Chapter 31: Problem 39
The number of radioactive nuclei present at the start of an experiment is \(4.60 \times 10^{15} .\) The number present twenty days later is \(8.14 \times 10^{14}\) What is the half-life (in days) of the nuclei?
Short Answer
Expert verified
The half-life is approximately 8.98 days.
Step by step solution
01
Identify the Given Information
We have the initial amount of nuclei as \( N_0 = 4.60 \times 10^{15} \) and the remaining number of nuclei after 20 days as \( N = 8.14 \times 10^{14} \). We are asked to find the half-life, denoted as \( t_{1/2} \).
02
Use the Exponential Decay Formula
The exponential decay of radioactive nuclei is given by the formula: \[ N = N_0 \times e^{-\lambda t},\]where \( N \) is the remaining number of nuclei, \( N_0 \) is the initial number of nuclei, \( t \) is the time elapsed, and \( \lambda \) is the decay constant. Let \( t = 20 \) days.
03
Solve for Decay Constant \( \lambda \)
Rearrange the equation to solve for \( \lambda \): \[ \lambda = \frac{1}{t} \ln\left(\frac{N_0}{N}\right).\]Substitute \( t = 20 \), \( N_0 = 4.60 \times 10^{15} \), and \( N = 8.14 \times 10^{14} \) into the equation:\[ \lambda = \frac{1}{20} \ln\left(\frac{4.60 \times 10^{15}}{8.14 \times 10^{14}}\right).\]Calculate this to find \( \lambda \).
04
Use the Formula for Half-life
The half-life is related to the decay constant by the formula:\[ t_{1/2} = \frac{\ln(2)}{\lambda}.\]Once \( \lambda \) is calculated, substitute it into this formula to find \( t_{1/2} \).
05
Calculate and Simplify
Substitute \( \lambda \) into the half-life formula we derived:\[ t_{1/2} = \frac{\ln(2)}{\lambda}.\]Compute this value to find the half-life in days.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-life calculation
Radioactive decay is a random process where unstable atomic nuclei lose energy by emitting radiation. The half-life of a radioactive substance is a crucial concept that describes the time it takes for half of the radioactive nuclei in a sample to decay. To find the half-life (\( t_{1/2} \)) of a substance, one can use the decay constant with the formula:
- \( t_{1/2} = \frac{\ln(2)}{\lambda} \)
Exponential decay formula
Exponential decay is a mathematical concept widely used in physics to model how quantities decrease over time, especially when described as a percentage of the current amount. The exponential decay formula for radioactive nuclei is mathematically defined as:
- \( N = N_0 \times e^{-\lambda t} \)
Decay constant
The decay constant (\( \lambda \)) is a fundamental parameter in the study of radioactive decay. It quantifies the stability of a radioactive substance. In essence, it tells us the probability of decay of a single nucleus per unit time. Higher values of \( \lambda \) indicate a faster decay process, and thus a shorter half-life, whereas smaller \( \lambda \) values correlate with slower decay processes.In our exercise, we calculated the decay constant by rearranging the exponential decay formula:
- \( \lambda = \frac{1}{t} \ln\left(\frac{N_0}{N}\right) \)