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A car (mass \(=1100 \mathrm{kg}\) ) is traveling at \(32 \mathrm{m} / \mathrm{s}\) when it collides head-on with a sport utility vehicle (mass \(=2500 \mathrm{kg}\) ) traveling in the opposite direction. In the collision, the two vehicles come to a halt. At what speed was the sport utility vehicle traveling?

Short Answer

Expert verified
The SUV was traveling at approximately 14.08 m/s.

Step by step solution

01

Identify the principle involved

This problem involves the principle of conservation of momentum. In a closed system where no external forces act, the total momentum before the collision is equal to the total momentum after the collision.
02

Set up the conservation of momentum equation

Momentum is given by the product of mass and velocity. The equation for the conservation of momentum before the collision can be written as: \[ m_1 imes v_1 + m_2 imes v_2 = 0 \]where \(m_1 = 1100 \, \text{kg}\), \(v_1 = 32 \, \text{m/s}\) (car's velocity), and \(m_2 = 2500 \, \text{kg}\), \(v_2\) is the unknown velocity of the SUV.
03

Calculate the momentum of the car

Substitute the known values for the car into the momentum equation:\[1100 \, \text{kg} \times 32 \, \text{m/s} = 35200 \, \text{kg} \cdot \text{m/s}\]This is the momentum of the car moving in the initial direction.
04

Calculate the momentum of the SUV

Since the total momentum must be zero (the vehicles come to a halt), the momentum of the SUV must counterbalance the momentum of the car. Thus, the momentum of the SUV is:\[-2500 \, \text{kg} \times v_2 = 35200 \, \text{kg} \cdot \text{m/s}\]
05

Solve for the SUV's velocity

Divide both sides of the equation by the mass of the SUV to solve for \(v_2\):\[v_2 = \frac{35200}{2500} = 14.08 \, \text{m/s}\]The negative sign in the momentum indicates that the direction of the SUV's velocity is opposite to that of the car's initial direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Calculation
Momentum is a fundamental concept in physics, rooted in the conservation of energy and motion. It describes the quantity of motion an object possesses and is dependent on both mass and velocity.
In formula terms, it is expressed as:
  • P = m × v
where P is the momentum, m is mass, and v is velocity.
Calculating the momentum of an object involves these variables and gives a sense of how hard it might be to stop an object in motion. This directs us to understanding the behavior of bodies in collisions and how their motions will result in a transfer of momentum. In a collision scenario like the one provided, each object's momentum before the collision sums up to the total system momentum. In our exercise, the car's significant mass and velocity imply it carries a considerable momentum of 35200 kg·m/s.
Head-on Collision
Head-on collisions are a specific type of contact scenario where two objects collide while moving directly toward one another. In such cases, each object's momentum contributes to the system's total momentum.
During these events, the key principle is that the total momentum in the system remains conserved if no external forces intervene. That means the combined momentum of the car and the SUV before the collision equals the momentum after the collision.
In our exercise, both vehicles come to a halt, indicating their combined momentum is zero post-collision, meaning their pre-collision momenta must perfectly balance one another to satisfy the conservation principle.
This balance means:
  • The car's forward momentum would be equal in magnitude but opposite in direction to the SUV's backward momentum.
Such insights highlight how predictably and neatly physics governs collisions.
Velocity Determination
Determining the velocity of an object in a collision, especially in head-on ones, involves leveraging the conservation of momentum.
In our scenario, the problem states that the combined momentum of both the car and the SUV post-collision is zero. This directly allows us to calculate the unknown velocity of the SUV using:
  • Conservation Equation: The momentum from the car is cancelled by the momentum from the SUV.
  • \[ -2500 \, \text{kg} \times v_2 = -35200 \, \text{kg} \cdot \text{m/s} \]
Solving this equation involves isolating the unknown velocity variable \(v_2\) on one side of the equation:
  • \[ v_2 = \frac{-35200}{-2500} = 14.08 \, \text{m/s} \]
This solution reveals the speed at which the SUV must have been traveling; the negative sign was addressed earlier, indicating the SUV moved in the opposite direction of the car's motion pre-collision.

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Most popular questions from this chapter

A model rocket is constructed with a motor that can provide a total impulse of \(29.0 \mathrm{N} \cdot\) s. The mass of the rocket is \(0.175 \mathrm{kg} .\) What is the speed that this rocket achieves when launched from rest? Neglect the effects of gravity and air resistance.

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