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A basketball \((m=0.60 \mathrm{kg})\) is dropped from rest. Just before striking the floor, the ball has a momentum whose magnitude is \(3.1 \mathrm{kg} \cdot \mathrm{m} / \mathrm{s} .\) At what height was the basketball dropped?

Short Answer

Expert verified
The basketball was dropped from approximately 1.36 meters.

Step by step solution

01

Understand the Problem

We need to find the height from which a basketball (mass = 0.60 kg) was dropped given that its momentum just before hitting the ground is 3.1 kgâ‹…m/s. We'll use physical principles involving momentum and the mechanics of free-fall to solve this.
02

State Given and Unknown Values

Given: mass of the basketball (\(m = 0.60\) kg), momentum just before impact (\(p = 3.1\) kgâ‹…m/s). Unknown: height from which the ball was dropped (\(h\)).
03

Formula for Momentum

The momentum \(p\) can be expressed as the product of mass \(m\) and velocity \(v\): \(p = mv\). Rearrange this to find the velocity \(v\): \(v = \frac{p}{m}\).
04

Calculate Velocity

Substitute the given values into the equation \(v = \frac{p}{m}\) to calculate the velocity of the ball just before impact. \(v = \frac{3.1}{0.60} = 5.1667\, \mathrm{m/s}\).
05

Use Energy Conservation Principle

Use the conservation of energy principle, where the potential energy at the height \(h\) is equal to the kinetic energy just before impact: \(mgh = \frac{1}{2}mv^2\). Here, \(g = 9.8\, \mathrm{m/s^2}\) is the acceleration due to gravity.
06

Cancel Out the Mass and Solve for Height

The masses (\(m\)) on both sides can be cancelled out, leading to \(gh = \frac{1}{2} v^2\). Solve for \(h\) to get \(h = \frac{v^2}{2g}\).
07

Calculate Height

Substitute the value of \(v = 5.1667\, \mathrm{m/s}\) and \(g = 9.8\, \mathrm{m/s^2}\) into the equation: \(h = \frac{(5.1667)^2}{2 \times 9.8}\). Thus, \(h \approx 1.36\, \mathrm{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free-Fall Mechanics
When we talk about free-fall mechanics, we're focusing on the motion of an object subject only to gravitational force. Imagine dropping a basketball. Initially, it has no velocity because it's at rest. As it falls, gravity speeds it up by approximately 9.8 meters per second squared. This is the acceleration due to gravity, often denoted as "g."

  • The ball starts from rest with an initial speed of 0 m/s.
  • Gravity is the sole force acting on it, pulling it downward.
  • As it falls, the ball gains speed until just before hitting the ground it reaches its final velocity.

In free-fall, air resistance is often neglected to simplify calculations. This means we assume the only factor changing the speed of the ball is gravity. By knowing the final velocity of the basketball before it hits the floor, we can determine the height from which it fell, leveraging the kinematics of free-fall.
Conservation of Energy
The conservation of energy is a principle stating that energy cannot be created or destroyed in an isolated system. In the context of our problem, we consider two main types of mechanical energy: potential energy and kinetic energy. As the basketball falls, its potential energy is converted into kinetic energy.

  • Initially, the ball has maximum potential energy and zero kinetic energy.
  • As the ball descends, its potential energy decreases while its kinetic energy increases.
  • Right before impact, all the potential energy has been transformed into kinetic energy.

The formula representing this conversion is:\[mgh = \frac{1}{2}mv^2\]Here "\(mgh\)" is the potential energy at the top, "\(\frac{1}{2}mv^2\)" is the kinetic energy just before impact, \(m\) is the mass, \(g\) is the acceleration due to gravity, \(h\) is the initial height, and \(v\) is the final velocity. Understanding how energy transforms helps us find the height the ball was dropped from.
Potential Energy
Potential energy is the energy stored in an object due to its position relative to others, stresses within itself, its electric charge, or other factors. In the case of the basketball, it refers specifically to gravitational potential energy due to its height above the ground.

  • Gravitational potential energy is given by the formula \(PE = mgh\), where \(m\) is mass, \(g\) is the acceleration due to gravity, and \(h\) is the height.
  • This form of energy is dependent on the height of the object. Higher it is, greater the potential energy.
  • As the basketball falls, this stored energy is gradually converted into kinetic energy.

Potential energy plays a crucial role in determining how much work an object can do because it's essentially trapped energy waiting to be transformed. In our problem, by determining the initial potential energy, we can understand how high the basketball started before it began its descent.

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Most popular questions from this chapter

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