/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Determine the ratio of the relat... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the ratio of the relativistic kinetic energy to the nonrelativistic kinetic energy \(\left(\frac{1}{2} m v^{2}\right)\) when a particle has a speed of (a) \(1.00 \times 10^{-3} c\) and \((b) 0.970 c.\)

Short Answer

Expert verified
The ratio is approximately 1 for \(1.00 \times 10^{-3}c\) and 6.62 for \(0.970c\).

Step by step solution

01

Understand the Problem

We need to calculate the ratio of relativistic kinetic energy (RKE) to non-relativistic kinetic energy (NKE) at two different speeds: \(1.00 \times 10^{-3}c\) and \(0.970c\), where \(c\) is the speed of light.
02

Determine Non-Relativistic Kinetic Energy (NKE)

The non-relativistic kinetic energy formula is given by \(K_{NR} = \frac{1}{2} mv^2\). This is straightforward to calculate for any speed \(v\) by plugging in the speed value in terms of \(c\).
03

Determine Relativistic Kinetic Energy (RKE)

The formula for relativistic kinetic energy is:\[K_{R} = (\gamma - 1) mc^2\]where \(\gamma\) is the Lorentz factor: \[\gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^2}}\]Calculate \(K_{R}\) for the given speeds.
04

Calculate Ratio for \(v = 1.00 \times 10^{-3}c\)

First, find \(\gamma\):\[\gamma = \frac{1}{\sqrt{1 - (1.00 \times 10^{-3})^2}} \approx 1.0000005\] Then, calculate RKE:\[K_{R} = (\gamma - 1) mc^2 \approx (1.0000005 - 1) mc^2 \approx 0.0000005 mc^2\] Calculate \(K_{NR}\):\[K_{NR} = \frac{1}{2} m (1.00 \times 10^{-3}c)^2 = 0.5 \times 10^{-6} mc^2\]The ratio is:\[\frac{K_{R}}{K_{NR}} = \frac{0.0000005 mc^2}{0.5 \times 10^{-6} mc^2} \approx 1\]
05

Calculate Ratio for \(v = 0.970c\)

Calculate \(\gamma\):\[\gamma = \frac{1}{\sqrt{1 - (0.970)^2}} \approx 4.114\]Then, calculate RKE:\[K_{R} = (\gamma - 1) mc^2 = (4.114-1) mc^2 = 3.114 mc^2\]Calculate \(K_{NR}\):\[K_{NR} = \frac{1}{2} m (0.970c)^2 = 0.5 \times 0.9409 mc^2 = 0.47045 mc^2\]The ratio is:\[\frac{K_{R}}{K_{NR}} = \frac{3.114 mc^2}{0.47045 mc^2} \approx 6.62\]
06

Conclusion

The ratio of RKE to NKE is approximately 1 for \(1.00 \times 10^{-3}c\) and 6.62 for \(0.970c\). This shows the significant effect of relativistic speeds on kinetic energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Non-Relativistic Kinetic Energy
To understand kinetic energy in the non-relativistic context, think of it as the energy an object possesses due to its motion at speeds much slower than the speed of light. This type of kinetic energy is visualized using the classic formula:
  • \( K_{NR} = \frac{1}{2}mv^2 \)
Here, \( m \) is the mass of the object, and \( v \) is its velocity. This equation assumes that the object's speed is much less than that of light, so relativistic effects don’t interfere. This simplified understanding serves well in everyday situations, such as calculating the energy of a moving car. However, as objects approach the speed of light, non-relativistic calculations become inaccurate, leading us to consider relativistic kinetic energy.
Lorentz Factor
One key aspect of relativity is the Lorentz factor, which comes into play when dealing with speeds near the speed of light. It is defined as:
  • \[ \gamma = \frac{1}{\sqrt{1 - \left( \frac{v}{c} \right)^2 }} \]
In this equation, \( v \) is the velocity of the object and \( c \) represents the speed of light. The Lorentz factor increases rapidly as \( v \) approaches \( c \), reflecting the time dilation, length contraction, and mass increase phenomena predicted in Einstein's theory of relativity. Understanding the Lorentz factor helps in determining how relativistic effects influence kinetic energy as objects move at significant fractions of the speed of light. For instance, speeds like \( 0.970c \) significantly affect energy calculations due to a large Lorentz factor.
Speed of Light
The speed of light, denoted as \( c \), is a fundamental constant of nature. Its value is approximately \( 3 \times 10^8 \) meters per second. One fascinating truth about the speed of light is that it is the ultimate speed limit in the universe - nothing can travel faster than light. This has profound implications for physics. When analyzing problems involving high velocities, the speed of light sets the scale upon which relativistic effects become significant. As an object's speed approaches that of light, calculations using classical mechanics become less accurate, making relativistic mechanics essential. For example, when assessing kinetic energy at \( 0.970c \), we must consider relativistic formulas because non-relativistic formulas provide only an approximate and less accurate picture.
Physics Problem Solving
Solving physics problems, especially those involving relativistic concepts, requires a structured approach. Here is a method you can follow:
  • Understand the problem: Clearly identify what you need to find. For example, distinguishing between the types of kinetic energy needed in a problem.
  • Choose appropriate formulas: Decide on using either non-relativistic or relativistic kinetic energy formulas based on the velocities involved.
  • Consider relevant constants: Know important constants, like the speed of light, which influence calculations.
  • Calculate methodically: Perform calculations step-by-step. For instance, first compute the Lorentz factor before substituting into energy equations.
By following these steps, students can more effectively approach and solve physics questions, providing a clearer understanding and accurate results.

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Most popular questions from this chapter

Two spaceships A and B are exploring a new planet. Relative to this planet, spaceship A has a speed of \(0.60 c,\) and spaceship \(B\) has a speed of \(0.80 c .\) What is the ratio \(D_{\Lambda} / D_{B}\) of the values for the planet's diameter that each spaceship measures in a direction that is parallel to its motion?

Suppose that you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by a clock on board the spacecraft, and then return home at the same speed. Upon your return, the people on earth will have advanced exactly one hundred years into the future. According to special relativity, how fast must you travel? Express your answer to five significant figures as a multiple of \(c-\) for example, \(0.95585 c\)

ssm A particle known as a pion lives for a short time before breaking apart into other particles. Suppose that a pion is moving at a speed of \(0.990 c\), and an observer who is stationary in a laboratory measures the pion's lifetime to be \(3.5 \times 10^{-8}\) s. (a) What is the lifetime according to a hypothetical person who is riding along with the pion? (b) According to this hypothetical person, how far does the laboratory move before the pion breaks apart?

ssM A spacecraft approaching the earth launches an exploration vehicle. After the launch, an observer on earth sees the spacecraft approaching at a speed of \(0.50 \mathrm{c}\) and the exploration vehicle approaching at a speed of \(0.70 \mathrm{c}\). What is the speed of the exploration vehicle relative to the spaceship?

Twins who are 19.0 years of age leave the earth and travel to a distant planet 12.0 light-years away. Assume that the planet and earth are at rest with respect to each other. The twins depart at the same time on different spaceships. One twin travels at a speed of \(0.900 c,\) and the other twin travels at \(0.500 c .\) (a) According to the theory of special relativity, what is the difference between their ages when they meet again at the earliest possible time? (b) Which twin is older?

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