/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 A volcano launches a lava bomb s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A volcano launches a lava bomb straight upward with an initial speed of \(28 \mathrm{m} / \mathrm{s}\). Taking upward to be the positive direction, find the speed and direction of motion of the lava bomb (a) 2.0 seconds and (b) 3.0 seconds after it is launched.

Short Answer

Expert verified
(a) 8.4 m/s upward; (b) 1.4 m/s downward.

Step by step solution

01

Understanding the problem

We need to find the speed and direction of a lava bomb launched vertically upward at an initial speed of \(28\,\mathrm{m/s}\). We'll determine the speed after \(2.0\,\mathrm{s}\) and \(3.0\,\mathrm{s}\), using the formula that relates velocity, initial velocity, acceleration, and time.
02

State the equation for velocity

The velocity of a falling object can be found using the equation: \(v = u + at\), where \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(t\) is the time. Here, \(u = 28 \, \mathrm{m/s}\) and \(a = -9.8 \, \mathrm{m/s^2}\) due to gravity acting downwards.
03

Calculate velocity at 2.0 seconds

Plug in the values into the equation: \[v = 28 + (-9.8) \times 2.0\] This simplifies to \[v = 28 - 19.6 = 8.4 \, \mathrm{m/s}\]So, at \(2.0\, \mathrm{s}\), the speed is \(8.4\,\mathrm{m/s}\) in the upward direction.
04

Calculate velocity at 3.0 seconds

Use the same formula with \(t = 3.0\) seconds:\[v = 28 + (-9.8) \times 3.0\] This simplifies to: \[v = 28 - 29.4 = -1.4 \, \mathrm{m/s}\]At \(3.0\,\mathrm{s}\), the negative sign indicates that the speed is \(1.4\,\mathrm{m/s}\) in the downward direction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Projectile Motion
Projectile motion refers to the path that an object follows when it is thrown or projected into the air and is subject to gravitational forces. This encompasses motion in two dimensions: horizontal and vertical. However, in this exercise, we are focusing on vertical projectile motion.
When an object, like the lava bomb, is launched upward, it follows a parabolic trajectory under the influence of gravity. In vertical projectile motion, which is a simpler form, the object accelerates upwards initially, slows down due to gravity, and eventually comes back down. This motion can be described using kinematic equations that incorporate velocity, time, and acceleration.
  • Key components include the initial launch angle and velocity, although in vertical motion, the launch angle is simply 90 degrees.
  • The impact of air resistance is often neglected to simplify calculations.
  • Gravity is the only force acting upon the object after it is launched.
The solution to the problem involves calculating the speed at different points in time using these principles.
Initial Velocity
Initial velocity is the speed at which an object starts its motion. In kinematic problems like this one, initial velocity plays a crucial role in determining how the object moves over time.
For the lava bomb, the initial velocity is given as \(28 \text{ m/s}\) in the upward direction. When solving problems in physics, initial velocity is often denoted as \(u\) in equations.
With the initial velocity known, you can use it to find final velocities at various time intervals through the kinematic equation:
  • \(v = u + at\), where \(v\) is final velocity, \(u\) is initial velocity, \(a\) is acceleration, and \(t\) is time.
The importance of initial velocity lies in how it sets the starting conditions for projectile motion, influencing the object's maximum height and the total time of flight.
Gravity
Gravity is the force that pulls objects towards the center of the Earth, influencing all motion on and near the surface. It is a constant acceleration, denoted by \(g\), typically valued at \(9.8 \text{ m/s}^2\) downward.
In this exercise, gravity is the opposing force acting against the lava bomb's upward velocity. It continuously decelerates the bomb until it momentarily stops at its peak height, before accelerating it downward.
Understanding gravity's role is paramount in solving kinematic problems, as it affects the object's speed and direction over time.
  • It acts consistently and equally on all freely falling objects.
  • Only affects motion vertically, leaving horizontal motion unaffected.
  • Provides a reference to determine the direction of acceleration (downward in this case).
By factoring in gravity, we observe the negative sign in the acceleration term in kinematic equations, which adjusts the initial upward motion to predict future velocity and direction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You jog at \(9.5 \mathrm{km} / \mathrm{h}\) for \(8.0 \mathrm{km},\) then you jump into a car and drive an additional \(16 \mathrm{km}\). With what average speed must you drive your car if your average speed for the entire \(24 \mathrm{km}\) is to be \(22 \mathrm{km} / \mathrm{h} ?\)

A Tongue's Acceleration When a chameleon captures an insect, its tongue can extend \(16 \mathrm{cm}\) in \(0.10 \mathrm{s}\). (a) Find the magnitude of the tongue's acceleration, assuming it to be constant. (b) In the first \(0.050 \mathrm{s}\), does the tongue extend \(8.0 \mathrm{cm},\) more than \(8.0 \mathrm{cm}\) or less than \(8.0 \mathrm{cm} ?\) Support your conclusion with a calculation.

Wrongly called for a foul, an angry basketball player throws the ball straight down to the floor. If the ball bounces straight up and returns to the floor \(2.8 \mathrm{s}\) after first striking it, what was the ball's greatest height above the floor?

At the edge of a roof you throw ball 1 upward with an initial speed \(v_{0}\) : a moment later you throw ball 2 downward with the same initial speed. The balls land at the same time. Which of the following statements is true for the instant just before the balls hit the ground? A. The speed of ball 1 is greater than the speed of ball \(2 ;\) B. The speed of ball 1 is equal to the speed of ball 2; C. The speed of ball 1 is less than the speed of ball 2 .

Blo Bacterial Motion Approximately 0.1\% of the bacteria in an adult human's intestines are Esclerichia coll. These bacteria have been observed to move with speeds up to \(15 \mathrm{mm} / \mathrm{s}\) and maximum accelerations of \(166 \mu \mathrm{m} / \mathrm{s}^{2}\). Suppose an \(E\). coli bacterium in your intestines starts at rest and accelerates at \(156 \mu \mathrm{m} / \mathrm{s}^{2}\). How much (a) time and (b) distance are required for the bacterium to reach a speed of \(12 \mu \mathrm{m} / \mathrm{s} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.