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A solid cylindrical disk has a radius of \(0.15 \mathrm{m}\). It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a \(45-N\) force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of \(120 \mathrm{rad} / \mathrm{s}^{2} .\) What is the mass of the disk?

Short Answer

Expert verified
The mass of the disk is 5 kg.

Step by step solution

01

Understanding the Problem

We have a solid cylindrical disk with a known radius and we need to find its mass. A tangential force produces a given angular acceleration. We'll use these to derive the mass.
02

Identify Known Quantities

From the problem, we know:- Radius (\( r \)) = 0.15 m- Force (\( F \)) = 45 N- Angular acceleration (\( \alpha \)) = 120 rad/s²
03

Calculate Torque

Torque (\( \tau \)) is given by the formula: \[ \tau = F \times r \]Substituting the known values:\[ \tau = 45 \times 0.15 = 6.75 \, \text{Nm} \]
04

Relate Torque to Angular Acceleration

The torque is also related to the moment of inertia (\( I \)) and angular acceleration by:\[ \tau = I \times \alpha \]Substitute known values for \( \tau \) and \( \alpha \):\[ 6.75 = I \times 120 \]
05

Solve for Moment of Inertia

Solve for \( I \):\[ I = \frac{6.75}{120} = 0.05625 \text{ kg} \cdot \text{m}^2 \]
06

Moment of Inertia of a Solid Cylinder

For a solid cylinder, the moment of inertia is:\[ I = \frac{1}{2} m r^2 \]We already found \( I \) and know \( r \). Substitute these values:\[ 0.05625 = \frac{1}{2} m (0.15)^2 \]
07

Solve for Mass

Rearrange and solve for \( m \):\[ m = \frac{0.05625}{0.5 \times 0.0225} = 5 \text{ kg} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration is a measure of how quickly the rotational speed of an object changes. It's analogous to linear acceleration. In this exercise, angular acceleration is given as 120 rad/s², a measure indicating rapid rotational change.

When a force is applied to a rotating body, it not only causes a change in speed but also changes the object’s angular velocity. Angular acceleration (\( \alpha \)) is calculated by dividing the change in angular velocity by the time over which the change occurs:

  • \( \alpha = \frac{\Delta \omega}{\Delta t} \)
In the context of a cylindrical disk, this is affected by how large the force is and where it is applied, specifically, perpendicular to the radius.

When dealing with angular motion, increasing force or decreasing the radius can increase angular acceleration, given the moment of inertia remains constant. Understanding this interplay helps us determine other properties of the rotating system, like the moment of inertia or mass, as seen in this solution.
Moment of Inertia
The moment of inertia is a critical concept in rotational dynamics, representing how much torque is needed for a desired angular acceleration about a particular axis of rotation.

It's comparable to mass in linear motion, indicating how much resistance an object will have against changes in its rotational motion. For a cylindrical disk, the formula for the moment of inertia (\( I \)) is given by:
  • \( I = \frac{1}{2} m r^2 \)
Where:

  • \( m \) is the mass of the disk
  • \( r \) is the radius of the disk
In this particular exercise, we calculate the moment of inertia as 0.05625 kg·m², using the measured angular acceleration and applied torque. By rearranging the moment of inertia equation, we can solve for mass after computing torque and knowing the radius and angular acceleration.
  • The moment of inertia equation shows the relationship between the mass and how the mass is distributed around the axis, especially in determining rotational dynamics of the disk.
  • Understanding this concept helps in identifying how objects will behave when set into rotational motion, whether it's a simple disk or a complex mechanical system.
    Cylindrical Disk
    A cylindrical disk is a symmetrical, flat, rounded object which often acts as a classic study model in physics for simplifying rotational problems. In our exercise, the disk has a radius of 0.15 meters.

    This disk's symmetry and uniform mass distribution allow for easier calculation of its moment of inertia and understanding its rotational dynamics. When calculating these properties, we're considering it being mounted to an axle at the center, perpendicular to its circular face, allowing it to rotate in a neat, predictable manner.

    With the disk's radius being part and parcel to many equations in rotational dynamics, such as those for torque as \( \tau = F \times r \) and moment of inertia \( I = \frac{1}{2} m r^2 \), knowing the disk's geometry is crucial for solving problems.
    • The application of force at a tangential point means it is at the edge of this disk, maximizing the effect to induce rotation.
    • Understanding a cylindrical disk's properties extends to practical scenarios, like wheels, pulleys, and more, ensuring broader comprehension of rotational systems.
    Studying a cylindrical disk gives insight into many practical applications seen in engineering and physics, illustrating fundamental principles of rotary motion and energy transformation.

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    Most popular questions from this chapter

    As seen from above, a playground carousel is rotating counter-clockwise about its center on frictionless bearings. A person standing still on the ground grabs onto one of the bars on the carousel very close to its outer edge and climbs aboard. Thus, this person begins with an angular speed of zero and ends up with a nonzero angular speed, which means that he underwent a counterclockwise angular acceleration. The carousel has a radius of \(1.50 \mathrm{m},\) an initial angular speed of \(3.14 \mathrm{rad} / \mathrm{s},\) and a moment of inertia of \(125 \mathrm{kg} \cdot \mathrm{m}^{2} .\) The mass of the person is \(40.0 \mathrm{kg} .\) Find the final angular speed of the carousel after the person climbs aboard.

    Two spheres are each rotating at an angular speed of \(24 \mathrm{rad} / \mathrm{s}\) about axes that pass through their centers. Each has a radius of \(0.20 \mathrm{m}\) and a mass of 1.5 kg. However, as the figure shows, one is solid and the other is a thin-walled spherical shell. Suddenly, a net external torque due to friction (magnitude \(=0.12 \mathrm{N} \cdot \mathrm{m}\) ) begins to act on each sphere and slows the motion down. Concepts: (i) Which sphere has the greater moment of inertia and why? (ii) Which sphere has the angular acceleration (a deceleration) with the smaller magnitude? (iii) Which sphere takes a longer time to come to a halt? Calculations: How long does it take each sphere to come to a halt?

    A hiker, who weighs \(985 \mathrm{N}\), is strolling through the woods and crosses a small horizontal bridge. The bridge is uniform, weighs \(3610 \mathrm{N}\), and rests on two concrete supports, one at each end. He stops one-fifth of the way along the bridge. What is the magnitude of the force that a concrete support exerts on the bridge (a) at the near end and (b) at the far end?

    Multiple-Concept Example 10 provides one model for solving this type of problem. Two wheels have the same mass and radius of \(4.0 \mathrm{kg}\) and \(0.35 \mathrm{m}\), respectively. One has the shape of a hoop and the other the shape of a solid disk. The wheels start from rest and have a constant angular acceleration with respect to a rotational axis that is perpendicular to the plane of the wheel at its center. Each turns through an angle of 13 rad in 8.0 s. Find the net external torque that acts on each wheel.

    The drawing shows a rectangular piece of wood. The forces applied to corners \(\mathrm{B}\) and \(\mathrm{D}\) have the same magnitude of \(12 \mathrm{N}\) and are directed parallel to the long and short sides of the rectangle. The long side of the rectangle is twice as long as the short side. An axis of rotation is shown perpendicular to the plane of the rectangle at its center. A third force (not shown in the drawing) is applied to corner A, directed along the short side of the rectangle (either toward \(\mathrm{B}\) or away from \(\mathrm{B}\) ), such that the piece of wood is at equilibrium. Find the magnitude and direction of the force applied to corner A.

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