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Chapter 14: Problem 80

Many species cool themselves by sweating, because as the sweat evaporates, heat is given up to the surroundings. A human exercising strenuously has an evaporative heat loss rate of about \(650 \mathrm{W}\). If a person exercises strenuously for 30.0 min, how much water must he drink to replenish his fluid loss? The heat of vaporization of water is \(2430 \mathrm{J} / \mathrm{g}\) at normal skin temperature.

Short Answer

Expert verified
Answer: The person must drink approximately 481.48 g (or 0.481 L) of water to replenish the fluid loss.

Step by step solution

01

Calculate the total heat lost

To find the total heat lost, we'll use the formula: Total Heat Lost = Evaporative Heat Loss Rate 脳 Time We are given Evaporative Heat Loss Rate = 650 W and Time = 30 min (which needs to be converted to seconds). So, Time in seconds = 30 脳 60 = 1800 s. Now, we can calculate the total heat lost: Total Heat Lost = 650 W 脳 1800 s = 1170000 J (Joules)
02

Calculate the amount of water needed

Now that we have the total heat lost, we can use the heat of vaporization to find out the amount of water needed. We are given the heat of vaporization of water as 2430 J/g. So, we'll use the formula: Amount of Water = Total Heat Lost / Heat of Vaporization of Water Amount of Water = 1170000 J / (2430 J/g) = 481.481481 g To replenish the fluid loss, the person must drink approximately 481.48 g (or 0.481 L) of water.

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Most popular questions from this chapter

A hotel room is in thermal equilibrium with the rooms on either side and with the hallway on a third side. The room loses heat primarily through a 1.30 -cm- thick glass window that has a height of \(76.2 \mathrm{cm}\) and a width of $156 \mathrm{cm} .\( If the temperature inside the room is \)75^{\circ} \mathrm{F}$ and the temperature outside is \(32^{\circ} \mathrm{F}\), what is the approximate rate (in \(\mathrm{kJ} / \mathrm{s}\) ) at which heat must be added to the room to maintain a constant temperature of \(75^{\circ} \mathrm{F} ?\) Ignore the stagnant air layers on either side of the glass.
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Consider the leaf of Problem \(70 .\) Assume that the top surface of the leaf absorbs \(70.0 \%\) of \(9.00 \times 10^{2} \mathrm{W} / \mathrm{m}^{2}\) of radiant energy, while the bottom surface absorbs all of the radiant energy incident on it due to its surroundings at \(25.0^{\circ} \mathrm{C} .\) (a) If the only method of heat loss for the leaf were thermal radiation, what would be the temperature of the leaf? (Assume that the leaf radiates like a blackbody.) (b) If the leaf is to remain at a temperature of \(25.0^{\circ} \mathrm{C}\) how much power per unit area must be lost by other methods such as transpiration (evaporative heat loss)?
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