/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 A crate full of artichokes rests... [FREE SOLUTION] | 91影视

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Chapter 4: Problem 54

A crate full of artichokes rests on a ramp that is inclined \(10.0^{\circ}\) above the horizontal. Give the direction of the normal force and the friction force acting on the crate in each of these situations. (a) The crate is at rest. (b) The crate is being pushed and is sliding up the ramp. (c) The crate is being pushed and is sliding down the ramp.

Short Answer

Expert verified
Answer: The normal force always acts perpendicular to the ramp, making an angle of \(10.0^{\circ}\) with the horizontal. The friction force opposes the motion of the crate: when the crate is at rest, it acts upward along the ramp; when the crate is sliding up the ramp, it acts down the ramp; and when the crate is sliding down the ramp, it acts up the ramp.

Step by step solution

01

Situation (a) - The crate is at rest.

When the crate is at rest, the forces on it must be balanced in both the horizontal and vertical directions. The normal force acts perpendicular to the ramp and therefore makes an angle of \(10.0^{\circ}\) with the horizontal. The friction force opposes the potential motion of the crate (which would be downwards), so it acts in a direction opposite to that, which is upward along the ramp.
02

Situation (b) - The crate is being pushed and is sliding up the ramp.

When the crate is being pushed and sliding up the ramp, the normal force again acts perpendicular to the ramp, making an angle of \(10.0^{\circ}\) with the horizontal. However, for this scenario, the friction force acts in a direction opposite to the motion of the crate, which is down the ramp.
03

Situation (c) - The crate is being pushed and is sliding down the ramp.

When the crate is being pushed and sliding down the ramp, the normal force still acts perpendicular to the ramp, making an angle of \(10.0^{\circ}\) with the horizontal. The frictional force opposes the motion of the crate and acts in the direction opposite to that of the crate's motion, which is up the ramp. In summary, the direction of the normal force is always perpendicular to the ramp and makes an angle of \(10.0^{\circ}\) with the horizontal. The direction of the friction force depends on the motion of the crate and will act to oppose the direction of the crate's motion, either up or down the ramp.

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Most popular questions from this chapter

An \(80.0-\mathrm{N}\) crate of apples sits at rest on a ramp that runs from the ground to the bed of a truck. The ramp is inclined at \(20.0^{\circ}\) to the ground. (a) What is the normal force exerted on the crate by the ramp? (b) The interaction partner of this normal force has what magnitude and direction? It is exerted by what object on what object? Is it a contact or a long-range force? (c) What is the static frictional force exerted on the crate by the ramp? (d) What is the minimum possible value of the coefficient of static friction? (e) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. Find the magnitude and direction of the contact force.
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