/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 An engine pulls a train of 20 fr... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 88

An engine pulls a train of 20 freight cars, each having a mass of $5.0 \times 10^{4} \mathrm{kg}$ with a constant force. The cars move from rest to a speed of \(4.0 \mathrm{m} / \mathrm{s}\) in \(20.0 \mathrm{s}\) on a straight track. Ignoring friction, what is the force with which the 10th car pulls the 11th one (at the middle of the train)? (school bus)

Short Answer

Expert verified
Answer: The force with which the 10th car pulls the 11th car is \(1.0 \times 10^5\) N.

Step by step solution

01

Calculate the acceleration of the train.

First, let's find the acceleration of the train using the given data: Initial velocity (u) = 0 m/s (since the train starts at rest) Final velocity (v) = 4.0 m/s Time (t) = 20.0 s We can use the equation: v = u + a*t We can plug in the values and solve for 'a': 4.0 m/s = 0 + a*(20.0 s) a = 0.2 m/s^2 The acceleration of the train is 0.2 m/s虏.
02

Calculate the total mass of the train.

Now, let's calculate the total mass of the train: Number of freight cars = 20 Mass of each freight car = \(5.0 \times 10^4\) kg Total mass of the train (M) = Number of freight cars * Mass of each freight car M = 20 * \(5.0 \times 10^4\) kg = \(1.0 \times 10^6\) kg.
03

Calculate the total force acting on the train.

Using Newton's second law of motion, we can calculate the total force exerted on the train: Force (F) = Total mass (M) * Acceleration (a) F = \(1.0 \times 10^6\) kg * 0.2 m/s虏 F = \(2.0 \times 10^5\) N
04

Calculate the force between the 10th and 11th freight cars.

Since there are 20 freight cars in the train and we are looking for the force between cars 10 and 11, we can calculate the force on one half of the train (10 cars). Since the force is uniformly distributed, we can divide the total force by 2: Force between the 10th and 11th car = Total Force / 2 Force between the 10th and 11th car = \(2.0 \times 10^5\) N / 2 Force between the 10th and 11th car = \(1.0 \times 10^5\) N The force with which the 10th car pulls the 11th one is \(1.0 \times 10^5\) N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A hanging potted plant is suspended by a cord from a hook in the ceiling. Draw an FBD for each of these: (a) the system consisting of plant, soil, and pot; (b) the cord; (c) the hook; (d) the system consisting of plant, soil, pot, cord, and hook. Label each force arrow using subscripts (for example, \(\overrightarrow{\mathbf{F}}_{\mathrm{ch}}\) would represent the force exerted on the cord by the hook).
You grab a book and give it a quick push across the top of a horizontal table. After a short push, the book slides across the table, and because of friction, comes to a stop. (a) Draw an FBD of the book while you are pushing it. (b) Draw an FBD of the book after you have stopped pushing it, while it is sliding across the table. (c) Draw an FBD of the book after it has stopped sliding. (d) In which of the preceding cases is the net force on the book not equal to zero? (e) If the book has a mass of \(0.50 \mathrm{kg}\) and the coefficient of friction between the book and the table is \(0.40,\) what is the net force acting on the book in part (b)? (f) If there were no friction between the table and the book, what would the free-body diagram for part (b) look like? Would the book slow down in this case? Why or why not?
You are standing on a bathroom scale inside an elevator. Your weight is 140 lb, but the reading of the scale is \(120 \mathrm{lb} .\) (a) What is the magnitude and direction of the acceleration of the elevator? (b) Can you tell whether the elevator is speeding up or slowing down?
Before hanging new William Morris wallpaper in her bedroom, Brenda sanded the walls lightly to smooth out some irregularities on the surface. The sanding block weighs \(2.0 \mathrm{N}\) and Brenda pushes on it with a force of $3.0 \mathrm{N}\( at an angle of \)30.0^{\circ}$ with respect to the vertical, and angled toward the wall. Draw an FBD for the sanding block as it moves straight up the wall at a constant speed. What is the coefficient of kinetic friction between the wall and the block?
A crate full of artichokes rests on a ramp that is inclined \(10.0^{\circ}\) above the horizontal. Give the direction of the normal force and the friction force acting on the crate in each of these situations. (a) The crate is at rest. (b) The crate is being pushed and is sliding up the ramp. (c) The crate is being pushed and is sliding down the ramp.
See all solutions

Recommended explanations on Physics Textbooks

Nuclear Physics

Read Explanation

Space Physics

Read Explanation

Classical Mechanics

Read Explanation

Modern Physics

Read Explanation

Medical Physics

Read Explanation

Linear Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.