/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 A car travels at a constant spee... [FREE SOLUTION] | 91Ó°ÊÓ

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A car travels at a constant speed around a circular track whose radius is \(2.6 \mathrm{km}\). The car goes once around the track in \(360 \mathrm{s}\). What is the magnitude of the centripetal acceleration of the car?

Short Answer

Expert verified
The centripetal acceleration is approximately 0.792 m/s².

Step by step solution

01

Calculate the Circumference of the Track

The first step is to find the circumference of the circular track. The formula for the circumference \( C \) of a circle is \( C = 2\pi r \), where \( r \) is the radius. Here, \( r = 2.6 \text{ km} = 2600 \text{ m} \). Therefore, the circumference is:\[ C = 2 \pi \times 2600 \text{ m} = 5200 \pi \text{ m} \approx 16336.42 \text{ m}. \]
02

Calculate the Speed of the Car

Next, we calculate the speed \( v \) of the car. Since the car travels the circumference of the track in \( 360 \) seconds, the speed is the total distance divided by the time. Thus,\[ v = \frac{16336.42 \text{ m}}{360 \text{ s}} \approx 45.38 \text{ m/s}. \]
03

Apply the Formula for Centripetal Acceleration

Finally, we use the formula for centripetal acceleration, which is \( a_c = \frac{v^2}{r} \), where \( v \) is the speed and \( r \) is the radius. We already found \( v = 45.38 \text{ m/s} \) and \( r = 2600 \text{ m} \). Substituting in these values gives:\[ a_c = \frac{(45.38 \text{ m/s})^2}{2600 \text{ m}} \approx 0.792 \text{ m/s}^2. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
When an object moves along a circular path, it experiences what is known as circular motion. Circular motion is exhibited by any object that revolves around a central point. In our example, the car travels around a track that forms a complete circle. This type of motion can be observed in everyday situations, like a satellite orbiting the Earth or a roller coaster looping the loops. In circular motion, there is a continuous change in the direction of the object's velocity, even if the speed remains constant. This change in direction is due to a force acting towards the center of the circle, called centripetal force. It keeps the object in its circular path. A key aspect of circular motion is the centripetal acceleration, which is directed towards the center of the circle and ensures that the object maintains its curved path.
Constant Speed
Constant speed is a concept often encountered in physics, where an object covers equal distances in equal intervals of time, without changing the rate of motion. This means the speed does not vary as the object moves. In the context of circular motion, even if an object like our car keeps its speed constant at 45.38 m/s, its velocity is not constant because velocity includes both speed and direction. Thus, while the magnitude of the car's speed remains unchanged, its velocity is continuously changing because its direction is constantly altering as it moves around the circle. This change in direction is what causes the necessity for centripetal acceleration.
Radius of Circle
The radius of a circle is the distance from its center to any point on the circle itself. In circular motion problems, the radius plays a crucial role in determining both the circumference of the circle and the centripetal acceleration of the object in motion.For our car traveling around a track with a radius of 2.6 km, converting this length into meters gives us 2600 m. This radius is instrumental in calculating the track's circumference, using the formula \( C = 2\pi r \). Furthermore, the radius is also a key variable in the formula for centripetal acceleration, \( a_c = \frac{v^2}{r} \), indicating how centripetal acceleration depends inversely on the radius. Thus, a larger radius with the same speed results in a smaller centripetal acceleration, highlighting the fundamental influence of the circle's radius on motion dynamics.

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Most popular questions from this chapter

A centrifuge is a device in which a small container of material is rotated at a high speed on a circular path. Such a device is used in medical laboratories, for instance, to cause the more dense red blood cells to settle through the less dense blood serum and collect at the bottom of the container. Suppose the centripetal acceleration of the sample is \(6.25 \times 10^{3}\) times as large as the acceleration due to gravity. How many revolutions per minute is the sample making, if it is located at a radius of \(5.00 \mathrm{cm}\) from the axis of rotation?

\(\mathrm{A}\) satellite has a mass of \(5850 \mathrm{kg}\) and is in a circular orbit \(4.1 \times\) \(10^{5} \mathrm{m}\) above the surface of a planet. The period of the orbit is \(2.00 \mathrm{hours}\). The radius of the planet is \(4.15 \times 10^{6} \mathrm{m} .\) What would be the true weight of the satellite if it were at rest on the planet's surface?

A stone is tied to a string (length \(=1.10 \mathrm{m}\) ) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is nearly parallel to the ground. Next, the circle is vertical. In the vertical case the maximum tension in the string is \(15.0 \%\) larger than the tension that exists when the circle is horizontal. Determine the speed of the stone.

A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius \(r .\) A passenger feels the seat of the car pushing upward on her with a force equal to twice her weight as she goes through the dip. If \(r=20.0 \mathrm{m},\) how fast is the roller coaster traveling at the bottom of the dip?

The aorta is a major artery, rising upward from the left ventricle of the heart and curving down to carry blood to the abdomen and lower half of the body. The curved artery can be approximated as a semicircular arch whose diameter is \(5.0 \mathrm{cm} .\) If blood flows through the aortic arch at a speed of \(0.32 \mathrm{m} / \mathrm{s}\) what is the magnitude (in \(\mathrm{m} / \mathrm{s}^{2}\) ) of the blood's centripetal acceleration?

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