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Chapter 14: Problem 9

Convert \(1.00 \mathrm{kJ}\) to kilowatt-hours \((\mathrm{kWh})\).

Short Answer

Expert verified
Question: Convert 1.00 kJ (kilojoule) to kilowatt-hours (kWh). Answer: 1.00 kJ is approximately equal to \(2.78 \times 10^{-4}\, \mathrm{kWh}\).

Step by step solution

01

Convert kJ to J

First, we need to convert the given energy value in kJ to J (joules). Since 1 kJ equals 1000 J, then we have: \(1.00\, \mathrm{kJ} = 1.00 * 1000\, \mathrm{J} = 1000\, \mathrm{J}\)
02

Convert J to kWh

Now that we have the energy value in J, we can use the conversion factor to convert it to kWh. As we know, 1 kWh = 3,600,000 J. To find the equivalent value in kWh, we can divide the value in joules by 3600000: \(1000\, \mathrm{J} \times \dfrac{1\, \mathrm{kWh}}{3,600,000\, \mathrm{J}}\) An easy way to do this step is to cancel out the units and perform the calculation: \(\dfrac{1000\, \mathrm{J}}{3,600,000\, \mathrm{J}} \times 1\, \mathrm{kWh} = \dfrac{1}{3600}\, \mathrm{kWh}\)
03

Simplify the Answer

Finally, we can simplify the expression and write the answer as: \(\dfrac{1}{3600}\, \mathrm{kWh} \approx 2.78 \times 10^{-4}\, \mathrm{kWh}\) So, 1.00 kJ is approximately equal to \(2.78 \times 10^{-4}\, \mathrm{kWh}\).

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Most popular questions from this chapter

A piece of gold of mass \(0.250 \mathrm{kg}\) and at a temperature of \(75.0^{\circ} \mathrm{C}\) is placed into a \(1.500-\mathrm{kg}\) copper pot containing \(0.500 \mathrm{L}\) of water. The pot and water are at $22.0^{\circ} \mathrm{C}$ before the gold is added. What is the final temperature of the water?
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Imagine a person standing naked in a room at \(23.0^{\circ} \mathrm{C}\) The walls are well insulated, so they also are at \(23.0^{\circ} \mathrm{C}\) The person's surface area is \(2.20 \mathrm{m}^{2}\) and his basal metabolic rate is 2167 kcal/day. His emissivity is \(0.97 .\) (a) If the person's skin temperature were \(37.0^{\circ} \mathrm{C}\) (the same as the internal body temperature), at what net rate would heat be lost through radiation? (Ignore losses by conduction and convection.) (b) Clearly the heat loss in (a) is not sustainable-but skin temperature is less than internal body temperature. Calculate the skin temperature such that the net heat loss due to radiation is equal to the basal metabolic rate. (c) Does wearing clothing slow the loss of heat by radiation, or does it only decrease losses by conduction and convection? Explain.
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