Chapter 31: Problem 22
$$\text { Find the energy that is released when a nucleus of lead }{ }_{ 82}^{211} \text {} \mathrm{Pb} \text { (atomic mass } $$$$ \begin{aligned} &\text { }=210.988735 \text { u) undergoes } \beta^{-} \text {decay to become bismuth }{ }_{83}^{211} \mathrm{Bi} \text { (atomic mass }\\\ &\text { }=210.987255 \mathrm{u}). \end{aligned}$$
Short Answer
Step by step solution
Understanding Beta Decay
Apply the Atomic Mass Change
Calculate Mass Defect
Convert Mass Defect to Energy
Calculate and Present the Energy
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