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The world's tallest building is the Taipei 101 Tower in Taiwan, which rises to a height of \(508 \mathrm{m}(1667 \mathrm{ft})\). (a) When standing on the top floor of the building, is your angular speed due to the Earth's rotation greater than, less than, or equal to your angular speed when you stand on the ground floor? (b) Choose the hest explanation from among the following: I. The angular speed is the same at all distances from the axis of rotation. II. At the top of the building you are farther from the axis of rotation and hence you have a greater angular speed. III. You are spinning faster when you are closer to the axis of rotation.

Short Answer

Expert verified
(a) Angular speed is equal at both heights. (b) Explanation I is correct.

Step by step solution

01

Understand Angular Speed

Angular speed, \(\omega\), is defined as the rate of change of angular displacement and is given by the formula \(\omega\,=\,\frac{v}{r}\) where \(v\) represents linear speed and \(r\) the radius from the axis of rotation. Importantly, angular speed for any object completing a rotation remains constant irrespective of its distance from the axis of rotation.
02

Compare Angular Speed at Different Heights

When standing on the Taipei 101 Tower, you are indeed at a greater radius from the Earth's axis of rotation than when you are on the ground. However, since Earth rotates as a rigid body, everyone on its surface has the same angular speed regarding Earth's rotation irrespective of their height above the ground. Thus, even if you are at a higher elevation on the tower, the angular speed remains consistent at all heights.
03

Evaluate Explanations

Explanation I states that the angular speed is the same at all distances from the axis of rotation, which aligns with our understanding of Earth’s rotation. Explanation II incorrectly suggests that angular speed increases with distance from the axis, and Explanation III incorrectly suggests that angular speed decreases with distance from the axis. Therefore, the correct explanation is I.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's rotation
Earth's rotation is a fascinating phenomenon that results in day and night on our planet. Imagine Earth as a giant spinning ball. As it rotates, different parts of Earth face the Sun, bringing daylight, while the other side is in darkness, experiencing night. This rotation occurs around an imaginary line called the axis, which runs from the North Pole to the South Pole. For a more precise understanding, Earth's rotation is consistent in its angular speed, meaning it turns at the same rate all the time. This is measured in a unit called radians per second. Quite incredibly, Earth's angular speed is about 0.0000727 radians per second. This constant speed is why it roughly takes 24 hours to complete one full rotation. When considering locations on Earth, regardless of whether you are at sea level or atop a tall building like Taipei 101, your angular speed due to Earth's rotation doesn't change. You and the building both rotate at the same rate along with the Earth's surface.
rigid body rotation
Rigid body rotation refers to the spinning motion of a solid object where all points in the object move in circular paths centered on a single axis. Picture a merry-go-round; as it spins, every part of the ride moves around the axis at the same rate without bending or distorting. This is a classic example of rigid body rotation. Earth behaves like a giant rigid body in terms of its rotation. Despite being made up of oceans, mountains, and diverse landscapes, it rotates as though it were a solid object. Every point on Earth's surface rotates around the axis at the same angular speed. This concept is crucial to understand why, when you stand at different heights above Earth, your angular rotation speed remains constant. No matter if you're on the ground or on top of Taipei 101, you rotate with the Earth as one rigid body.
angular displacement
Angular displacement describes the change in angle as an object rotates around a specific point or axis. Imagine opening a book. As you turn a page, you’re creating angular displacement. The page takes a curved path, changing its angle relative to its original position. In terms of Earth's rotation, as our planet spins, different points on its surface experience angular displacement. However, everyone's angular speed, or the rate of that displacement, remains unchanged due to Earth's rigid body rotation. Thus, even as you move higher up a building like Taipei 101, the angular displacement over a given time doesn't vary; you still complete the same degree of rotation as anyone on ground level. The concept of angular displacement helps explain why, regardless of your elevation on Earth's surface, you experience the same cycle of day turning into night as anyone else.

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Most popular questions from this chapter

A \(12-g\) CD with a radius of \(6.0 \mathrm{cm}\) rotates with an angular speed of 34 rad / s. (a) What is its kinetic energy? (b) What angular speed must the CD have if its kinetic energy is to be doubled?

The angle an airplane propeller makes with the horizontal as a function of time is given by \(\theta=(125 \mathrm{rad} / \mathrm{s}) \mathrm{t}+\) \(\left(42.5 \mathrm{rad} / \mathrm{s}^{2}\right) t^{2}\) (a) Estimate the instantaneous angular velocity at \(t=0.00\) s by calculating the average angular velocity from \(t=0.00 \mathrm{s}\) to \(t=0.010 \mathrm{s}\) (b) Estimate the instantaneous angular velocity at \(t=1.000 \mathrm{s}\) by calculating the average angular velocity from \(t=1.000 \mathrm{s}\) to \(t=1.010 \mathrm{s}\) (c) Estimate the instantaneous angular velocity at \(t=2.000\) s by calculating the average angular velocity from \(t=2.000 \mathrm{s}\) to \(t=2.010 \mathrm{s}\) (d) Based on your results from parts (a), (b), and (c), is the angular acceleration of the propeller positive, negative, or zero? Explain. (e) Calculate the average angular acceleration from \(f=0.00 \mathrm{s}\) to \(t=1.00 \mathrm{s}\) and from \(t=1.00 \mathrm{s}\) to \(t=2.00 \mathrm{s}\).

A 2.5-kg solid sphere (radius \(=0.10 \mathrm{m}\) ) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is \(0.75 \mathrm{m}\) high and \(5.6 \mathrm{m}\) long. When the sphere reaches the bottom of the ramp, what are (a) its total kinetic energy, (b) its rotational kinetic energy, and (c) its translational kinetic energy?

A 1.3 -kg block is tied to a string that is wrapped a round the rim of a pulley of radius \(7.2 \mathrm{cm}\). The block is released from rest. (a) Assuming the pulley is a uniform disk with a mass of \(0.31 \mathrm{kg},\) find the speed of the block after it has fallen through a height of \(0.50 \mathrm{m}\). (b) If a small lead weight is attached near the rim of the pulley and this experiment is repeated, will the speed of the block increase, decrease, or stay the same? Explain.

An object at rest begins to rotate with a constant angular acceleration. If the angular speed of the object is \(\omega\) after the time \(t,\) what was its angular speed at the time \(t / 2 ?\)

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