/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 A discus thrower starts from res... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A discus thrower starts from rest and begins to rotate with a constant angular acceleration of \(2.2 \mathrm{rad} / \mathrm{s}^{2}\) (a) How many revolutions does it take for the discus thrower's angular speed to reach \(6.3 \mathrm{rad} / \mathrm{s} ?\) (b) How much time does this take?

Short Answer

Expert verified
(a) 1.44 revolutions. (b) 2.86 seconds.

Step by step solution

01

Identify Given Information

We are given an initial angular speed \( \omega_0 = 0 \mathrm{rad/s} \), final angular speed \( \omega = 6.3 \mathrm{rad/s} \), and constant angular acceleration \( \alpha = 2.2 \mathrm{rad/s^2} \). We need to find the number of revolutions and the time taken to reach this speed.
02

Apply Angular Motion Equation for Revolutions

To calculate the number of revolutions, we use the equation: \( \omega^2 = \omega_0^2 + 2\alpha \theta \), where \( \theta \) is the angular displacement in radians. Solving for \( \theta \), we have \( \theta = \frac{\omega^2 - \omega_0^2}{2\alpha} \). Substitute \( \omega = 6.3 \mathrm{rad/s} \), \( \omega_0 = 0 \mathrm{rad/s} \), and \( \alpha = 2.2 \mathrm{rad/s^2} \) to find \( \theta \).
03

Calculate Angular Displacement

Substituting the values: \( \theta = \frac{(6.3)^2 - (0)^2}{2 \times 2.2} = \frac{39.69}{4.4} \approx 9.02 \mathrm{rad} \).
04

Convert Angular Displacement to Revolutions

Convert radians to revolutions using the relationship: \( 1 \text{ revolution} = 2\pi \text{ radians} \). Therefore, the number of revolutions \( N \) is \( N = \frac{9.02}{2\pi} \approx 1.44 \) revolutions.
05

Use Angular Motion Equation for Time

To find the time taken, use the equation: \( \omega = \omega_0 + \alpha t \). Solving for \( t \), we find \( t = \frac{\omega - \omega_0}{\alpha} \). Substitute \( \omega = 6.3 \mathrm{rad/s} \), \( \omega_0 = 0 \mathrm{rad/s} \), and \( \alpha = 2.2 \mathrm{rad/s^2} \) into the equation.
06

Calculate Time Taken

Substitute the values: \( t = \frac{6.3 - 0}{2.2} = \frac{6.3}{2.2} \approx 2.86 \mathrm{seconds} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration refers to how quickly the angular speed of an object changes over time. It is an essential component of rotational motion, similar to how linear acceleration works for objects moving in a straight line.
Angular acceleration is often denoted by the symbol \( \alpha \) and measured in radians per second squared (\( \mathrm{rad/s^2} \)).
In the context of the discus thrower problem, the angular acceleration is given as \( 2.2 \mathrm{rad/s^2} \), which means that for every second, the discus thrower's angular speed increases by \( 2.2 \mathrm{rad/s} \). This constant value allows us to use specific equations of motion to determine other characteristics of the motion, such as angular speed or displacement. By knowing the initial speed, final speed, and angular acceleration, we can calculate how long it takes to reach a certain speed or how far the object has rotated.
Angular Displacement
Angular displacement represents the angle through which an object moves on a circular path. Rather like distance in linear motion, it describes how far an object has turned from its starting point.
In equations, angular displacement is usually represented by the symbol \( \theta \) and is typically measured in radians. Radians are a unit of angular measurement, where \( 2\pi \) radians equal one full revolution (360 degrees).
Using the formula \( \theta = \frac{\omega^2 - \omega_0^2}{2\alpha} \), we can calculate the angular displacement when knowing the angular speed \( \omega \), initial angular speed \( \omega_0 \), and the angular acceleration \( \alpha \).
In our exercise, we calculated \( \theta \) as approximately \( 9.02 \) radians, which shows how far the discus thrower has turned while reaching the given angular speed.
Angular Speed
Angular speed is a measure of how fast something rotates or spins. It tells us the rate at which an object covers an angle in a certain amount of time. This concept is essential when understanding rotational motion.
Angular speed, often denoted by \( \omega \), is measured in radians per second (\( \mathrm{rad/s} \)). This unit helps us understand how quickly an object revolves around a central point.
In the problem about the discus thrower, we have an initial angular speed \( \omega_0 = 0 \mathrm{rad/s} \) because the motion starts from rest, and a final angular speed \( \omega = 6.3 \mathrm{rad/s} \). These values were crucial to find out how many revolutions the discus thrower completes before reaching the final speed and how much time it takes.
Revolutions
Revolutions describe the complete circular turns an object makes. It's a measure often used when discussing rotary motion, providing a straightforward way to talk about how far an object rotates.
One complete revolution equals \( 2\pi \) radians. Sometimes, translating angular displacement in radians to revolutions helps simplify understanding the concept of how much an object has turned.
  • We use the relationship \( N = \frac{\theta}{2\pi} \) to convert from radians to revolutions.
  • In exercises involving angular motion, knowing how many revolutions have occurred can offer valuable insights, especially in applications like mechanics and engineering.

Discussing the discus thrower problem, we concluded that the angular displacement of \( 9.02 \) radians is equivalent to approximately \( 1.44 \) revolutions. This lets us visualize how much the thrower rotates.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The world's tallest building is the Taipei 101 Tower in Taiwan, which rises to a height of \(508 \mathrm{m}(1667 \mathrm{ft})\). (a) When standing on the top floor of the building, is your angular speed due to the Earth's rotation greater than, less than, or equal to your angular speed when you stand on the ground floor? (b) Choose the hest explanation from among the following: I. The angular speed is the same at all distances from the axis of rotation. II. At the top of the building you are farther from the axis of rotation and hence you have a greater angular speed. III. You are spinning faster when you are closer to the axis of rotation.

A compact disk (CD) speeds up uniformly from rest to 310 rpm in \(3.3 \mathrm{s}\). (a) Describe a strategy that allows you to calculate the number of revolutions the CD makes in this time. (b) Use your strategy to find the number of revolutions.

A child pedals a tricycle, giving the driving wheel an angular speed of 0.373 rev \(/ \mathrm{s}\) (Figure \(10-20)\). If the radius of the wheel is \(0.260 \mathrm{m},\) what is the child's linear speed?

Suppose a bicycle wheel is rotated about an axis through its rim and parallel to its axle. (a) Is its moment of inertia about this axis greater than, less than, or equal to its moment of inertia about its axle? (b) Choose the best explanation from among the following: I. The moment of inertia is greatest when an object is rotated about its center. II. The mass and shape of the wheel remain the same. III. Mass is farther from the axis when the wheel is rotated about the rim.

The following angles are given in radians. Convert them to degrees: \(\pi / 6,0.70 \pi, 1.5 \pi, 5 \pi\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.