/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 A billiard ball strikes and rebo... [FREE SOLUTION] | 91Ó°ÊÓ

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A billiard ball strikes and rebounds from the cushion of a pool table perpendicularly. The mass of the ball is 0.38 kg. The ball approaches the cushion with a velocity of \(+2.1 \mathrm{m} / \mathrm{s}\) and rebounds with a velocity of \(-2.0 \mathrm{m} / \mathrm{s} .\) The ball remains in contact with the cushion for a time of \(3.3 \times 10^{-3}\) s. What is the average net force (magnitude and direction) exerted on the ball by the cushion?

Short Answer

Expert verified
The average net force exerted on the ball is approximately \(-239.39\) N.

Step by step solution

01

Determine Initial Momentum

Calculate the initial momentum of the billiard ball by multiplying its mass by its initial velocity. The formula for momentum is given by \( p = m \times v \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. For the initial condition: \( p_{\text{initial}} = 0.38 \text{ kg} \times (+2.1 \text{ m/s}) \).
02

Determine Final Momentum

Calculate the final momentum of the billiard ball by using the same formula, with the final velocity instead. \( p_{\text{final}} = 0.38 \text{ kg} \times (-2.0 \text{ m/s}) \).
03

Calculate Change in Momentum

Find the change in momentum using \( \Delta p = p_{\text{final}} - p_{\text{initial}} \). Substitute the values from the previous steps to get \( \Delta p = 0.38 \times (-2.0) - 0.38 \times (+2.1) \).
04

Apply Impulse-Momentum Theorem

The Impulse-Momentum Theorem states that \( F_{\text{avg}} \times \Delta t = \Delta p \), where \( F_{\text{avg}} \) is the average net force and \( \Delta t \) is the time interval. Rearrange to solve for \( F_{\text{avg}} = \frac{\Delta p}{\Delta t} \). Use \( \Delta p \) from the previous step and \( \Delta t = 3.3 \times 10^{-3} \text{ s} \).
05

Calculate Average Net Force

Substitute \( \Delta p \) and \( \Delta t \) values into the formula for \( F_{\text{avg}} \) to find the average net force. Calculate: \( F_{\text{avg}} = \frac{0.38 \times (-2.0 - 2.1)}{3.3 \times 10^{-3}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in physics, describing the motion of an object. Momentum depends on two factors: the mass of the object and its velocity. It is calculated using the formula \[ p = m \times v \]where:
  • \( p \) represents momentum,
  • \( m \) is the mass of the object in kilograms,
  • \( v \) is the velocity of the object in meters per second.

In our exercise, the billiard ball has a mass of 0.38 kg. To find the momentum before hitting the cushion, use the initial velocity of \( +2.1 \mathrm{m}/\mathrm{s} \). Calculate the initial momentum:\[ p_{\text{initial}} = 0.38 \text{ kg} \times (+2.1 \text{ m/s}) = 0.798 \text{ kg m/s} \]After rebounding, the velocity changes to \(-2.0 \mathrm{m}/\mathrm{s} \). Calculate the final momentum:\[ p_{\text{final}} = 0.38 \text{ kg} \times (-2.0 \text{ m/s}) = -0.76 \text{ kg m/s} \]
Understanding momentum helps in grasping how objects move and how forces affect their motion. Knowing the initial and final momenta is crucial for calculating any change in momentum.
Average Net Force
The average net force is the constant force that would produce the same change in an object's momentum over a given time period as produced by the actual variable force. It is related to the impulse experienced by the object and thus to the change in momentum.On the billiard ball, to find the average net force exerted by the cushion, we use the change in momentum and the time during which the ball was in contact with the cushion. The impulse-momentum theorem links these concepts with the equation:\[ F_{\text{avg}} \times \Delta t = \Delta p \]
Here, \( F_{\text{avg}} \) is the average net force, \( \Delta t \) is the time interval, and \( \Delta p \) is the change in momentum.By rearranging, we solve for the average net force:\[ F_{\text{avg}} = \frac{\Delta p}{\Delta t} \]
In the exercise, \( \Delta t \) is \( 3.3 \times 10^{-3} \text{ s} \). By calculating the change in momentum using the initial and final momenta, we can determine the average net force applied on the ball by the cushion.
Change in Momentum
Change in momentum is a critical concept for understanding how collisions and interactions affect objects. It is calculated by subtracting the initial momentum from the final momentum, expressed as:\[ \Delta p = p_{\text{final}} - p_{\text{initial}} \]
This change is often a result of external forces acting on the object.In the context of our exercise, the billiard ball's momentum changes when it strikes and rebounds off the cushion. To find this change:
  • Initial momentum was \( 0.798 \text{ kg m/s} \).
  • Final momentum is \(-0.76 \text{ kg m/s} \).

Thus, the change in momentum is calculated as:\[ \Delta p = -0.76 \text{ kg m/s} - 0.798 \text{ kg m/s} = -1.558 \text{ kg m/s} \]
The negative sign indicates the direction change caused by the cushion. By understanding this change, we can calculate the force exerted and analyze how the billiard ball's motion is influenced by the collision with the cushion.

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Most popular questions from this chapter

Air rushing over the wings of high-performance race cars generates unwanted horizontal air resistance but also causes a vertical down-force, which helps the cars hug the track more securely. The coefficient of static friction between the track and the tires of a 690-kg race car is 0.87. What is the magnitude of the maximum acceleration at which the car can speed up without its tires slipping when a 4060-N downforce and an 1190-N horizontal-air- resistance force act on it?

An electron is a subatomic particle \(\left(m=9.11 \times 10^{-31} \mathrm{kg}\right)\) that is subject to electric forces. An electron moving in the \(+x\) direction accelerates from an initial velocity of \(+5.40 \times 10^{5} \mathrm{m} / \mathrm{s}\) to a final velocity of \(+2.10 \times 10^{6} \mathrm{m} / \mathrm{s}\) while traveling a distance of \(0.038 \mathrm{m} .\) The electron's acceleration is due to two electric forces parallel to the \(x\) axis: \(\overrightarrow{\mathbf{F}}_{1}=+7.50 \times 10^{-17} \mathrm{N},\) and \(\overrightarrow{\mathbf{F}}_{2}\) which points in the \(-x\) direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force \(\overrightarrow{\mathbf{F}}_{2}.\)

A 35-kg crate rests on a horizontal floor, and a 65-kg person is standing on the crate. Determine the magnitude of the normal force that (a) the floor exerts on the crate and (b) the crate exerts on the person.

The figure shows two forces, \(\overrightarrow{\mathbf{F}}_{1}=+3000 \mathrm{N}\) and \(\overrightarrow{\mathbf{F}}_{2}=+5000 \mathrm{N},\) acting on a spacecraft; the plus signs indicate that the forces are directed along the \(+x\) axis. A third force \(\overrightarrow{\mathbf{F}}_{3}\) also acts on the spacecraft but is not shown in the drawing. Concepts: (i) Suppose the spacecraft were stationary. What would be the direction of \(\overrightarrow{\mathbf{F}}_{3} ?\) (ii) When the spacecraft is moving at a constant velocity of \(+850 \mathrm{m} / \mathrm{s},\) what is the direction of \(\overrightarrow{\mathbf{F}}_{3} ?\) Calculations: Find the direction and magnitude of \(\overrightarrow{\mathbf{F}}_{3}\).

A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne 129-kg laser sensor that measures the thickness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude \(2.84 \mathrm{m} / \mathrm{s}^{2}\). Ignoring air resistance, find the tension in the cable towing the sensor.

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