/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 A surfer floating beyond the bre... [FREE SOLUTION] | 91Ó°ÊÓ

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A surfer floating beyond the breakers notes 14 waves per minute passing her position. If the wavelength of these waves is \(34 \mathrm{m},\) what is their speed?

Short Answer

Expert verified
The wave speed is approximately 7.922 m/s.

Step by step solution

01

Identify Given Information

The problem states that there are 14 waves passing per minute. Hence, the frequency of the waves, denoted as \( f \), is \( 14 \text{ waves/min} \). Additionally, it is given that the wavelength, represented by \( \lambda \), is \( 34 \text{ meters} \).
02

Convert Frequency to Standard Unit

To work with standard units, convert the frequency into waves per second (Hz). Since there are 60 seconds in a minute, the frequency \( f \) is \( \frac{14}{60} \approx 0.233 \text{ Hz} \).
03

Use the Wave Speed Formula

The speed of a wave \( v \) is given by the product of its frequency \( f \) and its wavelength \( \lambda \). The formula is \( v = f \cdot \lambda \).
04

Calculate the Wave Speed

Substitute the values into the formula: \( v = 0.233 \text{ Hz} \times 34 \text{ m} = 7.922 \text{ m/s} \). Thus, the speed of the waves is approximately \( 7.922 \text{ meters per second} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency Conversion
Understanding frequency conversion is crucial when dealing with wave phenomena. Frequency, in general, refers to how often something happens over a specific time period. For waves, it is the number of oscillations or waves that pass a particular point in one second, expressed in Hertz (Hz). In the original exercise, the surfer counts 14 waves passing per minute. However, for practical calculations, we usually prefer the standard unit of Hertz, which measures waves per second.
  • To convert from waves per minute to Hz, divide the number of waves by the number of seconds in a minute.
  • There are 60 seconds in a minute, so the conversion involves dividing 14 waves/minute by 60 seconds.
This results in a frequency of approximately 0.233 Hz, meaning that roughly 0.233 waves pass through a point each second. This conversion makes it easier to use the frequency in further calculations involving standard units.
Wavelength
Wavelength is another fundamental concept when studying waves. It is the distance between successive crests (or troughs) of a wave. This measurement indicates the length of one complete wave cycle and is significant because it helps determine a wave's properties, like speed.
In the problem, the wavelength of the waves observed by the surfer is given as 34 meters. Knowing the wavelength, in combination with the frequency, allows one to calculate the speed of the waves.
  • The formula for wave speed (v) is expressed as \( v = f \cdot \lambda \), where \(\lambda\) is the wavelength.
  • Longer wavelengths mean that the wave cycles are spread out more, while shorter wavelengths indicate cycles that are closer together.
Understanding the concept of wavelength is key to predicting how a wave will travel through different mediums.
Wave Speed Calculation
Wave speed calculation is the ultimate goal of the given exercise. The speed of a wave signifies how fast the wave travels through a medium, and it is directly dependent on both the frequency and the wavelength of the wave.
Using the formula for wave speed \( v = f \cdot \lambda \), where fis the frequency and \(\lambda\)is the wavelength:
  • The frequency in the problem is 0.233 Hz, and the wavelength is 34 meters.
  • Multiplying these values provides the wave speed.
Through this calculation, \( v = 0.233 \text{ Hz} \times 34 \text{ m} = 7.922 \text{ m/s} \).
This means that each wave travels at a speed of approximately 7.922 meters per second. This understanding is essential, especially in real-world applications such as physics, oceanography, and sound engineering, where precise measurement of wave properties impacts outcomes significantly.

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Most popular questions from this chapter

Two strings that are fixed at cach end are identical, except that one is \(0.560 \mathrm{cm}\) longer than the other. Waves on these strings propagate with a speed of \(34.2 \mathrm{m} / \mathrm{s},\) and the fundamental frequency of the shorter string is \(212 \mathrm{Hz}\). (a) What beat frequency is produced if each string is vibrating with its fundamental frequency? (b) Does the beat frequency in part (a) increase or decrease if the longer string is increased in length? (c) Repeat part (a), assuming that the longer string is \(0.761 \mathrm{cm}\) longer than the shorter string.

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake with a speed of \(2.0 \mathrm{m} / \mathrm{s}\) and a wavelength of \(1.5 \mathrm{m}\). When these waves move into a shallower part of the lake, their speed decreases to \(1.6 \mathrm{m} / \mathrm{s}\), though their frequency remains the same. Find the wavelength of the waves in the shallower water.

A Slinky has a mass of 0.28 kg and negligible length. When it is stretched \(1.5 \mathrm{m},\) it is found that transverse waves travel the length of the Slinky in \(0.75 \mathrm{s}\). (a) What is the force constant, \(k\), of the Slinky? (b) If the Slinky is stretched farther, will the time required for a wave to travel the length of the Slinky increase, decrease, or stay the same? Explain. (c) If the Slinky is stretched \(3.0 \mathrm{m},\) how much time does it take a wave to travel the length of the Slinky? (The Slinky stretches like an ideal spring, and propagates transverse waves like a rope with variable tension.)

Sound 1 has an intensity of \(38.0 \mathrm{W} / \mathrm{m}^{2}\). Sound 2 has an intensity level that is \(2.5 \mathrm{dB}\) greater than the intensity level of sound 1\. What is the intensity of sound \(2 ?\)

The Bullet Train The Shinkansen, the Japanese "bullet" train, runs at high speed from Tokyo to Nagoya. Riding on the Shinkansen, you notice that the frequency of a crossing signal changes markedly as you pass the crossing. As you approach the crossing, the frequency you hear is \(f\); as you recede from the crossing the frequency you hear is \(2 f / 3 .\) What is the speed of the train?

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