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A meteoroid is traveling east through the atmosphere at \(18.3 \mathrm{km} / \mathrm{s}\) while descending at a rate of \(11.5 \mathrm{km} / \mathrm{s}\). What is its speed, in \(\mathrm{km} / \mathrm{s} ?\)

Short Answer

Expert verified
The meteoroid's speed is approximately 21.6 km/s.

Step by step solution

01

Understand the Components

The problem describes two components of the meteoroid's motion: one horizontal (eastward) at 18.3 km/s, and one vertical (downward) at 11.5 km/s. These are like the legs of a right triangle.
02

Apply the Pythagorean Theorem

To find the resultant speed, which acts like the hypotenuse of a right triangle, we use the Pythagorean theorem: \[ c = \sqrt{a^2 + b^2} \] where \(a\) and \(b\) are the components of speed.
03

Substitute the Values into the Formula

Substitute the given speeds into the formula: \[ c = \sqrt{(18.3)^2 + (11.5)^2} \]
04

Calculate the Squared Values

First, find the squares of each component: \[ (18.3)^2 = 334.89 \] and \[ (11.5)^2 = 132.25 \]
05

Add the Squared Values

Add these squared values together: \[ 334.89 + 132.25 = 467.14 \]
06

Take the Square Root

Finally, take the square root of the sum to find the resultant speed: \[ c = \sqrt{467.14} \approx 21.6 \]
07

Conclusion

The speed of the meteoroid is approximately 21.6 km/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Components
In physics, understanding how different aspects of motion interact is vital. When a meteoroid travels through the atmosphere, its speed can be thought of in multiple dimensions. Each dimension's speed is a component of the overall motion.
Think of these velocity components as puzzle pieces that come together to form a complete picture of the meteoroid's velocity.
  • Horizontal Component: In our scenario, the meteoroid is moving eastward at 18.3 km/s. This is its horizontal component of velocity.
  • Vertical Component: Simultaneously, it descends at a speed of 11.5 km/s, representing its vertical component.
By identifying these components, we set the stage for computing the meteoroid's total speed using mathematical principles like the Pythagorean theorem.
Resultant Speed
To find the meteoroid's overall speed, we need to unify its horizontal and vertical velocities into one. This gives us the resultant speed or the total speed at which it travels.

The trick lies within the Pythagorean theorem, which is a powerful tool in physics when dealing with right-angle scenarios. According to this theorem, the resultant speed can be visualized as the hypotenuse of a right triangle formed by the horizontal and vertical components. The formula is:\[ c = \sqrt{a^2 + b^2} \]where \(a\) and \(b\) are the horizontal and vertical components of velocity.
  • Substitute known values: For the meteoroid, substitute \(a = 18.3\) km/s and \(b = 11.5\) km/s into the formula.
  • Compute: Squaring these values and adding them gives \( (18.3)^2 = 334.89 \) and \( (11.5)^2 = 132.25 \). Their sum is 467.14.
  • Find the square root: Taking the square root of this sum results in a resultant speed of approximately 21.6 km/s.
Successfully calculating the resultant speed allows a comprehensive understanding of the meteoroid's velocity as it hurtles through the sky.
Right Triangle Applications in Physics
The connection between right triangles and physics might not seem obvious at first, but they are intrinsically linked, especially in scenarios involving vector motions like velocity.

When the velocity components create a right triangle, as with a meteoroid's motion, the Pythagorean theorem becomes an invaluable tool.
  • Defining right triangles with velocity: Each component forms a side of the triangle, and the resultant speed is the hypotenuse. This geometric relationship simplifies complex motion analysis by breaking it down into manageable parts.
  • Utilizing angles: Though this problem focuses solely on sides, knowing angles further enriches the analysis, often used in projectile motion assessments.
  • Real-world importance: Engineers and scientists use right triangles in physics to develop spacecraft, analyze flight paths, and ensure safe and efficient travel routes in various fields.
Understanding right triangle applications allows for greater comprehension of motion dynamics in various physical systems, making complex scenarios more accessible for students and professionals alike.

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