/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 An electron is a subatomic parti... [FREE SOLUTION] | 91Ó°ÊÓ

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An electron is a subatomic particle \(\left(m=9.11 \times 10^{-31} \mathrm{kg}\right)\) that is subject to electric forces. An electron moving in the \(+x\) direction accelerates from an initial velocity of \(+5.40 \times 10^{5} \mathrm{m} / \mathrm{s}\) to a final velocity of \(+2.10 \times 10^{6} \mathrm{m} / \mathrm{s}\) while traveling a distance of \(0.038 \mathrm{m} .\) The electron's acceleration is due to two electric forces parallel to the \(x\) axis: \(\overrightarrow{\mathbf{F}}_{1}=+7.50 \times 10^{-17} \mathrm{N},\) and \(\overrightarrow{\mathbf{F}}_{2}\) which points in the \(-x\) direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force \(\overrightarrow{\mathbf{F}}_{2}.\)

Short Answer

Expert verified
Net force is approximately \(3.28 \times 10^{-17} \mathrm{N}\). Force \(F_2\) is \(-4.22 \times 10^{-17}\) N.

Step by step solution

01

Calculate the acceleration

To find the acceleration, we can use the kinematic equation \( v_f^2 = v_i^2 + 2a \cdot d \), where \( v_f \) is the final velocity, \( v_i \) is the initial velocity, and \( d \) is the distance traveled. By rearranging the formula for acceleration, we get:\[a = \frac{v_f^2 - v_i^2}{2d}\]Substitute \( v_f = 2.10 \times 10^6 \ \text{m/s} \), \( v_i = 5.40 \times 10^5 \ \text{m/s} \), and \( d = 0.038 \ \text{m} \) into the equation:\[a = \frac{(2.10 \times 10^6)^2 - (5.40 \times 10^5)^2}{2 \times 0.038}\]Calculate this to find the acceleration.
02

Calculate the net force on the electron

Using Newton's second law \( F_{\text{net}} = m \cdot a \), where \( m \) is the mass of the electron and \( a \) is the acceleration, we can calculate the net force. Substitute \( m = 9.11 \times 10^{-31} \ \text{kg} \) and the acceleration calculated in Step 1.\[F_{\text{net}} = 9.11 \times 10^{-31} \times a\]Evaluate this expression to find the net force \( F_{\text{net}} \) on the electron.
03

Calculate the electric force F2

We know from Newton's second law that the net force is the sum of individual forces acting on the electron. Given \( F_1 = +7.50 \times 10^{-17} \ \text{N} \), the net force \( F_{\text{net}} = F_1 + F_2 \), where \( F_2 \) is in the \(-x\) direction, so it is subtracted.Rearrange to solve for \( F_2 \):\[F_2 = F_{\text{net}} - F_1\]Substitute the value of \( F_{\text{net}} \) from Step 2 and \( F_1 \) to find \( F_2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Motion
Electrons are subatomic particles with a negative charge and very small mass, approximately \(9.11 \times 10^{-31} \text{ kg}\). They play a crucial role in electricity and chemical bonding. Their motion is often influenced by electric forces, which can cause them to accelerate or change direction. In scenarios where forces are present, like the one described in the exercise, the electron moves due to the net effect of these forces. The net force determines the acceleration and consequently how fast the electron's velocity changes. Electric forces are typically described as vectors, having both magnitude and direction. In the case of this exercise, the electron experiences forces along the \(x\)-axis, which affect its motion in that direction only. When examining electron motion, it's important to consider both the forces acting on the particle and its resulting behavior or change in velocity.
Kinematic Equations
Kinematic equations are fundamental in physics for describing motion with constant acceleration. They allow us to connect quantities such as initial and final velocities, acceleration, distance, and time. In the exercise above, the kinematic equation used is \( v_f^2 = v_i^2 + 2a \cdot d \). This equation links the final velocity \( v_f \), initial velocity \( v_i \), acceleration \( a \), and distance \( d \). When using this equation, we can solve for any one of these variables if the other three are known.
By rearranging the equation, you can solve for acceleration, as shown in the solution, by expressing acceleration as \(a = \frac{v_f^2 - v_i^2}{2d}\). Understanding these equations helps in predicting how an object's motion will evolve over time, especially under constant forces like gravity or electric fields.
Newton's Second Law
Newton's Second Law of Motion is pivotal for understanding how objects respond to forces. It states that the net force acting on an object is equal to the product of its mass and acceleration: \( F_{\text{net}} = m \cdot a \). This law explains how forces influence motion and is essential in predicting how an object will accelerate in response to the net force.
In the context of the exercise, you'd use Newton's Second Law to find the net force on the electron after determining its acceleration. With the mass of the electron known, the force can be calculated simply by multiplying its mass by the acceleration. This calculated net force can then be broken down into component forces, like in the exercise, helping us understand the various influences on the electron's motion. This principle not only helps in complex calculations but also forms the basis for understanding much of classical mechanics.

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Most popular questions from this chapter

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