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As a tennis ball is struck, it departs from the racket horizontally with a speed of \(28.0 \mathrm{m} / \mathrm{s}\). The ball hits the court at a horizontal distance of \(19.6 \mathrm{m}\) from the racket. How far above the court is the tennis ball when it leaves the racket?

Short Answer

Expert verified
The tennis ball is 2.40 m above the court when it leaves the racket.

Step by step solution

01

Analyze the Given Data

We are given the horizontal speed of the tennis ball as it leaves the racket as 28.0 m/s, and the horizontal distance traveled by the ball until it hits the ground as 19.6 m. We need to find the vertical height from which the ball was launched.
02

Calculate the Time of Flight

Since the ball travels horizontally at a constant speed, we can find the time of flight using the formula \( t = \frac{d}{v} \), where \( d = 19.6 \) m is the distance traveled, and \( v = 28.0 \) m/s is the speed. Thus, \( t = \frac{19.6}{28.0} = 0.7 \) seconds.
03

Use the Vertical Motion Equation

In vertical motion, the ball is subject to gravity. We use the formula for distance \( h = \frac{1}{2}gt^2 \), where \( g = 9.8 \) m/s² is the acceleration due to gravity and \( t = 0.7 \) seconds is the time of flight. Substitute these values to find \( h \): \( h = \frac{1}{2} imes 9.8 imes (0.7)^2 = 2.401 \) m.
04

Finalize the Solution

The height \( h \) represents the vertical distance the ball falls due to gravity. Therefore, the tennis ball was struck at a height of approximately 2.40 meters above the court.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Distance in Projectile Motion
When we talk about the horizontal distance in projectile motion, we're generally referring to the path traveled by the object in a straight line parallel to the ground. In the case of the tennis ball in the original exercise, the horizontal distance covered is 19.6 meters. To understand how this distance is achieved, it's crucial to know that the ball maintains a constant horizontal speed as there is no horizontal acceleration (in ideal conditions ignoring air resistance).

The formula to calculate horizontal distance is simple: multiply the horizontal speed by the time of flight. This relationship is expressed in the equation:
  • Distance = Speed x Time

As time progresses, the object continues moving with the same speed, covering more and more ground until it reaches the target location. That’s why knowing either the distance or the speed can help you solve for the other variable, as seen in the exercise.
Understanding Vertical Motion
Vertical motion in projectile scenarios is influenced by gravity, which means the object simultaneously begins an accelerated motion downward as soon as it is launched. Unlike horizontal motion, vertical motion is not constant; instead, it is affected by the force of gravity, pulling the object towards the Earth.

The vertical displacement reached by the tennis ball, moving in the vertical direction, can be computed using the equation:
\[ h = \frac{1}{2} g t^2 \]
where,
  • \( h \) represents the height or vertical displacement,
  • \( g \) is the gravitational acceleration which is constant at 9.8 m/s²,
  • \( t \) is the time the object spends in the air.

In our exercise, the time of flight is 0.7 seconds, calculated using horizontal parameters, but then applied to determine how far the ball has fallen vertically. This rapid analysis shows how interlinked vertical and horizontal components are in projectile motion.
The Role of Acceleration Due to Gravity
Gravity is a constant force acting on all objects on Earth, and it's defined as 9.8 m/s². In projectile motion, gravity is the key driver for vertical movement.

The acceleration due to gravity essentially governs how fast an object accelerates towards the ground once it’s in motion. When objects are projected, they start with an initial vertical velocity of zero (particularly objects launched horizontally like the tennis ball). Gravity then increases their downward velocity as time passes.

It’s crucial to solve vertical velocity and displacement by incorporating gravity's influence using formulas like
  • Final velocity after time\(u + gt\)
  • Height formula given in vertical motion \[ h = \frac{1}{2} g t^2 \]

Understanding the significance of gravity helps in grasping why projectiles follow a parabolic path and why no matter the horizontal speed; gravity will always determine the vertical drop.

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Most popular questions from this chapter

A fire hose ejects a stream of water at an angle of \(35.0^{\circ}\) above the horizontal. The water leaves the nozzle with a speed of \(25.0 \mathrm{m} / \mathrm{s}\). Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

A meteoroid is traveling east through the atmosphere at \(18.3 \mathrm{km} / \mathrm{s}\) while descending at a rate of \(11.5 \mathrm{km} / \mathrm{s}\). What is its speed, in \(\mathrm{km} / \mathrm{s} ?\)

A skateboarder, starting from rest, rolls down a 12.0 -m ramp. When she arrives at the bottom of the ramp her speed is \(7.70 \mathrm{m} / \mathrm{s}\). (a) Determine the magnitude of her acceleration, assumed to be constant. (b) If the ramp is inclined at \(25.0^{\circ}\) with respect to the ground, what is the component of her acceleration that is parallel to the ground?

A baseball player hits a triple and ends up on third base. A baseball "diamond" is a square, each side of length \(27.4 \mathrm{m},\) with home plate and the three bases on the four corners. What is the magnitude of the player's displacement?

A skateboarder shoots off a ramp with a velocity of \(6.6 \mathrm{m} / \mathrm{s},\) directed at an angle of \(58^{\circ}\) above the horizontal. The end of the ramp is \(1.2 \mathrm{m}\) above the ground. Let the \(x\) axis be parallel to the ground, the \(+y\) direction be vertically upward, and take as the origin the point on the ground directly below the top of the ramp. (a) How high above the ground is the highest point that the skateboarder reaches? (b) When the skateboarder reaches the highest point, how far is this point horizontally from the end of the ramp?

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