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Force A has a magnitude \(F\) and acts for the time \(\Delta t\) force B has a magnitude \(2 F\) and acts for the time \(\Delta t / 3,\) force \(C\) has a magnitude \(5 F\) and acts for the time \(\Delta t / 10,\) and force \(D\) has a magnitude \(10 F\) and acts for the time \(\Delta t / 100 .\) Rank these forces in order of increasing impulse. Indicate ties where appropriate.

Short Answer

Expert verified
The ranking is: D, C, B, A.

Step by step solution

01

Understand the concept of impulse

Impulse is calculated as the product of force and the time duration over which the force is applied. It is given by the formula: \( I = F \cdot \Delta t \). This means the impulse depends on both the strength of the force and how long it acts.
02

Calculate impulse for each force

For each force, calculate the impulse by multiplying the magnitude of the force by the time period it acts: - For Force A: \( I_A = F \cdot \Delta t \)- For Force B: \( I_B = 2F \cdot \frac{\Delta t}{3} \)- For Force C: \( I_C = 5F \cdot \frac{\Delta t}{10} \)- For Force D: \( I_D = 10F \cdot \frac{\Delta t}{100} \)
03

Simplify the expression for the impulse of each force

Simplify the expressions for impulse:- \( I_A = F \cdot \Delta t \)- \( I_B = \frac{2F\Delta t}{3} \)- \( I_C = \frac{5F\Delta t}{10} = \frac{F\Delta t}{2} \)- \( I_D = \frac{10F\Delta t}{100} = \frac{F\Delta t}{10} \)
04

Rank the forces based on impulse

To rank the forces, compare their impulse values:- For Force A: \( I_A = F \Delta t \)- For Force B: \( I_B \approx 0.67F \Delta t \)- For Force C: \( I_C = 0.5F \Delta t \)- For Force D: \( I_D = 0.1F \Delta t \)From lowest to highest impulse: Force D, Force C, Force B, Force A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impulse Calculations
Impulse is a crucial concept in physics that relates to how much force is applied over a period of time. The formula to calculate impulse is straightforward:
  • \( I = F \cdot \Delta t \)
Where \( I \) stands for impulse, \( F \) is the force, and \( \Delta t \) is the time duration the force is applied.
This equation shows us that impulse increases with either higher force or longer duration, meaning more significant impact or momentum change.
In the given exercise, calculating impulse involves determining this product for each provided force. By applying this calculation method, we convert each force and time pair into an impulse value.
This helps us assess and compare which forces cause greater changes in motion, which is central to understanding collision dynamics, sports, and everyday motion analyses.
Force and Time Relation
A fundamental aspect of physics is the relationship between force and time. When a force acts over a period of time, it does not matter just how strong the force is but also how long it is applied.
In practical scenarios, longer application of a moderate force might have the same impact as a short but strong force.
  • Force A acts for the full time \( \Delta t \)
  • Force B acts for \( \Delta t / 3 \)
  • Force C acts for \( \Delta t / 10 \)
  • Force D acts for \( \Delta t / 100 \)
The relation is evident in the calculations as shown: even though some forces are stronger, their reduced application time diminishes their overall impulse.
This is a typical consideration in design and engineering when optimizing the effects of applied forces, such as in airbags or crash cushions.
Ranking Impulses
Ranking impulses simply involves comparing the calculated impulse values for each force and time combination.
  • For Force A: \( I_A = F \Delta t \)
  • For Force B: \( I_B = \frac{2F \Delta t}{3} \)
  • For Force C: \( I_C = \frac{F \Delta t}{2} \)
  • For Force D: \( I_D = \frac{F \Delta t}{10} \)
By simplifying these, we see that:
  • \( I_D \) has the smallest impulse, with \( 0.1F \Delta t \)
  • \( I_C \) follows with \( 0.5F \Delta t \)
  • \( I_B \) is next with approximately \( 0.67F \Delta t \)
  • \( I_A \) has the largest impulse \( F \Delta t \)
Understanding how to rank these gives insight into which forces will cause the most significant change in motion, a critical skill for problem-solving in physics.
Physics Problem Solving
Solving physics problems effectively involves understanding core concepts, breaking down equations, and applying them step-by-step, much like solving a puzzle.
Let's break down the steps used in the exercise:
  • Understanding the problem statement: Recognize forces and time factors.
  • Using the impulse formula \( I = F \cdot \Delta t \) to calculate impulse for each scenario.
  • Assessing and simplifying results for easy comparison.
  • Ranking according to impulse values derived: helps to visualize which forces have more influence.
This structured approach aids in tackling more complex real-world problems by developing a methodical way of thinking and a disciplined problem-solving strategy.
Physics encourages exploring various routes and detailed processes, ultimately enhancing analytical and critical thinking skills, invaluable for academic and practical applications alike.

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Most popular questions from this chapter

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