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One day you notice that the outside temperature increased by \(27 \mathrm{F}^{\circ}\) between your early morning jog and your lunch at noon. What is the corresponding change in temperature in the (a) Celsius and (b) Kelvin scales?

Short Answer

Expert verified
The temperature change is 15°C and 15 K.

Step by step solution

01

Understanding the Problem

You need to convert a temperature increase of 27°F into Celsius and Kelvin. Remember that for temperature changes, the formulas to convert Fahrenheit to Celsius and Kelvin can be used without adjustments for initial values because you are dealing with differences, not absolute values.
02

Convert Temperature Change from Fahrenheit to Celsius

To convert the change from Fahrenheit to Celsius, use the formula for temperature differences: \[ \Delta C = \frac{\Delta F - 32}{1.8} \]Since you are dealing with a temperature change, the 32°F offset used in absolute conversions can be omitted. Thus, the formula simplifies to:\[ \Delta C = \frac{\Delta F}{1.8} \] Substitute the given temperature change into the formula:\[ \Delta C = \frac{27}{1.8} = 15°C \]
03

Convert Temperature Change from Celsius to Kelvin

The change in temperature in Celsius is the same in Kelvin for temperature differences because Kelvin and Celsius scales have the same magnitude units. Therefore, the temperature change in Kelvin is also the same as in Celsius. \[ \Delta K = 15 \, K \]
04

Verify the Results

Ensure the calculations align with the known formulas for converting temperature changes between Fahrenheit, Celsius, and Kelvin. The steps followed the correct process for converting differences, indicating the results are accurate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fahrenheit to Celsius
Temperature conversion from Fahrenheit to Celsius is a fundamental process in understanding how different temperature scales relate to each other. In particular, converting temperature differences is even more straightforward. Normally, when converting a specific temperature (not a difference), you would use the formula:
  • \[ C = \frac{5}{9} (F - 32) \]
However, when converting temperature differences, the offset 32°F does not apply because it is used to adjust for the starting baseline in absolute conversions.
Thus, for temperature differences, the conversion formula between Fahrenheit and Celsius simplifies to:
  • \[ \Delta C = \frac{\Delta F}{1.8} \]
This is because temperature scales, whether Celsius or Fahrenheit, differ mainly in their scaling factors (also known as unit differences) which is 1.8.
Therefore, to convert a temperature change of 27°F to Celsius, divide by 1.8 to find that the equivalent temperature change is \( 15^{\circ}C \). Understanding this formula allows you to navigate temperature changes seamlessly across these two scales.
Fahrenheit to Kelvin
Temperature conversions also extend to Kelvin, a scale often used in scientific contexts due to its absolute nature. Kelvin does not employ degree symbols because it is an absolute scale.
The Kelvin scale is directly related to the Celsius scale through a simple offset, rather than a conversion factor. The standard relationship is:
  • \[ K = C + 273.15 \]
However, when dealing with temperature differences, such as the change in temperature, this offset is irrelevant. Just like Celsius to Fahrenheit differences, the Kelvin scale directly correlates with the Celsius scale in terms of magnitude.
So a change of 15°C is equivalent to a change of 15 Kelvin. In summary, since the Celsius and Kelvin scales are baseline-aligned in terms of scope of difference, temperature changes calculated in Celsius can be directly converted to Kelvin one-to-one, making them very helpful for scientific calculations.
Temperature Differences
Understanding temperature differences is essential for making accurate scientific and practical assessments. When you are asked to convert a temperature difference, remember you are not starting from an absolute point but rather examining the change.
For scales like Fahrenheit, Celsius, and Kelvin, it’s crucial to recognize the handling of temperature differences versus static temperature values. A key takeaway is:
  • Use conversion formulas designed for differences, like \( \Delta C = \frac{\Delta F}{1.8} \) for converting Fahrenheit to Celsius.
  • Remember that temperature differences in Celsius directly align with Kelvin due to their scale's uniformity.
By focusing on these principles, you avoid unnecessary complexities that can arise if initial values are mistakenly incorporated into the conversion of differences.
Moreover, understanding these core concepts helps in various real-world applications such as weather forecasting, climate studies, and engineering projects, where temperature variation is critical to success.

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Most popular questions from this chapter

An 97.6-g lead ball is dropped from rest from a height of \(4.57 \mathrm{m} .\) The collision between the ball and the ground is totally inelastic. Assuming all the ball's kinetic energy goes into heating the ball, find its change in temperature.

Longest Suspension Bridge The world's longest suspension bridge is the Akashi Kaikyo Bridge in Japan. The bridge is \(3910 \mathrm{m}\) long and is constructed of steel. How much longer is the bridge on a warm summer day \(\left(30.0^{\circ} \mathrm{C}\right)\) than on a cold winter day \(\left(-5.00^{\circ} \mathrm{C}\right) ?\)

Referring to the copper ring in the previous problem, imagine that initially the ring is hotter than room temperature, and that an aluminum rod that is colder than room temperature fits snugly inside the ring. When this system reaches thermal equilibrium at room temperature, is the rod (A, firmly wedged in the ring; or \(\mathbf{B},\) can it be removed easily)?

Two objects are made of the same material but have different temperatures. Object 1 has a mass \(m\) and object 2 has a mass \(2 m\). If the objects are brought into thermal contact, (a) is the temperature change of object 1 greater than, less than, or equal to the temperature change of object \(2 ?\) (b) Choose the best explanation from among the following: I. The larger object gives up more heat, and therefore its temperature change is greatest. II. The heat given up by one object is taken up by the other object. since the objects have the same heat capacity, the temperature changes are the same. III. One object loses heat of magnitude \(Q\), the other gains heat of magnitude Q. With the same magnitude of heat involved, the smaller object has the greater temperature change.

The Cricket Thermometer The rate of chirping of the snowy tree cricket (Oecanthus fultoni Walker) varies with temperature in a predictable way. A linear relationship provides a good match to the chirp rate, but an even more accurate relationship is the following: $$N=\left(5.63 \times 10^{10}\right) e^{-(6290 \mathrm{K}) / \mathrm{T}}$$ In this expression, \(N\) is the number of chirps in \(13.0 \mathrm{s}\) and \(T\) is the temperature in kelvins. If a cricket is observed to chirp 185 times in \(60.0 \mathrm{s},\) what is the temperature in degrees Fahrenheit?

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