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The following table lists data for the speed and radius of three examples of uniform circular motion. Find the magnitude of the centripetal acceleration for each example. $$ \begin{array}{lcc} & \text { Radius } & \text { Speed } \\ \hline \text { Example 1 } & 0.50 \mathrm{m} & 12 \mathrm{m} / \mathrm{s} \\ \hline \text { Example 2 } & \text { Infinitely large } & 35 \mathrm{m} / \mathrm{s} \\ \hline \text { Example 3 } & 1.8 \mathrm{m} & 2.3 \mathrm{m} / \mathrm{s} \\ \hline \end{array} $$

Short Answer

Expert verified
1) 288 m/s², 2) 0 m/s², 3) 2.94 m/s².

Step by step solution

01

Understanding the Formula

To find the centripetal acceleration \( a_c \), use the formula: \[ a_c = \frac{v^2}{r} \] where \( v \) is the speed and \( r \) is the radius of the circular path.
02

Calculating Centripetal Acceleration for Example 1

For Example 1, the radius \( r = 0.50 \) m and the speed \( v = 12 \) m/s. Substitute these values into the formula: \[ a_c = \frac{12^2}{0.50} = \frac{144}{0.50} = 288 \text{ m/s}^2 \]
03

Calculating Centripetal Acceleration for Example 2

For Example 2, the radius is infinitely large, implying the path is straight. In this case, the centripetal acceleration is \( 0 \), because no force pulls the object inward.
04

Calculating Centripetal Acceleration for Example 3

For Example 3, the radius \( r = 1.8 \) m and the speed \( v = 2.3 \) m/s. Substitute these values into the formula: \[ a_c = \frac{2.3^2}{1.8} \approx \frac{5.29}{1.8} \approx 2.94 \text{ m/s}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Circular Motion
Uniform circular motion refers to the movement of an object along a circular path at a constant speed. Although the speed remains constant, the velocity is not constant because its direction changes continuously as the object moves along the circle. Velocity is a vector quantity, which means it has both magnitude (speed) and direction. The constant change in direction is what gives rise to acceleration, even if the speed does not change.
In uniform circular motion, specific properties are associated with this type of motion, such as:
  • The path of the object is a perfect circle.
  • The speed of the object does not vary with time.
  • Despite constant speed, the object experiences acceleration because of the continual change in direction.
The object is constantly being "pulled" or changing direction towards the center of the circle. This pull is due to the centripetal force, which we will discuss in the next section.
Centripetal Force
Centripetal force is the inward force necessary to keep an object moving in a circular path. Without it, the object would move off in a straight line due to inertia. This force acts perpendicular to the velocity of the object and towards the center of the circular path.
Some examples of centripetal force in action are:
  • The tension in the string of a tetherball that keeps the ball moving in a circle.
  • The gravitational pull acting as the centripetal force that keeps planets in orbit around the sun.
  • The friction between a car's tires and the road that allows it to turn in a circular path.
Centripetal force is crucial for maintaining an object's circular motion by continually pulling the object back towards the central point of the motion. It sustains the circular motion by altering the object's direction rather than its speed, thereby causing centripetal acceleration.
Physics Formulas
In physics, formulas allow us to quantify relationships between physical quantities. For the case of uniform circular motion, centripetal acceleration (\( a_c \) ) is given by the formula:\[ a_c = \frac{v^2}{r} \]Here:
  • \( v \) is the object's speed in meters per second (m/s).
  • \( r \) is the radius of the circular path in meters.
This formula helps us understand how the speed of the object and the radius of its path affect its acceleration. For instance:
  • Increasing the speed will increase the centripetal acceleration.
  • Decreasing the radius will also increase the centripetal acceleration, assuming the speed remains constant.
Understanding these relationships is vital in solving problems related to circular motion, as seen in the calculation steps described earlier. Grasping these formulas not only helps solve textbook problems, but also provides insight into real-world physics scenarios involving circular motion.

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Most popular questions from this chapter

On a banked race track, the smallest circular path on which cars can move has a radius of \(112 \mathrm{m},\) while the largest has a radius of \(165 \mathrm{m},\) as the drawing illustrates. The height of the outer wall is \(18 \mathrm{m}\). Find \((\mathrm{a})\) the smallest and (b) the largest speed at which cars can move on this track without relying on friction.

A stone is tied to a string (length \(=1.10 \mathrm{m}\) ) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is nearly parallel to the ground. Next, the circle is vertical. In the vertical case the maximum tension in the string is \(15.0 \%\) larger than the tension that exists when the circle is horizontal. Determine the speed of the stone.

A centrifuge is a device in which a small container of material is rotated at a high speed on a circular path. Such a device is used in medical laboratories, for instance, to cause the more dense red blood cells to settle through the less dense blood serum and collect at the bottom of the container. Suppose the centripetal acceleration of the sample is \(6.25 \times 10^{3}\) times as large as the acceleration due to gravity. How many revolutions per minute is the sample making, if it is located at a radius of \(5.00 \mathrm{cm}\) from the axis of rotation?

Ball A is attached to one end of a rigid massless rod, while an identical ball B is attached to the center of the rod, as shown in the figure. Each ball has a mass of \(m=0.50 \mathrm{kg}\), and the length of each half of the rod is \(L=0.40 \mathrm{m} .\) This arrangement is held by the empty end and is whirled around in a horizontal circle at a constant rate, so that each ball is in uniform circular motion. Ball A travels at a constant speed of \(v_{A}=5.0 \mathrm{m} / \mathrm{s} .\) Concepts: (i) How many tension forces contribute to the centripetal force that acts on ball A? (ii) How many tension forces contribute to the centripetal force that acts on ball B? (iii) Is the speed of ball A the same as that of ball B? Calculations: Find the tension in each half of the rod.

How long does it take a plane, traveling at a constant speed of \(110 \mathrm{m} / \mathrm{s},\) to fly once around a circle whose radius is \(2850 \mathrm{m} ?\)

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