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A man weighs \(0.80 \mathrm{kN}\) on Earth. What is his mass in kilograms?

Short Answer

Expert verified
The man's mass is approximately 81.55 kg.

Step by step solution

01

Understand the relationship between weight and mass

Weight is the force exerted by gravity on an object. It is related to mass by the equation: \( W = m \cdot g \), where \( W \) is the weight in newtons (N), \( m \) is the mass in kilograms (kg), and \( g \) is the acceleration due to gravity. On Earth, \( g \) is approximately \( 9.81 \mathrm{m/s^2} \).
02

Write the equation for the situation

Given the weight of the man is \( 0.80 \mathrm{kN} \), which is the same as \( 800 \mathrm{N} \) (since \( 1 \mathrm{kN} = 1000 \mathrm{N} \)). Use the equation \( W = m \cdot g \) to relate the weight and mass: \( 800 = m \cdot 9.81 \).
03

Solve for mass \( m \)

Rearrange the equation \( 800 = m \cdot 9.81 \) to solve for \( m \): \( m = \frac{800}{9.81} \). Calculate this to find \( m \approx 81.55 \mathrm{kg} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law of Motion is a fundamental principle in physics that explains the relationship between the motion of an object and the forces acting upon it. According to this law, the force applied to an object is equal to the mass of the object multiplied by its acceleration: \[ F = m \cdot a \] Where \( F \) is the force measured in newtons (N), \( m \) is the mass in kilograms (kg), and \( a \) is the acceleration in meters per second squared (m/s²).
  • When a force is applied to an object, it causes the object to accelerate, changing its speed or direction.
  • The larger the mass of the object, the more force is needed to achieve the same acceleration.
For example, if we want to understand how gravity affects a person standing on Earth, we consider their weight (the force of gravity on them). This weight is also calculated using Newton’s second law, where the force of gravity \( W \) equals mass \( m \) times the acceleration due to gravity \( g \). This concept is crucial when converting weight into mass, especially in exercises like finding a man's mass based on his weight.
Acceleration due to Gravity
The acceleration due to gravity, often represented as \( g \), is the rate at which objects accelerate towards the Earth when falling freely in a vacuum with no air resistance. On Earth, the value of \( g \) is approximately \( 9.81 \text{ m/s}^2 \). This means any object in free fall will accelerate at this rate, making it a constant factor in many physics calculations.
  • Gravity is a universal force of attraction that acts between all mass in the universe.
  • The standardized value of \( 9.81 \text{ m/s}^2 \) is used for calculations involving gravitational force on Earth's surface.
Understanding this concept helps us relate weight and mass through the equation \( W = m \cdot g \). Once we know the weight of an object and the acceleration due to gravity, we can calculate the mass. This is especially useful for converting the weight of objects, like people, into mass units like kilograms.
Unit Conversion
Unit conversion is essential for solving physics problems as it ensures consistency in calculations. In physics, different quantities have specific units and often need to be translated into one another to apply formulas correctly. When dealing with forces, such as weight, converting units like kilonewtons (kN) to newtons (N) is necessary because equations usually utilize the base unit of newtons for force:
  • 1 kilonewton equals 1,000 newtons.
  • Knowing this conversion allows us to rephrase the weight from high-level units like kN to N for precise calculations.
For example, converting a man's weight from \(0.80 \text{kN}\) to \(800 \text{N}\) is crucial to properly apply the weight-mass relation formula \( W = m \cdot g \). This conversion allows us to compute mass accurately. Mastery of unit conversions supports solving complex physics tasks and ensures the accuracy of results across different scenarios.

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Most popular questions from this chapter

A crate full of artichokes rests on a ramp that is inclined \(10.0^{\circ}\) above the horizontal. Give the direction of the normal force and the friction force acting on the crate in each of these situations. (a) The crate is at rest. (b) The crate is being pushed and is sliding up the ramp. (c) The crate is being pushed and is sliding down the ramp.
A rope is attached from a truck to a \(1400-\mathrm{kg}\) car. The rope will break if the tension is greater than \(2500 \mathrm{N}\) Ignoring friction, what is the maximum possible acceleration of the truck if the rope does not break? Should the driver of the truck be concerned that the rope might break?
A man is lazily floating on an air mattress in a swimming pool. If the weight of the man and air mattress together is \(806 \mathrm{N},\) what is the upward force of the water acting on the mattress?
An astronaut stands at a position on the Moon such that Earth is directly over head and releases a Moon rock that was in her hand. (a) Which way will it fall? (b) What is the gravitational force exerted by the Moon on a 1.0 -kg rock resting on the Moon's surface? (c) What is the gravitational force exerted by the Earth on the same 1.0 -kg rock resting on the surface of the Moon? (d) What is the net gravitational force on the rock?
Four identical spring scales, \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) are used to hang a \(220.0-\mathrm{N}\) sack of potatoes. (a) Assume the scales have negligible weights and all four scales show the same reading. What is the reading of each scale? (b) Suppose that each scale has a weight of \(5.0 \mathrm{N} .\) If scales \(\mathrm{B}\) and \(\mathrm{D}\) show the same reading, what is the reading of each scale?
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