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Longest Suspension Bridge The world's longest suspension bridge is the Akashi Kaikyo Bridge in Japan. The bridge is \(3910 \mathrm{m}\) long and is constructed of steel. How much longer is the bridge on a warm summer day \(\left(30.0^{\circ} \mathrm{C}\right)\) than on a cold winter day \(\left(-5.00^{\circ} \mathrm{C}\right) ?\)

Short Answer

Expert verified
The bridge is approximately 1.51 meters longer on a warm day.

Step by step solution

01

Understand the Concept of Thermal Expansion

The length of the bridge changes with temperature due to thermal expansion. The formula for linear expansion is \( \Delta L = \alpha \times L_0 \times \Delta T \), where \( \Delta L \) is the change in length, \( \alpha \) is the coefficient of linear expansion, \( L_0 \) is the original length, and \( \Delta T \) is the change in temperature.
02

Determine the Coefficient of Linear Expansion for Steel

Find the coefficient of linear expansion for steel. Typically, \( \alpha \approx 11 \times 10^{-6} \/ \text{°C}^{-1} \).
03

Calculate the Temperature Change

Find the temperature difference: \( \Delta T = 30.0^{\circ} \mathrm{C} - (-5.0^{\circ} \mathrm{C}) = 35.0^{\circ} \mathrm{C} \).
04

Apply the Formula for Linear Expansion

Use the formula to calculate \( \Delta L \): \( \Delta L = 11 \times 10^{-6} \/ \mathrm{°C}^{-1} \times 3910 \/ \mathrm{m} \times 35.0 \/ \mathrm{°C} \).
05

Solve the Equation

Calculate \( \Delta L \): \( \Delta L = 11 \times 10^{-6} \times 3910 \times 35 = 1.50885 \text{ meters} \).
06

Interpret the Result

The bridge will be approximately 1.51 meters longer on a warm summer day than on a cold winter day.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Expansion
Linear expansion is a key concept when considering how materials behave when temperatures change. This phenomenon occurs because most materials expand or contract when their temperature rises or falls. In simple terms, linear expansion is the tendency of an object to change its length in response to a change in temperature.

For linear expansion, the change in length \(\Delta L\) of an object can be calculated using the formula: \[\Delta L = \alpha \times L_0 \times \Delta T\]where:
  • \(\Delta L\) is the change in length.
  • \(\alpha\) is the coefficient of linear expansion, a material-specific constant that indicates how much a material expands per degree change in temperature.
  • \(L_0\) is the original length of the material.
  • \(\Delta T\) is the temperature change that the material undergoes.
Understanding linear expansion is crucial for engineers when designing structures like bridges, as it helps them predict how much a structure might expand or contract with temperature changes.
Coefficient of Linear Expansion
The coefficient of linear expansion, represented by the Greek letter \(\alpha\), is an intrinsic property of materials that quantifies how much they expand per degree of temperature change.

Each material has a unique \(\alpha\), which means that different materials will expand differently for the same change in temperature. For example, steel, which is commonly used in construction, has a coefficient of linear expansion of approximately \(11 \times 10^{-6} \/ \text{°C}^{-1}\).

This value can be interpreted as: for every 1°C increase in temperature, each meter of steel will expand by \(11 \times 10^{-6} \/ \text{m}\). Here are some key points about the coefficient:
  • It's always a positive number because materials typically expand when heated.
  • It is essential for engineers and architects to design structures that can withstand changes in length due to temperature variations.
By understanding the coefficient of linear expansion, engineers can ensure the integrity and safety of structures in different temperature conditions.
Temperature Change
Temperature change, denoted as \(\Delta T\), is a critical factor in the study of thermal expansion as it directly influences the change in length of materials.

In the example of the Akashi Kaikyo Bridge, the temperature difference between a warm summer day (30.0°C) and a cold winter day (-5.0°C) is calculated to be \(\Delta T = 35.0° \text{C}\). This means that the temperature increases by 35.0°C from the cold to the warm season.

Understanding the temperature change is crucial because:
  • It helps predict how much a material, like the steel in a bridge, will expand or contract over a specified temperature range.
  • Accurate temperature readings ensure that calculations for thermal expansion or contraction are precise.
  • Taking account of temperature changes helps in planning construction materials and techniques that can endure various weather conditions.
By factoring in the temperature change, engineers can make informed decisions about materials and designs to maintain structural stability throughout the seasons.

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Most popular questions from this chapter

A \(226-\mathrm{kg}\) rock sits in full sunlight on the edge of a cliff \(5.25 \mathrm{m}\) high. The temperature of the rock is \(30.2^{\circ} \mathrm{C}\). If the rock falls from the cliff into a pool containing \(6.00 \mathrm{m}^{3}\) of water at \(15.5^{\circ} \mathrm{C}\), what is the final temperature of the rock- water system? Assume that the specific heat of the rock is \(1010 \mathrm{J} /(\mathrm{kg} \cdot \mathrm{K})\).

If 2200 J of heat are added to a 190 -g object, its temperature increases by \(12 \mathrm{C}^{\circ} .\) (a) What is the heat capacity of this object? (b) What is the object's specific heat?

Hot tea is poured from the same pot into two identical mugs. Mug 1 is filled to the brim; \(\operatorname{mug} 2\) is filled only halfway. Is the rate of cooling of mug \(1(A,\) greater than; \(\mathbf{B},\) less than; or \(\mathrm{C},\) equal to \()\) the rate of cooling of \(\operatorname{mug} 2 ?\)

A steel tape measure is marked in such a way that it gives accurate length measurements at a normal room temperature of \(20^{\circ} \mathrm{C}\). If this tape measure is used outdoors on a cold day when the temperature is \(0^{\circ} \mathrm{C}\), are its measurements too long, too short, or accurate?

Two metal rods-one lead, the other copper-are connected in series, as shown in Figure \(16-18\). These are the same two rods that were connected in parallel in Example \(16-7 .\) Note that each rod is \(0.525 \mathrm{m}\) in length and has a square cross section \(1.50 \mathrm{cm}\) on a side. The temperature at the lead end of the rods is \(2.00^{\circ} \mathrm{C} ;\) the temperature at the copper end is \(106^{\circ} \mathrm{C} .\) (a) The average temperature of the two ends is \(54.0^{\circ} \mathrm{C}\). Is the temperature in the middle, at the lead- copper interface, greater than, less than, or equal to \(54.0^{\circ} \mathrm{C}\) ? Explain. (b) Given that the heat flow through each of these rods in \(1.00 \mathrm{s}\) is \(1.41 \mathrm{J}\), find the temperature at the lead- copper interface.

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