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A projectile is launched from ground level at an angle of \(12.0^{\circ}\) above the horizontal. It returns to ground level. To what value should the launch angle be adjusted, without changing the launch speed, so that the range doubles?

Short Answer

Expert verified
The launch angle should be adjusted to approximately \( 27.3^{\circ} \).

Step by step solution

01

Review the Range Formula

The range \( R \) of a projectile launched at an angle \( \theta \) is given by the formula: \[ R = \frac{v^2 \sin(2\theta)}{g} \] where \( v \) is the launch speed, \( \theta \) is the launch angle, and \( g \) is the acceleration due to gravity.
02

Express the Condition for Doubling the Range

If the range is to be doubled, we set \( R' = 2R \). This implies: \[ \frac{v^2 \sin(2\theta')}{g} = 2 \times \frac{v^2 \sin(2\theta)}{g} \] After simplifying, we get \( \sin(2\theta') = 2 \sin(2\theta) \).
03

Calculate the Sine of Initial and Target Angles

For the given angle \( \theta = 12.0^{\circ} \), first convert it to radians: \( 12.0^{\circ} = 0.2094 \text{ radians} \). Then calculate \( \sin(2\times0.2094) \approx \sin(0.4188) \approx 0.4067 \). Now, we need to find \( \theta' \) such that \( \sin(2\theta') = 2 \times 0.4067 = 0.8134 \).
04

Determine the New Angle \( \theta' \)

To find \( \theta' \), solve \( \sin(2\theta') = 0.8134 \). The inverse sine gives us \( 2\theta' = \arcsin(0.8134) \approx 0.9522 \text{ radians} \). Thus, \( \theta' = \frac{0.9522}{2} \approx 0.4761 \text{ radians} \), which is approximately \( 27.3^{\circ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Range Formula
The range of a projectile is a crucial aspect of projectile motion. It represents the horizontal distance traveled by the projectile. To find this range, we can make use of a special formula in physics. This formula is:\[R = \frac{v^2 \sin(2\theta)}{g}\]where:
  • \( R \) is the range
  • \( v \) is the initial velocity or launch speed of the projectile
  • \( \theta \) is the launch angle of the projectile
  • \( g \) is the acceleration due to gravity, which is approximately \( 9.8 \text{ m/s}^2 \) on Earth
This formula is essential in understanding how different angles and speeds impact the distance a projectile can travel. By changing any of these values, you can observe how the range is affected.
Launch Angle
The launch angle (\( \theta \)) is the angle at which a projectile is fired or launched with respect to the horizontal. This angle plays a significant role in determining the path of the projectile. A higher launch angle means the projectile will travel more vertically before coming back down, while a lower angle results in a more horizontal trajectory. For any given launch speed, the angle of launch affects how far the projectile will travel.In general, an optimal angle for maximum range on level ground is \( 45^\circ \), but practical scenarios may demand different angles. Adjusting the angle can change the nature of a projectile's flight, affecting both range and height.
Sine Function
The sine function is a trigonometric function that is fundamental to solving problems involving angles, such as projectile motion. In the range formula, the sine function is used with double the launch angle \( \sin(2\theta) \). This is due to trigonometric identities that relate to how angles operate in a circular manner. The sine function helps us translate angular information into practical measures of distance that a projectile can travel. Understanding the role of \( \sin(2\theta) \) is critical, as it affects the outcome of the range, showing how mathematical concepts are directly applied in physical motion.
Projectile Range Doubling
To double the range of a projectile without altering the initial speed means adjusting the launch angle such that the new angle affects the distance in the desired way.Using the range formula \( R = \frac{v^2 \sin(2\theta)}{g} \), if the goal is to have \( R' = 2R \), this implies\[\sin(2\theta') = 2 \sin(2\theta)\]This means finding a new angle \( \theta' \) that results in this doubled sine value, giving the projectile double the range. Solving for this requires the use of trigonometric identities and understanding of inverse trigonometric functions for accurate results. A precise understanding of these changes helps predict projectile behavior accurately in practical applications.

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