/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 The crew of a rocket that is mov... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The crew of a rocket that is moving away from the earth launches an escape pod, which they measure to be \(45 \mathrm{m}\) long. The pod is launched toward the earth with a speed of \(0.55 c\) relative to the rocket. After the launch, the rocket's speed relative to the earth is \(0.75 c .\) What is the length of the escape pod as determined by an observer on earth?

Short Answer

Expert verified
The length of the pod as observed from Earth is approximately 17.64 m.

Step by step solution

01

Understand the Problem

We need to find the length of the escape pod as observed from Earth, considering relativistic effects. The pod's length is given as \(45\,\mathrm{m}\) in its proper frame, and we know the velocities involved: \(v_{rp} = 0.55c\) (pod relative to the rocket) and \(v_r = 0.75c\) (rocket relative to Earth).
02

Calculate Relative Velocity of Pod to Earth

To find the velocity of the pod relative to Earth \(v_{pe}\), we use the relativistic velocity addition formula: \[ v_{pe} = \frac{v_{r} + v_{rp}}{1 + \frac{v_{r} \cdot v_{rp}}{c^2}} \]Substituting, we calculate:\[ v_{pe} = \frac{0.75c + 0.55c}{1 + \frac{0.75 \cdot 0.55}{1}} = \frac{1.3c}{1.4125} \approx 0.92c \]
03

Apply Length Contraction Formula

With the relative velocity \( v_{pe} \approx 0.92c \), we use the relativistic length contraction formula:\[ L = L_0 \sqrt{1-\frac{v^2}{c^2}} \]where \(L_0 = 45\,\mathrm{m}\). Calculating,\[ L = 45 \sqrt{1-\frac{(0.92c)^2}{c^2}} = 45 \sqrt{1-0.8464} \approx 45 \sqrt{0.1536} \approx 45 \cdot 0.392 \approx 17.64 \mathrm{m} \]
04

Conclusion

The length of the escape pod as observed by an observer on Earth is approximately \(17.64\,\mathrm{m}\), taking into account the relativistic length contraction due to its high velocity towards Earth.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativistic Velocity Addition
In the realm of special relativity, velocities do not simply add up like ordinary numbers, especially when dealing with speeds close to the speed of light, denoted as \(c\). This surprising behavior is described by the relativistic velocity addition formula, which is essential when combining velocities of objects moving at significant fractions of light speed. If you have a rocket moving at a velocity \(v_r\) and a pod moving at velocity \(v_{rp}\) relative to the rocket, the velocity \(v_{pe}\) of the pod relative to Earth is given by:
  • \[ v_{pe} = \frac{v_{r} + v_{rp}}{1 + \frac{v_{r} \cdot v_{rp}}{c^2}} \]
This formula accounts for the fact that no matter how fast you go, you can never exceed the speed of light. Instead of straightforward addition, there's a correction factor \(1 + \frac{v_{r} \cdot v_{rp}}{c^2}\) that adjusts the sum based on how significant the speeds are compared to \(c\). For the given problem, this was used to find that the pod's velocity relative to Earth was approximately \(0.92c\). This conceptual tool helps in observing real phenomena like the above, ensuring that the speed of light remains the ultimate speed limit.
Proper Length
In physics, the concept of "proper length" is crucial for understanding why objects appear shorter when they are moving at high speeds relative to an observer. Proper length, \(L_0\), is the length of an object measured in its own rest frame, where it is not experiencing relative motion. For the escape pod, this proper length is given as \(45\,\text{m}\).According to Einstein's theory of relativity, as an object moves at a significant fraction of the speed of light, it undergoes length contraction when observed from a different inertial frame. This means observers measuring the length of the escape pod from Earth, where it is moving rapidly, will see a contracted length calculated using:
  • \[ L = L_0 \sqrt{1-\frac{v^2}{c^2}} \]
Here, \(v\) is the relative velocity, \(v_{pe}\), between the escape pod and the observer on Earth. Use this formula to find \(L\), the 'contracted' length observed. By substituting \(L_0 = 45 \text{m}\) and \(v = 0.92c\), the resultant length is approximately \(17.64\,\text{m}\), showcasing the dramatic effects of relativistic length contraction at high speeds.
Observer Frame of Reference
Understanding an "observer frame of reference" is fundamental when dealing with relativistic effects like velocity addition and length contraction. A frame of reference refers to the setting or viewpoint from which an observer measures and perceives various events and phenomena. In our example, the observer frame of reference shifts between:
  • The rocket crew's perspective, where the escape pod's proper length is measured at rest as \(45\,\text{m}\).
  • The Earth observer, who measures the pod's length while it speeds towards them at a high velocity.
Each observer will have different measurements for the same object because of relativistic effects - velocities and lengths change based on the observer’s relative motion. This is why, in relativity, understanding which frame you're calculating from is so important.When examining situations involving high-speed travel, it's crucial to specify exactly which frame—like the Earth or the moving rocket—you're referring to. This affects calculations and phenomena like time dilation and length contraction. These concepts remind us that both motion and measurement are relative, and they change our perception of even the most tangible aspects like size and velocity.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose the straight-line distance between New York and San Francisco is \(4.1 \times 10^{6} \mathrm{m}\) (neglecting the curvature of the earth). A UFO is flying between these two cities at a speed of \(0.70 \mathrm{c}\) relative to the earth. What do the voyagers aboard the UFO measure for this distance?

Suppose that you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by a clock on board the spacecraft, and then return home at the same speed. Upon your return, the people on earth will have advanced exactly one hundred years into the future. According to special relativity, how fast must you travel? Express your answer to five significant figures as a multiple of \(c-\) for example, \(0.95585 c\)

Spaceships of the future may be powered by ion-propulsion engines in which ions are ejected from the back of the ship to drive it forward. In one such engine the ions are to be ejected with a speed of \(0.80 \mathrm{c}\) relative to the spaceship. The spaceship is traveling away from the earth at a speed of \(0.70 c\) relative to the earth. What is the velocity of the ions relative to the earth? Assume that the direction in which the spaceship is traveling is the positive direction, and be sure to assign the correct plus or minus signs to the velocities.

Determine the ratio of the relativistic kinetic energy to the nonrelativistic kinetic energy \(\left(\frac{1}{2} m v^{2}\right)\) when a particle has a speed of (a) \(1.00 \times 10^{-3} c\) and \((b) 0.970 c.\)

What is the magnitude of the relativistic momentum of a proton with a relativistic total energy of \(2.7 \times 10^{-10} \mathrm{J} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.