/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 You hold a brick at rest in your... [FREE SOLUTION] | 91Ó°ÊÓ

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You hold a brick at rest in your hand. (a) How many forces act on the brick? (b) Identify these forces, (c) Are these forces equal in magnitude and opposite in direction? (d) Are these forces an action-reaction pair? Explain.

Short Answer

Expert verified
Two forces act on the brick: gravity and normal force. They are equal and opposite, but not an action-reaction pair.

Step by step solution

01

Analyze the Scenario

You are holding a brick at rest in your hand. This implies that the brick is not accelerating, meaning the net force on the brick is zero according to Newton's First Law.
02

Count the Forces

Identify how many forces are acting on the brick. In this case, there are two main forces to consider: the gravitational force and the normal force exerted by your hand.
03

Identify the Forces

The gravitational force (often called weight) is acting downward on the brick, directed towards the center of the Earth. The normal force is exerted by your hand upward, opposing gravity.
04

Determine Force Magnitude and Direction

Since the brick is at rest, the forces must be equal in magnitude and opposite in direction. The gravitational force and the normal force are equal in magnitude but act in opposite directions to keep the brick stationary.
05

Evaluate Action-Reaction Pair

According to Newton's Third Law, for every action, there is an equal and opposite reaction. While the gravitational force and normal force are equal and opposite, they are not action-reaction pairs because they act on the same object, rather than different objects.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental force that attracts two masses toward each other. In the context of holding a brick, the gravitational force is essentially the weight of the brick acting downward towards the Earth.
This force results from the mass of the brick interacting with the Earth's gravitational field. It's always directed towards the center of the Earth, and its magnitude can be calculated using the equation: \( F_g = m \cdot g \), where \( F_g \) is the gravitational force, \( m \) is the mass of the brick, and \( g \) is the acceleration due to gravity (approximately \( 9.8 \text{ m/s}^2 \) on Earth).
Understanding gravitational force helps us comprehend why objects fall and why they have weight.
Normal Force
The normal force is a contact force exerted by a surface, in this case, your hand, to support the weight of the brick and prevent it from falling.
It acts perpendicular to the surface in contact with the object. For the brick sitting in your hand, the normal force acts upward and is equal in magnitude but opposite in direction to the gravitational force pulling downward.
This force ensures the brick is held stable and doesn't accelerate either upwards or downwards, maintaining its position in your hand.
Action-Reaction Pairs
Newton's Third Law of Motion describes action-reaction pairs as equal and opposite forces acting on two different objects. For every action, there is an equal and opposite reaction.
In the case of the brick, although the gravitational and normal forces are equal and opposite, they are not action-reaction pairs. This is because both forces are acting on the brick itself.
An action-reaction pair involving the brick could be identified like the brick pulling up on the Earth with the same gravitational force that the Earth pulls down on the brick. Here, the brick and the Earth are separate objects in this interaction.
Net Force
Net force is the overall force acting on an object when all the individual forces acting upon it are combined. It determines whether an object accelerates or remains at rest.
When you hold the brick stationary, the net force on it is zero. This is due to the gravitational force downwards being perfectly balanced by the normal force upwards.
Newton's First Law tells us that with no net force acting (net force equaling zero), an object will maintain its current state of motion—either staying at rest or moving at constant velocity.
Force Equilibrium
Force equilibrium occurs when all the forces acting on an object are balanced, resulting in a net force of zero. This concept is fundamental in understanding how objects can remain at rest or move without accelerating.
In our brick example, force equilibrium is achieved because the gravitational force is perfectly counterbalanced by the normal force from your hand.
When an object is in force equilibrium, it neither moves nor changes velocity, illustrating a state of mechanical balance and stability.

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Most popular questions from this chapter

\(\bullet\) Stopping a 747 A 747 jetliner lands and begins to slow to a stop as it moves along the runway. If its mass is \(3.50 \times 10^{5} \mathrm{kg}\) its speed is \(27.0 \mathrm{m} / \mathrm{s},\) and the net braking force is \(4.30 \times 10^{5} \mathrm{N}\) (a) what is its speed 7.50 s later? (b) How far has it traveled in this time?

You are pulling your little sister on her sled across an icy (frictionless) surtace. When you exert a constant horizontal force of \(120 \mathrm{N},\) the sled has an acceleration of \(2.5 \mathrm{m} / \mathrm{s}^{2} .\) If the sled has a mass of \(7.4 \mathrm{kg},\) what is the mass of your little sister?

IP B I O The Force of Running Biomechanical research has shown that when a \(67-\mathrm{kg}\) person is running, the force exerted on each foot as it strikes the ground can be as great as \(2300 \mathrm{N}\). (a) What is the ratio of the force exerted on the foot by the ground to the person's body weight? (b) If the only forces acting on the person are (i) the force exerted by the ground and (ii) the person's weight, what are the magnitude and direction of the person's acceleration? (c) If the acceleration found in part (b) acts for \(10.0 \mathrm{ms},\) what is the resulting change in the vertical component of the person's velocity?

Predict/Explain You jump out of an airplane and open your parachute after an extended period of free fall. (a) To decelerate your fall, must the force exerted on you by the parachute be greater than, less than, or equal to your weight? (b) Choose the best explanation from among the following: I. Parachutes can only exert forces that are less than the weight of the skydiver. II. The parachute exerts a force exactly equal to the skydiver's weight. III. To decelerate after free fall, the net force acting on a skydiver must be upward.

\- CE An object of mass \(m\) is initially at rest. After a force of magnitude \(F\) acts on it for a time \(T,\) the object has a speed \(v\). Suppose the mass of the object is doubled, and the magnitude of the force acting on it is quadrupled. In terms of \(T\), how long does it take for the object to accelerate from rest to a speed \(v\) now?

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