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Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of \(4.0 \mathrm{m} / \mathrm{s} .\) Neil is in front of her. With respect to the ground, Neil is skating due west at a speed of \(3.2 \mathrm{m} / \mathrm{s} .\) Find Neil's velocity (magnitude and direction relative to due west), as seen by Barbara.

Short Answer

Expert verified
Neil's relative velocity as seen by Barbara is approximately 5.12 m/s at 51.3° north of west.

Step by step solution

01

Identify the Components

To solve this problem, consider the velocities of Barbara and Neil in terms of vector components. Barbara's velocity is directed south at 4.0 m/s, so its vector is \( \mathbf{v}_B = (0, -4.0) \) in the \(xy\)-plane, where \(x\) points east and \(y\) points north. Neil's velocity vector is \( \mathbf{v}_N = (-3.2, 0) \), as he is moving west.
02

Determine Relative Velocity

The relative velocity of Neil with respect to Barbara, \( \mathbf{v}_{N/B} \), is found by subtracting Barbara's velocity from Neil's. So, \( \mathbf{v}_{N/B} = \mathbf{v}_N - \mathbf{v}_B = (-3.2, 0) - (0, -4.0) = (-3.2, 4.0) \). This vector represents Neil's velocity as seen by Barbara.
03

Calculate Magnitude of Relative Velocity

The magnitude of the relative velocity vector is calculated using the Pythagorean theorem: \( |\mathbf{v}_{N/B}| = \sqrt{(-3.2)^2 + (4.0)^2} = \sqrt{10.24 + 16} = \sqrt{26.24} \approx 5.12 \mathrm{m/s} \).
04

Determine Direction of Relative Velocity

To find the direction of Neil's relative velocity as seen by Barbara, calculate the angle \( \theta \) between the negative \(x\)-axis (due west) and the velocity vector \( \mathbf{v}_{N/B} \). Use the tangent function: \( \tan\theta = \frac{4.0}{3.2} \). Thus, \( \theta = \arctan(\frac{4.0}{3.2}) \approx 51.3^\circ \). This angle is north of west.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
In the realm of physics, analyzing the motion of objects often requires breaking down their movements into simpler parts called vector components. These components essentially represent how much of a vector points in certain directions. For example, in the original exercise, both Barbara's and Neil's velocities were expressed in vector form.

  • Barbara's skating south was expressed as a vector: \( \mathbf{v}_B = (0, -4.0) \). This indicates no movement in the east-west direction (x-axis), but a movement southward (negative y-axis).
  • Neil's movement was represented as \( \mathbf{v}_N = (-3.2, 0) \), showing movement in the westward direction (negative x-axis) and none in the north-south direction (y-axis).
Breaking down movement into vector components helps solve problems by turning complex motions into manageable parts, making it easier to perform operations like addition and subtraction of vectors.
Pythagorean Theorem
The Pythagorean theorem is a mathematical principle used to relate the lengths of the sides of a right triangle. In the context of velocity vectors, it's employed to find the magnitude of a resulting vector that arises from two perpendicular components.

To compute Neil's relative velocity magnitude, we use the theorem:\[ |\mathbf{v}_{N/B}| = \sqrt{(-3.2)^2 + (4.0)^2} = \sqrt{10.24 + 16} = \sqrt{26.24} \approx 5.12 \, \mathrm{m/s} \]This calculation shows that the length of the vector representing Neil's speed relative to Barbara is approximately 5.12 m/s. The Pythagorean theorem is crucial in physics for transforming components into an overall magnitude, enhancing our understanding of net effects in movements or forces.
Tangent Function
The tangent function is a trigonometric function that relates the angles of a right triangle to the ratio of its opposite and adjacent sides. It's particularly useful when needing to find angles in vector-related problems.

For example, to determine the angle of Neil's velocity as perceived by Barbara, we utilize the tangent function:\[\tan\theta = \frac{4.0}{3.2}\]This relates the north-south movement (4.0, opposite side) to the east-west movement (3.2, adjacent side), allowing us to calculate the angle \( \theta \):\[\theta = \arctan\left(\frac{4.0}{3.2}\right) \approx 51.3^\circ\]Using the tangent function, we can convert vector components into meaningful angles, providing insight into the direction of a vector relative to a reference axis.
Direction of Velocity
Understanding the direction of velocity is key in many vector-related problems, as it tells us the specific orientation in which an object is moving. Vector components help ascertain the precise direction by providing insight into how vectors combine in two dimensions.

In this instance, by determining the angle Neil's movement forms with the negative x-axis (due west), using the tangent function, we find that \( \theta \) is approximately 51.3 degrees north of west.
  • The direction is evaluated from a known axis—in this case, due west—and adjusted based on the computed angle.
  • Knowing the direction is useful for visualizing and planning the course of motion in practical and theoretical applications.
Thus, the concepts of vector components and trigonometry empower us to not only calculate the magnitude but also understand the direction of motion, enhancing the analysis of physical situations.

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