoning why the log moves opposite to the lumberjack's direction and why the lumberjack's relative speed changes depending on the mass of the log.
Physics Problem Solving
Physics problem-solving is a systematic approach that involves breaking down a complex scenario into manageable parts. When solving a problem like this, consider the following steps:Identify knowns and unknowns:- Start by clearly identifying all given values, such as masses and relative speeds.
- Define what you need to find—in this problem, the lumberjack's speed relative to the shore.Use the principles of physics:- Apply the conservation of momentum principle. It states that the total momentum of an isolated system remains constant if no external forces act upon it.- Set up the corresponding equation: \[ m_l \cdot v_{l/shore} + m_{log} \cdot v_{log/shore} = 0 \], where the sum of the momentums must equal zero as initially both objects are at rest.Solve systematically:- Substitute known values into your equation, and solve for the unknown variable, \( v_{l/shore} \).
Test your understanding:- Discuss results in the context of the scenario, like considering how changes in mass affect motion, which is crucial for confirming understanding and solution accuracy.These problem-solving strategies highlight the importance of systematic approaches and deep understanding in physics to approach a diverse range of problems confidently.

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Most popular questions from this chapter

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